Chapter 6: Problem 39
Evaluate the integral using the indicated trigonometric substitution. Sketch and label the associated right triangle. \(\int \frac{d x}{x^{2} \sqrt{4-x^{2}}} \quad x=2 \sin \theta\)
Short Answer
Expert verified
The integral evaluates to \(-\frac{1}{4} \frac{\sqrt{4-x^2}}{x} + C\).
Step by step solution
01
Substitute with Trigonometric Identity
Given the substitution \(x = 2 \sin \theta\), differentiate it to find \(dx\): \(dx = 2 \cos \theta \, d\theta\). Substitute \(x\) and \(dx\) in the integral.Substituting: \(\int \frac{2 \cos \theta \, d\theta}{(2\sin\theta)^2 \sqrt{4-(2 \sin \theta)^2}}\)
02
Simplify the Expression
Simplify the expression:\[(2 \sin \theta)^2 = 4\sin^2 \theta, \quad 4-(2\sin \theta)^2= 4-4\sin^2 \theta=4(1-\sin^2 \theta) = 4\cos^2 \theta\]The integral becomes:\[\int \frac{2 \cos \theta \, d\theta}{4 \sin^2 \theta \cdot 2 \cos \theta} = \int \frac{d\theta}{4 \sin^2 \theta}\]
03
Further Simplify and Change to Known Integral
The integral \(\int \frac{d\theta}{4 \sin^2 \theta}\) can be rewritten using \(\csc^2 \theta = \frac{1}{\sin^2 \theta}\):\[\int \frac{d\theta}{4 \sin^2 \theta} = \frac{1}{4} \int \csc^2 \theta \, d\theta\]
04
Determine the Antiderivative
The antiderivative of \(\csc^2 \theta\) is \(-\cot \theta\), so:\[\frac{1}{4} \int \csc^2 \theta \, d\theta = -\frac{1}{4} \cot \theta + C\]
05
Back-substitute to Original Variable
Using the substitution \(x = 2 \sin \theta\), we construct a right triangle:- Opposite side = \(x\)- Hypotenuse = \(2\)- Adjacent side = \(\sqrt{4-x^2}\)Thus, \(\cot \theta = \frac{\text{Adjacent}}{\text{Opposite}} = \frac{\sqrt{4-x^2}}{x}\).Back-substitute in terms of \(x\):\[\text{Integral result} = -\frac{1}{4}\left(\frac{\sqrt{4-x^2}}{x}\right) + C\]
06
Sketch and Label Right Triangle
Draw the right triangle with the information:- Opposite side: \(x\)- Hypotenuse: \(2\)- Adjacent side: \(\sqrt{4-x^2}\)Label the angle \(\theta\) such that \(\sin \theta = \frac{x}{2}\) and \(\cot \theta = \frac{\sqrt{4-x^2}}{x}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Integrals
Integrals are a fundamental concept in calculus that allow us to determine the accumulation of quantities, like area under a curve or total change over an interval. In this problem, we are tasked with solving an integral using trigonometric substitution, a technique used when direct integration is challenging due to complex expressions.
Given the function \( \int \frac{d x}{x^{2} \sqrt{4-x^{2}}} \), our goal is to find an antiderivative, a function whose derivative gives us back the original function inside the integral sign. This requires careful substitutions and simplifications to rewrite the original integral into a form that's easier to integrate.
The substitution \( x = 2 \sin \theta \) transforms our integral into the world of trigonometric calculus, where we can utilize identities to simplify and solve.
Given the function \( \int \frac{d x}{x^{2} \sqrt{4-x^{2}}} \), our goal is to find an antiderivative, a function whose derivative gives us back the original function inside the integral sign. This requires careful substitutions and simplifications to rewrite the original integral into a form that's easier to integrate.
The substitution \( x = 2 \sin \theta \) transforms our integral into the world of trigonometric calculus, where we can utilize identities to simplify and solve.
Trigonometric Identities
Trigonometric identities play a crucial role in simplifying expressions during integration, particularly when employing substitution techniques. In this exercise, the substitution \( x = 2 \sin \theta \) simplifies our radical expression \( \sqrt{4-x^2} \) by leveraging identities.
Here's how it works step-by-step:
Here's how it works step-by-step:
- The expression \( 4 - x^2 \) becomes \( 4 - (2 \sin \theta)^2 = 4 \cos^2 \theta \) by using the Pythagorean identity \( 1 - \sin^2 \theta = \cos^2 \theta \).
- Substituting these simplifications back into the integral enables us to express it in terms of trigonometric functions, which are often easier to integrate.
Right Triangle
The use of a right triangle in trigonometric substitution is a powerful visualization aid that simplifies the conceptual understanding of these problems. We can sketch a right triangle to relate the given trigonometric substitution and better grasp the relationships between sides and the angle \( \theta \).
For substitution \( x = 2 \sin \theta \), we sketch a right triangle where:
For substitution \( x = 2 \sin \theta \), we sketch a right triangle where:
- The hypotenuse measures 2 (because \( \sin \theta = \frac{x}{2} \))
- The opposite side measures \( x \)
- The adjacent side is \( \sqrt{4-x^2} \)
Antiderivative
Finding an antiderivative means determining a function whose derivative returns to the integrand. In our problem, after simplifying and substituting, we arrive at the integral \( \int \csc^2 \theta \, d\theta \).
To find the antiderivative, we use trigonometric integration rules:
This showcases the elegance of trigonometric substitution: simplifying complex expressions and solving challenging integrals by transforming them into familiar forms.
To find the antiderivative, we use trigonometric integration rules:
- The antiderivative of \( \csc^2 \theta \) is \( -\cot \theta \).
- Thus, the solution in terms of \( \theta \) becomes \( -\frac{1}{4} \cot \theta + C \).
This showcases the elegance of trigonometric substitution: simplifying complex expressions and solving challenging integrals by transforming them into familiar forms.