/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 19 The average amount of precipitat... [FREE SOLUTION] | 91Ó°ÊÓ

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The average amount of precipitation in Dallas, Texas, during the month of April is 3.5 inches (The World Almanac, 2000 ). Assume that a normal distribution applies and that the standard deviation is .8 inches. a. What percentage of the time does the amount of rainfall in April exceed 5 inches? b. What percentage of the time is the amount of rainfall in April less than 3 inches? c. \(\quad\) A month is classified as extremely wet if the amount of rainfall is in the upper \(10 \%\) for that month. How much precipitation must fall in April for it to be classified as extremely wet?

Short Answer

Expert verified
a) 3.07%, b) 26.59%, c) 4.524 inches for extremely wet classification.

Step by step solution

01

Define Variables

Identify the key variables from the problem. The mean \( \mu \) is the average rainfall, given as 3.5 inches, and the standard deviation \( \sigma \) is 0.8 inches. We will use these to find probabilities and thresholds related to the normal distribution.
02

Convert to Standard Normal Distribution (Part a)

To find the probability that rainfall exceeds 5 inches, convert the value to a z-score using the formula \( z = \frac{X - \mu}{\sigma} \). Substitute \( X = 5 \), \( \mu = 3.5 \), and \( \sigma = 0.8 \) to compute \( z = \frac{5 - 3.5}{0.8} = 1.875 \).
03

Calculate Probability (Part a)

Use the standard normal distribution table to find the probability associated with the z-score from Step 2. The table provides the probability to the left of the z-score. For \( z = 1.875 \), this is approximately 0.9693. Therefore, the probability of exceeding 5 inches is \( 1 - 0.9693 = 0.0307 \) or 3.07%.
04

Convert to Standard Normal Distribution (Part b)

For rainfall less than 3 inches, calculate the corresponding z-score with \( z = \frac{3 - 3.5}{0.8} = -0.625 \).
05

Calculate Probability (Part b)

Look up the z-score of -0.625 in the standard normal distribution table to find the probability. The probability associated with \( z = -0.625 \) is approximately 0.2659 or 26.59%.
06

Find Z-score for Upper 10% (Part c)

Determine the z-score that corresponds to the top 10% of the distribution. The z-score for the 90th percentile is approximately 1.28.
07

Calculate Precipitation Threshold for Extreme Wetness

Using the z-score from Step 6, calculate the corresponding precipitation level with \( X = \mu + z \times \sigma \). Substituting \( \mu = 3.5 \), \( z = 1.28 \), and \( \sigma = 0.8 \), we get \( X = 3.5 + 1.28 \times 0.8 = 4.524 \) inches.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score
A z-score is a useful concept in statistics primarily because it tells us how far a particular data point is from the mean in terms of the standard deviation. Think of it as a way to standardize scores on a common scale. To calculate a z-score, use the formula:
\[ z = \frac{X - \mu}{\sigma} \]
Where:
  • \(X\) is the data point in question, in this case, the inches of rainfall.
  • \(\mu\) represents the mean, or average, rainfall.
  • \(\sigma\) is the standard deviation of the dataset.
The z-score helps us understand the probability related to a data point. For instance, knowing the z-score allows you to use a table known as the standard normal distribution table to see how common or rare that data point is compared to the dataset overall.
It converts a value to a score that can be quickly interpreted, helping us to see if 5 inches of rain (or another amount) is a common occurrence or an outlier.
Probability Calculation
Calculating probability in a normal distribution involves determining the likelihood of different outcomes. Once you have the z-score, you can use the standard normal distribution table to find probabilities. These tables show the probability of a random variable falling to the left of a given z-score.
Here’s how you can find the probability related to a certain amount of rainfall:
  • First, calculate the z-score for the rainfall you're interested in (for example, whether it will exceed 5 inches).
  • Then, look up that z-score in the standard normal distribution table to find the probability up to that point.
  • For probabilities that need to show more than a certain z-score, subtract the table value from 1.
For example, the table tells us that a z-score of 1.875 corresponds to a probability of 0.9693. This means that 96.93% of the time, the rainfall is less than 5 inches. To find the probability that it rains more than 5 inches, subtract this value from 1.
Standard Deviation
The standard deviation is a key concept in understanding the spread or variability of a dataset. In a normal distribution, it helps determine how much variation exists from the average (mean).
Here's what you need to know about standard deviation:
  • It's denoted by \(\sigma\) and calculated as the square root of the variance.
  • The larger the standard deviation, the more spread out the data points are from the mean.
  • In the context of this problem, it tells us how variable the precipitation is over several Aprils.
A small standard deviation suggests that the data points are close to the mean, while a large standard deviation indicates that they are spread over a wider range. This intrinsic property is what allows the normal distribution to be defined efficiently.
For instance, if the standard deviation is 0.8 inches, it means most April rainfalls are within 0.8 inches above or below the average of 3.5 inches.

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Most popular questions from this chapter

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