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The probability distribution for the random variable \(x\) follows. $$\begin{array}{cc} \boldsymbol{x} & \boldsymbol{f}(\boldsymbol{x}) \\ 20 & .20 \\ 25 & .15 \\ 30 & .25 \\ 35 & .40 \end{array}$$ a. Is this probability distribution valid? Explain. b. What is the probability that \(x=30 ?\) c. What is the probability that \(x\) is less than or equal to \(25 ?\) d. What is the probability that \(x\) is greater than \(30 ?\)

Short Answer

Expert verified
a. Yes, it is valid. b. 0.25. c. 0.35. d. 0.40.

Step by step solution

01

Verify Validity of Distribution

To determine if the distribution is valid, we need to ensure that the sum of all probabilities equals 1. Let's add the probabilities together: \(0.20 + 0.15 + 0.25 + 0.40 = 1.00\). Since the sum is 1, the distribution is valid.
02

Find Probability for Specific x

The probability that \(x = 30\) is given directly as \(f(30) = 0.25\) from the table.
03

Calculate Cumulative Probability for x ≤ 25

We need to find the sum of the probabilities for \(x = 20\) and \(x = 25\). So, \(f(20) + f(25) = 0.20 + 0.15 = 0.35\). Thus, the probability that \(x\) is less than or equal to 25 is 0.35.
04

Calculate Probability for x > 30

To find the probability that \(x\) is greater than 30, we add the probabilities for values greater than 30, which is only \(x = 35\). So, \(f(35) = 0.40\). Therefore, the probability that \(x > 30\) is 0.40.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Random Variables
A random variable is a fundamental concept in statistics and probability theory. Random variables are used to quantify outcomes of random phenomena. In this context, the random variable is represented as \(x\) and it can take specific values like 20, 25, 30, or 35, as shown in the probability distribution table.
This distribution includes a rule that assigns a probability to each possible value of \(x\). Think of a random variable as a function that pairs each outcome of a probabilistic event with a number. In our example, the random variable \(x\) reflects different possible outcomes, each happening with a specific likelihood. These likelihoods are reflected in the probabilities listed next to each value in the table.
  • Random variables are typically classified into two types: discrete and continuous. Discrete random variables, like \(x\), take on distinct, separate values.
  • Continuous random variables can take an infinite number of possible values within a given range.
  • In this case, \(x\) represents a discrete random variable because it can only assume a limited set of individual values.
Understanding the type of random variable involved helps to apply the correct statistical methods for analysis.
Delving Into Probability Theory
Probability theory is the branch of mathematics that deals with the analysis of random events. It provides the foundation for the study of statistics, helping us to make sense of the randomness and uncertainty in various contexts, including this exercise.
Probability theory assigns a number to an event, which can range from 0 (impossible event) to 1 (certain event). The probability of a random event occurs when determining how likely it is for that event to happen. With the given distribution, the probability of each \(x\) value is listed as \(f(x)\).
  • One of the main principles of probability theory is that the total probability of all possible outcomes must always sum to 1. In our problem, we can see this when summing all the probabilities: \(0.20 + 0.15 + 0.25 + 0.40 = 1.00\).
  • This rule ensures the integrity of the probability distribution, confirming that it is valid.
  • Each outcome in a sufficiently complex probability scenario can be tackled with tools provided by probability theory, such as probability distributions, outcomes, events, and random variables.
Probability theory is crucial for making informed conclusions based on data and predicting future outcomes based on known probabilities.
Exploring Cumulative Probability
Cumulative probability is an essential concept in statistics. It helps us understand the likelihood of a random variable being less than or equal to a certain value. It represents the probability that a random variable takes on a value within a certain domain, including a complete range of possible values leading up to that point.
In our exercise, the cumulative probability of \(x\) being less than or equal to 25 is determined by adding the probabilities of \(x\) being 20 and 25:
\[ f(20) + f(25) = 0.20 + 0.15 = 0.35 \]
This gives us a cumulative probability of 0.35 for \(x\) being less than or equal to 25. Understanding cumulative probability allows better insights into data trends and patterns.
  • Cumulative distribution functions, CDFs, provide a way to describe the probability that a random variable is less than or equal to a particular value.
  • The CDF is a useful tool to convert probability mass functions (PMFs) or density functions (in continuous cases) into knowledge about probabilities.
  • In discrete scenarios, like ours, calculating cumulative probability amounts to summing the probabilities of the discrete events below a certain threshold.
With these insights, students can tackle problems involving cumulative probabilities with more confidence and clarity.

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Most popular questions from this chapter

Consider a binomial experiment with \(n=20\) and \(p=.70\). a. Compute \(f(12)\). b Compute \(f(16)\). c.Compute \(P(x \geq 16)\). d. Compute \(P(x \leq 15)\). e. Compute \(E(x)\). f. Compute \(\operatorname{Var}(x)\) and \(\sigma\) .

A university found that \(20 \%\) of its students withdraw without completing the introductory statistics course. Assume that 20 students registered for the course. a. Compute the probability that two or fewer will withdraw. b. Compute the probability that exactly four will withdraw. c. Compute the probability that more than three will withdraw. d. Compute the expected number of withdrawals.

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The following table provides a probability distribution for the random variable \(x\). $$\begin{array}{cc} x & f(x) \\ 3 & .25 \\ 6 & .50 \\ 9 & .25 \end{array}$$ a. \(\quad\) Compute \(E(x),\) the expected value of \(x\). b. Compute \(\sigma^{2},\) the variance of \(x\). c. Compute \(\sigma,\) the standard deviation of \(x\) .

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