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According to the 2003 Annual Consumer Spending Survey, the average monthly Bank of America Visa credit card charge was \(\$ 1838\) (U.S. Airways Attaché Magazine, December 2003 ). A sample of monthly credit card charges provides the following data. \\[\begin{array}{llrrr}236 & 1710 & 1351 & 825 & 7450 \\\316 & 4135 & 1333 & 1584 & 387 \\ 991 & 3396 & 170 & 1428 & 1688\end{array}\\] a. Compute the mean and median. b. Compute the first and third quartiles. c. \(\quad\) Compute the range and interquartile range. d. Compute the variance and standard deviation. e. The skewness measure for these data is \(2.12 .\) Comment on the shape of this distribution. Is it the shape you would expect? Why or why not? f. Do the data contain outliers?

Short Answer

Expert verified
Mean: 1708.33, Median: 1351. Outliers: 7450, 4135. Skewed right.

Step by step solution

01

Organize the Data

Let's list the data in ascending order to make calculations easier: \(\{170, 236, 316, 387, 825, 991, 1333, 1351, 1428, 1584, 1688, 1710, 3396, 4135, 7450\}\).
02

Compute the Mean

The mean is the sum of all data points divided by the number of data points. Calculate the sum and divide by 15 (the number of data points): \[\text{Mean} = \frac{170 + 236 + 316 + 387 + 825 + 991 + 1333 + 1351 + 1428 + 1584 + 1688 + 1710 + 3396 + 4135 + 7450}{15} = 1708.33\].
03

Compute the Median

To find the median, we need the middle value in the ordered dataset (since there are 15 numbers, this will be the 8th value):\[\text{Median} = 1351\].
04

Compute the First and Third Quartiles

The first quartile \(Q_1\) is the median of the first half of the data (excluding the median if the number of observations is odd). For 15 data points, this is the 4th value:\[Q_1 = 387\].The third quartile \(Q_3\) is the median of the second half of the data, the 12th value:\[Q_3 = 1710\].
05

Compute the Range and Interquartile Range

The range is the difference between the maximum and minimum values:\[\text{Range} = 7450 - 170 = 7280\].The interquartile range (IQR) is \(Q_3 - Q_1\):\[\text{IQR} = 1710 - 387 = 1323\].
06

Compute the Variance and Standard Deviation

First, compute the variance by finding the average of the squared differences from the mean:\[s^2 = \frac{\sum{(x_i - \bar{x})^2}}{n-1}\], where \(\bar{x} = 1708.33\). Calculate each squared difference, sum them up, then divide by 14 (since \(n = 15\)):\[s^2 \approx 3663440.57\].The standard deviation is the square root of the variance:\[s \approx 1913.46\].
07

Comment on Skewness

A skewness of \(2.12\) indicates a positive or right-skewed distribution, meaning there is a long tail on the right. This aligns with the presence of high-value data points (such as 7450), which skew the mean upwards.
08

Check for Outliers

Outliers can be identified using the IQR. Any data point below \(Q_1 - 1.5 \times \text{IQR}\) or above \(Q_3 + 1.5 \times \text{IQR}\) is considered an outlier:Lower bound: \(387 - 1.5 \times 1323 = -1597.5\) (none below this as data is positive) Upper bound: \(1710 + 1.5 \times 1323 = 3694.5\).7450 and 4135 are above the upper bound, marking them as outliers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean and Median
The mean is a measure that is commonly referred to as the average. It is calculated by adding all the values in a dataset and then dividing by the number of values. In the example given, the mean was computed as approximately 1708.33. This can be a helpful indicator of the central value in a dataset, especially when the data is symmetrically distributed.

On the other hand, the median is the middle value when the data is arranged in ascending order. Unlike the mean, the median is not affected by extremely high or low values, making it a more robust measure of center for skewed distributions. Here, the median value was 1351, which indicates that half the data points are below this value and half are above. Comparing the mean and median can provide insights into the nature of the data's distribution.
Quartiles
Quartiles are values that divide a dataset into four equal parts, each containing a quarter of the data points. These are helpful in understanding the spread and distribution of the data.
  • The first quartile ( Q_1 er) is the median of the lower half of the data. It is found to be 387 in this case.
  • The third quartile ( Q_3 a) is the median of the upper half, which is 1710 here.
Quartiles are useful for identifying the range of the central half of your data and are particularly helpful in constructing box plots for data visualization.
Variance and Standard Deviation
Variance and standard deviation are statistical measures of how spread out the numbers in a dataset are. Variance, denoted by (s^2) , is the average of the squared differences from the mean. A larger variance indicates more spread in the data.

