Chapter 2: Problem 16
\(3-26=\) Differentiate. $$g(t)=\frac{t-\sqrt{t}}{t^{1 / 3}}$$
Short Answer
Expert verified
The derivative is \(g'(t) = \frac{2}{3}t^{-1/3} - \frac{1}{6}t^{-5/6}\).
Step by step solution
01
Simplify the Function
First, let's simplify the function by expressing it in terms of powers. Write \(g(t)\) as \(g(t) = \frac{t}{t^{1/3}} - \frac{\sqrt{t}}{t^{1/3}}\). This simplifies to \(g(t) = t^{2/3} - t^{1/2 - 1/3}\), which is \(g(t) = t^{2/3} - t^{1/6}\).
02
Differentiate the First Term
Differentiate the first term, \(t^{2/3}\). Using the power rule \(\frac{d}{dt}[t^n] = nt^{n-1}\), we find the derivative of \(t^{2/3}\) to be \(\frac{2}{3}t^{-1/3}\).
03
Differentiate the Second Term
Now differentiate the second term, \(t^{1/6}\). Using the power rule again, \(\frac{d}{dt}[t^n] = nt^{n-1}\), we find the derivative of \(t^{1/6}\) to be \(\frac{1}{6}t^{-5/6}\).
04
Combine the Derivatives
Combine the derivatives from both terms. Thus, the derivative of \(g(t)\) is \(g'(t) = \frac{2}{3}t^{-1/3} - \frac{1}{6}t^{-5/6}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding the Power Rule
The power rule is a fundamental concept in calculus used to find the derivative of power functions, which are functions of the form \(t^n\). It allows us to quickly and easily determine the rate at which a function is changing. The rule states that for any real number \(n\), the derivative of \(t^n\) with respect to \(t\) is \(nt^{n-1}\). This means you multiply the entire term by its current power and then subtract one from that power.
For example, if you want to differentiate \(t^{2/3}\), you use the power rule by multiplying \(t^{2/3}\) by \(\frac{2}{3}\) and then decrease the exponent by 1 to get \(\frac{2}{3}t^{-1/3}\).
This method is powerful as it provides an efficient shortcut to handle derivatives, especially when dealing with polynomials or any expressions with variables raised to a power.
For example, if you want to differentiate \(t^{2/3}\), you use the power rule by multiplying \(t^{2/3}\) by \(\frac{2}{3}\) and then decrease the exponent by 1 to get \(\frac{2}{3}t^{-1/3}\).
This method is powerful as it provides an efficient shortcut to handle derivatives, especially when dealing with polynomials or any expressions with variables raised to a power.
Basics of Differentiation
Differentiation is the process of finding a derivative, which represents the rate of change of a function. Imagine you're driving a car; the derivative is like the speedometer, it tells you how fast you're going (or how fast something is changing in general).
When you differentiate a function, you apply rules, such as the power rule or the product rule, to calculate how much the function's value changes with respect to a change in its input (like time, \(t\)).
This gives you insight into how fast and in what manner the function \(g(t)\) is changing.
When you differentiate a function, you apply rules, such as the power rule or the product rule, to calculate how much the function's value changes with respect to a change in its input (like time, \(t\)).
- The power rule is used for differentiating power functions like \(t^n\).
- Other rules, like the product and quotient rules, are used when functions are multiplied or divided.
- Chain rule is used for compositions of functions.
This gives you insight into how fast and in what manner the function \(g(t)\) is changing.
Simplifying Functions for Easier Differentiation
Simplifying a function before differentiation is almost like cleaning your workspace before starting a task. It makes the process smoother and reduces potential errors. Simplification involves expressing functions in a form that's easier to work with, often by breaking down complex expressions into simpler components.
In our example, the original function \(g(t) = \frac{t - \sqrt{t}}{t^{1/3}}\) was simplified to \(g(t) = t^{2/3} - t^{1/6}\) before differentiation. This was done by simplifying each part of the expression using properties of exponents:
In our example, the original function \(g(t) = \frac{t - \sqrt{t}}{t^{1/3}}\) was simplified to \(g(t) = t^{2/3} - t^{1/6}\) before differentiation. This was done by simplifying each part of the expression using properties of exponents:
- The term \(\frac{t}{t^{1/3}}\) simplifies to \(t^{2/3}\) because dividing powers subtracts their exponents.
- The term \(\frac{\sqrt{t}}{t^{1/3}}\) simplifies to \(t^{1/6}\) by realizing that \(\sqrt{t} = t^{1/2}\) and then applying exponent rules.