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For each situation, identify the sample size \(n\), the probability of success \(p\), and the number of successes \(x .\) When asked for the probability, state the answer in the form \(b(n, p, x) .\) There is no need to give the numerical value of the probability. Assume the conditions for a binomial experiment are satisfied. a. According to the Federal Highway Research Institute in Germany, 2 out of 3 persons in an accident get killed. In a random sample of 27 persons meeting with an accident, what is the probability that exactly 12 persons would have died? b. Twenty-five percent of the persons killed in accidents are pedestrians. If we randomly select 27 persons who have died in an accident, what is the probability that 12 persons are pedestrians?

Short Answer

Expert verified
The answer for case a is \(b(27, 2/3, 12)\) and for case b is \(b(27, 0.25, 12)\).

Step by step solution

01

Identifying parameters for case a.

For case a, the sample size \(n\) is 27 (persons involved in an accident), the probability of success \(p\) is 2/3 (probability that a person dies in an accident), and the number of successes \(x\) we are interested in is 12 (persons who have died in an accident).
02

Stating the answer for case a.

Substitute the identified parameters into the binomial distribution function. The answer can be given in the format \(b(n, p, x)\). Filling in the values, we find that the probability is \(b(27, 2/3, 12)\).
03

Identifying parameters for case b.

For case b, the sample size \(n\) is again 27 (persons who have died in an accident), the probability of success \(p\) is 0.25 (probability that a person who died in an accident is a pedestrian), and the number of successes \(x\) we're interested in is 12 (people who were pedestrians).
04

Stating the answer for case b.

Substitute the identified parameters into the binomial distribution function. The answer can be given in the format \(b(n, p, x)\). Filling in the values, we find that the probability is \(b(27, 0.25, 12)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Size
When dealing with binomial distributions, the sample size, denoted as n, is critical because it represents the number of trials or observations involved. In the context of our exercise, the sample size refers to the number of persons in each situation: for both scenarios a and b, the sample size is 27. This figure is significant as it sets the stage for the total number of events where the outcome of interest (success) could occur.

Understanding the sample size is crucial for calculating probabilities in binomial experiments, as it directly affects the spread and shape of the distribution. With a larger sample size, for example, we often see a more accurate representation of the underlying probability, and the distribution starts to resemble a normal distribution thanks to the Central Limit Theory. Conversely, a smaller sample size may lead to greater variability and less certainty in outcomes.
Probability of Success
In binomial distribution problems, the probability of success, p, is the likelihood that any individual trial results in the desired outcome. It's a fundamental component because it defines what we're evaluating - the chance of a specific event happening.

For our first scenario (a), the probability of success is the chance of a person getting killed in an accident, which is given as 2/3. In the second scenario (b), the probability of success is the proportion of deceased that are pedestrians, set at 0.25 (or 25%). This probability is not to be confused with the frequency of occurrences; it is a fixed value that characterizes the event we are interested in across all trials, regardless of the sample size.

The probability of success remains constant throughout each trial in a binomial experiment, which is one of the defining characteristics of such experiments. This constancy allows us to make predictions about the distribution of outcomes using the binomial formula. If this probability changes during the trials, we'd be looking at a different kind of distribution entirely.
Number of Successes
The number of successes, x, in a binomial distribution is the count of the specific outcomes we're interested in across all the trials. It's the target number of occurrences for our event of interest. In our exercise cases, for both scenario a and b, we are looking for the probability that exactly 12 out of 27 people meet the success condition (died in an accident for a, and are pedestrians for b).

The number of successes is essential when applying the binomial formula, as it helps determine the probability of finding exactly x successes in n trials given a constant probability p. It's a discrete value, meaning it can take only certain numbers (whole numbers from 0 to n) rather than any value within a range.

Identifying the correct number of successes is crucial in interpreting binomial distribution results. Unlike the probability of success, which is a measure of likelihood, the number of successes is an actual count of how many times the event occurred as desired. This distinction helps us utilize the binomial probability formula effectively to obtain meaningful statistical insights into the likelihood of various outcomes.

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Most popular questions from this chapter

According to GMAC Insurance. \(20 \%\) of drivers aged \(60-65\) fail the written drivers' test. This is the lowest failure rate of any age group. (Source: http://www.gmacinsurance.com/SafeDriving/PressRelease.asp) If 200 people aged \(60-65\) independently take the exam, how many would you expect to pass? Give or take how many?

Suppose there is a club for tall people that requires that men be at or above the 98th percentile in height. Assume that men's heights are distributed as \(N(69,3)\). Find what men's height is the minimum required for joining the club, rounding to the nearest inch. Draw a well-labeled sketch to support your answer.

A survey shows that in one year, the average number of bilingual doctors in a hospital was \(42 .\) Assume that the standard deviation is 12 and the number of bilingual doctors in a hospital is normally distributed. Include an appropriately labeled and shaded Normal curve for each part. a. What percentage of hospitals have between 40 and 45 bilingual doctors? b. What percentage of hospitals have between 45 and 50 bilingual doctors?

A study of U.S. births published on the website Medscape from WebMD reported that the average birth length of babies was \(20.5\) inches and the standard deviation was about \(0.90\) inch. Assume the distribution is approximately Normal. Find the percentage of babies who have lengths of 19 inches or less at birth.

Critical reading SAT scores are distributed as \(N(500,100)\) a. Find the SAT score at the 75 th percentile. b. Find the SAT score at the 25 th percentile. c. Find the interquartile range for SAT scores. d. Is the interquartile range larger or smaller than the standard deviation? Explain.

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