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91Ó°ÊÓ

Use a table or technology to answer each question. Include an appropriately labeled sketch of the Normal curve for each part. Shade the appropriate region. a. Find the area to the left of a \(z\) -score of \(-0.50\). h. Find the area to the right of a \(z\) -score of \(-0.50\).

Short Answer

Expert verified
The area to the left of a z-score of -0.50 is approximately 0.3085 and the area to the right is approximately 0.6915.

Step by step solution

01

Use of z-table for z-score of -0.50

A z-table is used to find the probability that a statistic is observed below, above, or between values. In this case, we look up the z-score of -0.50 in the z-table to find the area to the left of it. The z-table shows this to be approximately 0.3085.
02

Calculation of area to the right

To calculate the area to the right of the z-score, one needs to subtract the area to the left from 1 (since the total area under the curve is equal to 1). Thus, the calculation becomes \(1 - 0.3085 = 0.6915\).
03

Sketch and label the Normal curve

In this part, we are to draw and label a standard normal distribution curve. The z-score of -0.50 is indicated on the horizontal axis. Two areas are shaded: the area to the left of -0.50 (representing the area or probability of approximately 0.3085) indicated by the left shaded region, and the area to the right of -0.50 (representing the probability of approximately 0.6915) shown by the right region shaded.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

z-score
A z-score is a numerical measurement that describes a value's relationship to the mean of a group of values. It is expressed as a number of standard deviations from the mean. For instance, a z-score of -0.50 means the value is 0.5 standard deviations below the mean. You can interpret z-scores to understand how far away something is from the average.

To calculate a z-score, you use the formula:
\[ z = \frac{X - \mu}{\sigma} \]
where:
  • \(X\) is the value from the dataset.
  • \(\mu\) is the mean of the dataset.
  • \(\sigma\) is the standard deviation of the dataset.

Understanding z-scores helps when working with data that fit a normal distribution, aiding in comparing scores from different datasets.
probability
Probability is the measure of the likelihood of an event occurring, expressed as a number between 0 and 1. In the context of the normal distribution, we're often interested in the probability of a statistic falling within a particular range of values.

For instance, in our exercise, the probability that a z-score is to the left of -0.50 is 0.3085. This means there's a 30.85% chance that a value falls below this z-score. Alternatively, the area to the right of -0.50 has a probability of 0.6915 (or 69.15%), highlighting how probabilities help quantify expectations in statistical analyses.

The probabilities obtained from a normal curve are always underpinned by the idea that the total area under the curve equals 1, encapsulating all potential outcomes.
standard normal distribution
The standard normal distribution is a special type of normal distribution with a mean of 0 and a standard deviation of 1. It is symmetrical and bell-shaped, like any normal distribution, but it adds the advantage of using standard deviations as a natural scale.

Such a curve mathematically describes how values are distributed, with most values concentrated near the mean. When we talk about z-scores, they're measured with respect to this distribution, converting raw scores into a standard form.
By understanding the standard normal distribution, you can utilize z-scores to easily compare different data points from diverse datasets or populations.
z-table
A z-table, also known as a standard normal distribution table, is a reference table that provides the probabilities associated with different z-scores in a standard normal distribution. It's an essential tool for statistics because it quickly lets you find the probability of a statistic falling below, above, or between specific z-score values.

For example, finding the area to the left of a z-score involves looking it up in the z-table. The table entry for -0.50 shows 0.3085, meaning that there's a 30.85% chance a value is less than this z-score.

Using a z-table effectively allows for quick probability calculations and decisions in various statistical analyses, making complex evaluations straightforward.

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Most popular questions from this chapter

According to the College Board, the mean quantitative SAT score for male college-bound high school seniors in one year was \(530 .\) SAT scores are approximately Normally distributed with a population standard deviation of \(100 .\) What is the SAT score at the 96 th percentile for male college-bound seniors?

The Normal model \(N(500,100)\) describes the distribution of critical reading SAT scores in the United States. Which of the following questions asks for a probability and which asks for a measurement (and is thus an inverse Normal question)? a. What reading SAT score is at the 65 th percentile? b. What is the probability that a randomly selected person will score 550 or more?

A study of U.S. births published on the website Medscape from WebMD reported that the average birth length of babies was \(20.5\) inches and the standard deviation was about \(0.90\) inch. Assume the distribution is approximately Normal. Find the percentage of babies with birth lengths of 22 inches or less.

A 2013 Gallup poll indicated that about \(80 \%\) of U.S. households had access to a high-speed Internet connection. Assume this rate has not changed. a. Suppose 100 houscholds were randomly selected from the United States. How many of the households would you expect to have access to a high-speed Internet connection? b. If 10 households are selected randomly, what is the probability that exactly 6 have high-speed access? c. If 10 houscholds are selected randomly, what is the probability that 6 or fewer have high-speed access?

For each situation, identify the sample size \(n\), the probability of success \(p\), and the number of successes \(x .\) When asked for the probability, state the answer in the form \(b(n, p, x) .\) There is no need to give the numerical value of the probability. Assume the conditions for a binomial experiment are satisfied. a. According to the Federal Highway Research Institute in Germany, 2 out of 3 persons in an accident get killed. In a random sample of 27 persons meeting with an accident, what is the probability that exactly 12 persons would have died? b. Twenty-five percent of the persons killed in accidents are pedestrians. If we randomly select 27 persons who have died in an accident, what is the probability that 12 persons are pedestrians?

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