/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 A tangent line is drawn to the h... [FREE SOLUTION] | 91Ó°ÊÓ

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A tangent line is drawn to the hyperbola \(x y=c\) at a point \(P .\) (a) Show that the midpoint of the line segment cut from this tangent line by the coordinate axes is \(P\) . (b) Show that the triangle formed by the tangent line and the coordinate axes always has the same area, no matter where \(P\) is located on the hyperbola.

Short Answer

Expert verified
(a) Midpoint at P. (b) Triangle's area is always 2c.

Step by step solution

01

Find the equation of the tangent line

The equation of the hyperbola is given by \(xy = c\). To find the tangent at a point \((x_0, y_0)\) on the hyperbola, we use the derivative. Differentiate with respect to \(x\), we get \(y + x\frac{dy}{dx} = 0\). Solve for \(\frac{dy}{dx}\), which gives the slope \(m = -\frac{y_0}{x_0}\). The tangent line at \((x_0, y_0)\) is: \[y - y_0 = -\frac{y_0}{x_0}(x - x_0)\] Simplifying, we get:\[x y_0 + y x_0 = 2x_0 y_0\]. This is the equation of the tangent line.
02

Determine where the tangent line intersects the axes

To find the x-intercept, set \(y = 0\) in the equation \(xy_0 + yx_0 = 2x_0y_0\):\[x = 2x_0\].To find the y-intercept, set \(x = 0\):\[y = 2y_0\]. Thus, the tangent line intersect the axes at points \((2x_0, 0)\) and \((0, 2y_0)\).
03

Find the midpoint of the segment cut by the axes

The coordinates of mid-point of the line segment between \((2x_0, 0)\) and \((0, 2y_0)\) is:\[\left(\frac{2x_0 + 0}{2},\frac{0 + 2y_0}{2}\right) = (x_0, y_0)\].Hence, the midpoint of the segment is \(P=(x_0, y_0)\), proving part (a) of the question.
04

Calculate the area of the triangle formed by the tangent and axes

The vertices of the triangle are \((0, 0)\), \((2x_0, 0)\), and \((0, 2y_0)\). The base of the triangle on the x-axis is \(2x_0\) and the height on the y-axis is \(2y_0\). The area \(A\) of the triangle is given by:\[A = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 2x_0 \times 2y_0 = 2x_0y_0\]Since \(x_0y_0 = c\) (from the hyperbola's equation), the area \(A = 2c\). This area is constant, irrespective of the point \(P\)'s position, hence proving part (b).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Tangent Line
A tangent line is a straight line that touches a curve at a single point without crossing it. Mathematically, a tangent to a curve at a point represents the 'instantaneous direction' of the curve at that point. When we find a tangent line for the hyperbola given by the equation \(xy = c\), we first need to compute the slope at a point \((x_0, y_0)\) on the hyperbola. This involves calculus, specifically differentiation.
  • Differentiate the hyperbola equation \(xy = c\) with respect to \(x\) to find the slope (or gradient) of the tangent line.
  • The derivative gives \(y + x\frac{dy}{dx} = 0\), which simplifies to the slope \(m = -\frac{y_0}{x_0}\).
Thus, the equation of the tangent line at \((x_0, y_0)\) becomes \(y - y_0 = -\frac{y_0}{x_0}(x - x_0)\). Here, the tangent not only tells us about the angle at which it touches the hyperbola but also helps us explore other geometric characteristics, such as intersecting the coordinate axes.
Hyperbola
A hyperbola is a type of conic section, formed by intersecting a cone with a plane at a steeper angle than the cone's side. The standard form of a hyperbola is \(xy = c\), where \(c\) is a constant. This equation describes an open curve that has two branches.
  • The branches of a hyperbola are symmetric with respect to both the x-axis and y-axis.
  • A hyperbola has two asymptotes, which are lines that the curve approaches but never touches.
When exploring the hyperbola \(xy = c\), one interesting point is how tangent lines behave. For this specific hyperbola, each point \((x_0, y_0)\) has an associated tangent line, and the curvature changes as \(c\) varies or as point \(P\) moves along the curve. Understanding the tangent lines helps us conclude about midpoints and areas related to the hyperbola.
Midpoint of a Segment
The midpoint of a segment is the point that divides the segment into two equal parts. Usually, if you have two points \((x_1, y_1)\) and \((x_2, y_2)\), the midpoint can be found using the formula:\[\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)\]This concept is crucial when dealing with line segments on coordinate planes. In this exercise, after solving where the tangent line intersects the axes at points \((2x_0, 0)\) and \((0, 2y_0)\), we find the midpoint to be \((x_0, y_0)\), verifying that P itself is the midpoint.
  • This confirms that the tangent correctly reflects the hyperbola's symmetry and balance.
  • Finding the midpoint showcases how tangents relate to both geometric positioning and algebraic representation.
Area of a Triangle
The area of a triangle can be calculated if you know the base and height: \[A = \frac{1}{2} \times \text{base} \times \text{height}\]In this specific case, the triangle is formed by the tangent line and the coordinate axes, with vertices \((0, 0)\), \((2x_0, 0)\), and \((0, 2y_0)\). This straightforward setup simplifies the calculation.
  • The base is the horizontal line \(2x_0\) along the x-axis.
  • The height is the vertical line \(2y_0\) along the y-axis.
  • The area ends up as \(2x_0y_0\), but since \(x_0y_0 = c\), we have \(A = 2c\).
No matter where point \((x_0, y_0)\) is located on the hyperbola \(xy = c\), the area of this triangle remains constant. It's a beautiful example of how algebraic constraints (the hyperbola's equation) translate into geometric invariances in solving problems.

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Most popular questions from this chapter

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