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Determine whether each integral is convergent or divergent. Evaluate those that are convergent. $$\int_{2}^{\infty} e^{-5 p} d p$$

Short Answer

Expert verified
The integral converges and evaluates to \(\frac{1}{5}e^{-10}\).

Step by step solution

01

Analyze the Type of Integral

The given integral is an improper integral because it has an infinite upper limit. We need to determine whether this integral converges or diverges.
02

Set Up the Integral to Evaluate

The integral we are examining is \(\int_{2}^{\infty} e^{-5p} \, dp\). We need to evaluate the limit as the upper bound approaches infinity: \(\lim_{b \to \infty} \int_{2}^{b} e^{-5p} \, dp\).
03

Determine the Antiderivative

To evaluate the integral \(\int e^{-5p} \, dp\), we find the antiderivative. The antiderivative of \(e^{-5p}\) is \(-\frac{1}{5}e^{-5p}\).
04

Evaluate the Definite Integral

Now, substitute the limits of integration into the antiderivative: \[\int_{2}^{b} e^{-5p} \, dp = \left[ -\frac{1}{5}e^{-5p} \right]_{2}^{b}\] Plug in the upper limit \(b\) and lower limit \(2\):\[-\frac{1}{5}e^{-5b} + \frac{1}{5}e^{-10}\].
05

Evaluate the Limit as the Upper Bound Approaches Infinity

Evaluate the limit as \(b\) approaches infinity: \(\lim_{b \to \infty} \left(-\frac{1}{5}e^{-5b} + \frac{1}{5}e^{-10}\right)\)As \(b\) approaches infinity, \(e^{-5b}\) approaches 0. Hence, the limit simplifies to \(\frac{1}{5}e^{-10}\).
06

Determine Convergence

Since the limit exists and evaluates to a finite number, the integral \(\int_{2}^{\infty} e^{-5p} \, dp\) converges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Convergent Integrals
Convergent integrals are a special kind of improper integral. These are integrals where limits either head towards infinity or an undefined point, but still lead to a specific, finite value. It may seem odd to think that integrating over an infinite range yields a finite number, but it is definitely possible.

For the integral to converge, we typically follow a clear process. First, we check if the integral has an infinite range or a singularity point. Finding asymptotic behavior or making limits crucially helps in determining convergence.

In the example given \(\int_{2}^{\infty} e^{-5p} \, dp\), we determine that it begins at 2 and continues infinitely. Employing limits as a tool is how we inspect convergence, which in this problem occurs due to the presence of an exponential function. That exponential part continuously decreases, ensuring the integral's convergence.

The end result is that our infinite sum indeed sums to something meaningful yet finite. In this instance, our integral indeed converges to a finite numerical value.
Antiderivatives
Antiderivatives are the opposite operation of derivatives. Where derivatives focus on rates of change, antiderivatives reverse the operation to find original functions from their changes.

During integration, the antiderivative aids us in handling specific integrals. When it comes to our example, the function is \(e^{-5p}\), which results in an antiderivative of \(-\frac{1}{5}e^{-5p}\). This represents essentially going in reverse to see what function leads you to the specific rate of change noted by \(e^{-5p}\).
  • First, identify the function you need to reverse.
  • Transform it back to its primitive form using integration.
  • Use the antiderivative to evaluate definite integrals with proper limits.
Through these steps, one derives the necessary rule to find the definitive integral value over a given range.
Limits at Infinity
Limits at infinity help us understand behavior as approach distances become colossal or negligible. In calculus, this concept lays the foundation for evaluating improper integrals over infinite intervals.

In our evaluated case, we refurbish the upper bound limit with a variable \(b\) approaching infinity. The function \(e^{-5b}\) heads to zero as \(b\) becomes infinite thanks to the rapid decline when exponentiated by large numbers.

Assessing the result \(\lim_{b \to \infty} (-\frac{1}{5}e^{-5b} + \frac{1}{5}e^{-10})\), what remains as \(b\) reaches infinity is the constant term, \(\frac{1}{5}e^{-10}\). This calculation confirms that although we appear to explore boundless space, the integral value proves grounded and manageable.
  • Observe how exponential decay affects a function's approach towards zero.
  • Use limits to exclude any endless functions or baseless infinite results.
  • Evaluate meaningful outcomes even when initially facing infinite domains.
Understanding these limits allows us to ascertain the finite nature of the convergence at infinity within these structures.

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Most popular questions from this chapter

Suppose that \(F, G,\) and \(Q\) are polynomials and $$\frac{F(x)}{Q(x)}=\frac{G(x)}{Q(x)}$$ for all \(x\) except when \(Q(x)=0 .\) Prove that \(F(x)=G(x)\) for all \(x .[\)Hint\(:\) Use continuity. \(]\)

A particle moves on a straight line with velocity function \(v(t)=\sin \omega t \cos ^{2} \omega t .\) Find its position function \(s=f(t)\) if \(f(0)=0\)

(a) If \(g(x)=1 /(\sqrt{x}-1),\) use your calculator or computer to make a table of approximate values of \(\int_{2}^{t} g(x) d x\) for \(t=5,10,100,1000,\) and \(10,000 .\) Does it appear that \(\int_{2}^{\infty} g(x) d x\) is convergent or divergent? (b) Use the Comparison Theorem with \(f(x)=1 / \sqrt{x}\) to show that \(\int_{2}^{\infty} g(x) d x\) is divergent. (c) Illustrate part (b) by graphing \(f\) and \(g\) on the same screen for 2\(\leqslant x \leqslant 20 .\) Use your graph to explain intuitively why \(\int_{2}^{\infty} g(x) d x\) is divergent.

Astronomers use a technique called stellar stereography to determine the density of stars in a star cluster from the observed (two-dimensional) density that can be analyzed from a photograph. Suppose that in a spherical cluster of radius the density of stars depends only on the distance from the center of the cluster. If the perceived star density is given by , where is the observed planar distance from the center of the cluster, and is the actual density, it can be shown that $$y(s)=\int_{s}^{R} \frac{2 r}{\sqrt{r^{2}-s^{2}}} x(r) d r$$ If the actual density of stars in a cluster is \(x(r)=\frac{1}{2}(R-r)^{2}\) , find the perceived density \(y(s) .\)

(a) Evaluate the integral \(\int_{0}^{\infty} x^{n} e^{-x} d x\) for \(n=0,1,2,\) and \(3 .\) (b) Guess the value of \(\int_{0}^{\infty} x^{n} e^{-x} d x\) when \(n\) is an arbitrary positive integer. (c) Prove your guess using mathematical induction.

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