In this dataset, the variance was calculated to be approximately 3663440.57. The standard deviation is the square root of the variance and gives a measure of spread that is in the same units as the data, making it easier to interpret. Here, the standard deviation was computed as around 1913.46. A high standard deviation points towards a wide variability in the data values.
Skewness
Skewness helps to understand the asymmetry of the data distribution. A skewness above 1 or below -1 is considered notably skewed.
This dataset has a skewness value of 2.12, indicating a positive skew, or right-skewed distribution. This means that there are relatively high-value outliers pulling the mean to the right. A positively skewed dataset often suggests that data points are spread more to the side of higher values, with most of the data clustered towards the lower end. The presence of very high credit card charges in the dataset causes this skewness.
Interquartile Range
The interquartile range (IQR) measures the middle 50% spread. It's the difference between the third quartile ( Q_3 a) and the first quartile ( Q_1 er). In this example, the IQR is calculated as 1323, which is the difference between 1710 and 387 .

IQR is a useful measure of variability. Since it relies only on the middle spread, it is not affected by outliers or extreme values, unlike the full range of a dataset. This makes it especially helpful in identifying the typical spread of a dataset when it's skewed.
Outliers
Outliers are data points that are significantly different from the rest of the dataset. They can drastically affect the results of statistical calculations. Identifying outliers can help refine data analysis and ensure more accurate conclusions.

In this example, any data point higher than 3694.5 is considered an outlier. The values 7450 and 4135 exceed this threshold, marking them as outliers. Outliers can skew data results, as seen with the high skewness in this dataset. It's essential to assess whether these outliers represent errors or rare events, or if they are valid data points that need to be accounted for in the analysis.

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Most popular questions from this chapter

Consider a sample with a mean of 30 and a standard deviation of \(5 .\) Use Chebyshev's theorem to determine the percentage of the data within each of the following ranges. a. 20 to 40 b. 15 to 45 c. 22 to 38 d. 18 to 42 e. 12 to 48

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The National Association of Colleges and Employers compiled information about annual starting salaries for college graduates by major. The mean starting salary for business administration graduates was \(\$ 39,850\) (CNNMoney.com, February 15,2006 ). Samples with annual starting data for marketing majors and accounting majors follow (data are in thousands): Marketing Majors \(34.2 \quad 45.0 \quad 39.5 \quad 28.4 \quad 37.7 \quad 35.8 \quad 30.6 \quad 35.2 \quad 34.2 \quad 42.4\) Accounting Majors \(33.5 \quad 57.1 \quad 49.7 \quad 40.2 \quad 44.2 \quad 45.2 \quad 47.8 \quad 38.0\) \(\begin{array}{llllll}53.9 & 41.1 & 41.7 & 40.8 & 55.5 & 43.5 & 49.1 & 49.9\end{array}\) a. Compute the mean, median, and mode of the annual starting salary for both majors. b. Compute the first and third quartiles for both majors. c. Business administration students with accounting majors generally obtain the highest annual salary after graduation. What do the sample data indicate about the difference between the annual starting salaries for marketing and accounting majors?

Small business owners often look to payroll service companies to handle their employee payroll. Reasons are that small business owners face complicated tax regulations and penalties for employment tax errors are costly. According to the Internal Revenue Service, \(26 \%\) of all small business employment tax returns contained errors that resulted in a tax penalty to the owner (The Wall Street Journal, January 30,2006 ). The tax penalties for a sample of 20 small business owners follow: \\[ \begin{array}{llllllll} 820 & 270 & 450 & 1010 & 890 & 700 & 1350 & 350 & 300 & 1200 \\ 390 & 730 & 2040 & 230 & 640 & 350 & 420 & 270 & 370 & 620 \end{array}\\] a. What is the mean tax penalty for improperly filed employment tax returns? b. What is the standard deviation? c. Is the highest penalty, \(\$ 2040,\) an outlier? d. What are some of the advantages of a small business owner hiring a payroll service company to handle employee payroll services, including the employment tax returns?

A panel of economists provided forecasts of the U.S. economy for the first six months of 2007 (The Wall Street Journal, January 2,2007 ). The percentage changes in gross domestic product (GDP) forecasted by 30 economists are as follows. \\[\begin{array}{lllllllll} 2.6 & 3.1 & 2.3 & 2.7 & 3.4 & 0.9 & 2.6 & 2.8 & 2.0 & 2.4 \\ 2.7 & 2.7 & 2.7 & 2.9 & 3.1 & 2.8 & 1.7 & 2.3 & 2.8 & 3.5 \\ 0.4 & 2.5 & 2.2 & 1.9 & 1.8 & 1.1 & 2.0 & 2.1 & 2.5 & 0.5 \end{array}\\] a. What is the minimum forecast for the percentage change in GDP? What is the maximum? b. Compute the mean, median, and mode. c. Compute the first and third quartiles. d. Did the economists provide an optimistic or pessimistic outlook for the U.S. economy? Discuss.

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