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Choosing Science Judging on the basis of experience, a school counselor claims that \(60 \%\) of Australian students choose the science stream for higher studies. Suppose you surveyed 25 randomly selected students, and 18 of them reported having chosen the science stream. The null hypothesis is that the overall proportion of the students who have made such a choice is \(60 \%\). What value of the test statistic should you report?

Short Answer

Expert verified
The test statistic value to be reported is approximately 1.22.

Step by step solution

01

Identify the sample proportion

Calculate the sample proportion (p̂), which is the number of students who chose the science stream divided by the total number of students surveyed. So, \(\frac{18}{25} = 0.72\).
02

Identify the hypothesized proportion

The null hypothesis states that the proportion of students who choose the science stream is 60%, so the hypothesized proportion (p) is 0.60.
03

Calculate the standard error

The standard error (SE) is the square root of \(p(1-p) / n\). Substituting \(p = 0.60\) and \(n = 25\) gives \(SE = \sqrt{0.60 \cdot 0.40 / 25 } = 0.09798\).
04

Calculate the test statistic

The test statistic is the difference between the sample proportion and the hypothesized proportion, divided by the standard error. So, \( statistic = \frac{p̂ - p}{SE} = \frac{0.72 - 0.60}{0.09798} = 1.22474\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Proportion
The sample proportion is a fundamental concept used within statistical hypothesis testing. It helps us understand how well a sample matches a hypothesized population characteristic.
In the case of the school counselor's claim that 60% of students choose the science route, our sample proportion (denoted by \(\hat{p}\)) indicates what fraction of our surveyed group fits that narrative. Here, we have surveyed 25 students and found that 18 chose science.
To find the sample proportion, simply divide the number of students who chose the science stream by the total number of students surveyed. So in our equation, it becomes \(\frac{18}{25} = 0.72\). This value of 0.72 suggests that 72% of the surveyed students opted for science, differing from the counselor's claim.
Test Statistic
The test statistic is a tool that tells us how far off our sample is from the null hypothesis.
Specifically, in hypothesis testing, it helps us determine if the difference between our sample's proportion and the null hypothesis can be attributed to random chance or if it is significant.
In our scenario, we're testing if our finding from the sample significantly deviates from the counselor's claim of 60%. To compute the test statistic, we subtract the hypothesized population proportion (0.60) from our sample proportion \(\hat{p} = 0.72\), and then divide by the standard error.
\[statistic = \frac{0.72 - 0.60}{0.09798} = 1.22474\]
If the test statistic is large in magnitude, it suggests a significant difference, leading us to question the null hypothesis.
Standard Error
Standard error (SE) serves as an estimate of the variability, or standard deviation, of a sample proportion.
It offers a way to measure how much our sample proportion could vary from the true population proportion, assuming the null hypothesis is true. The lower the SE, the less variability in our sampling, making our results more reliable.
For this case, SE is calculated with the formula:
\[ SE = \sqrt{p(1-p) / n} \]
Substituting \(p = 0.60\) and \(n = 25\), we get:
\[ SE = \sqrt{0.60 \times 0.40 / 25 } \approx 0.09798 \]
This value suggests that even though our sample proportion is 0.72, the true proportion could reasonably be expected to vary by about ±0.09798 from the hypothesized level of 0.60 due to sample fluctuation.

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Most popular questions from this chapter

A statistician studying ESP tests 500 students. Each student is asked to predict the outcome of a large number of dice rolls. For each student, a hypothesis test using a \(10 \%\) significance level is performed. If the p-value for the student is less than or equal to \(0.10\), the researcher concludes that the student has ESP. Out of 500 students who do not have ESP, about how many could you expect the statistician to declare do have ESP?

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