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Show that the curve with parametric equations \(x=t^{2}\) , \(y=1-3 t, z=1+t^{3}\) passes through the points \((1,4,0)\) and \((9,-8,28)\) but not through the point \((4,7,-6)\)

Short Answer

Expert verified
The curve passes through \\( (1, 4, 0) \\\) and \\( (9, -8, 28) \\\), but not \\( (4, 7, -6) \\\).

Step by step solution

01

Substitute Values for Point (1, 4, 0)

Check if the point \( (1, 4, 0) \) lies on the curve by substituting the parametric equations with parameter \( t \). Start with \( x = 1, y = 4, z = 0 \).- Since \( x = t^2 \), solving for \( t \) gives \( t = \pm 1 \).- Choosing \( t = -1 \) (since with \( t=1, y eq 4\)), we substitute \( t = -1 \) into the other equations: \( y = 1 - 3(-1) = 4 \) and \( z = 1 + (-1)^3 = 0 \). Thus, the point \( (1, 4, 0) \) is on the curve.
02

Substitute Values for Point (9, -8, 28)

Verify if the point \( (9, -8, 28) \) lies on the curve using the parametric equations.- For \( x = 9 \), solving \( x = t^2 \) gives \( t = \pm 3 \).- Choosing \( t = -3 \) (since with \( t=3, y eq -8\)), we substitute it into the other equations: \( y = 1 - 3\times (-3) = -8 \) and \( z = 1 + (-3)^3 = 28 \). Thus, the point \( (9, -8, 28) \) is on the curve.
03

Verify Point (4, 7, -6)

Check whether the point \( (4, 7, -6) \) is on the curve.- Since \( x = t^2 \) implies \( t = \pm 2 \), substitute these values into the other equations.- For \( t = 2 \): \( y = 1 - 3\times 2 = -5 \), which does not match \( y = 7 \). Similarly, check \( t = -2 \): \( y = 1 - 3\times (-2) = 7 \), \( z = 1 + (-2)^3 = -7 \), which does not match \( z = -6 \). Thus, the point \( (4, 7, -6) \) is not on the curve.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Curve Analysis
Parametric equations are a fantastic way to represent curves, especially when dealing with multidimensional geometry. These equations involve a parameter, often denoted as \(t\), which expresses the coordinates \(x\), \(y\), and \(z\) in terms of simple functions of \(t\). For instance, the parametric equations in our problem are \(x = t^2\), \(y = 1 - 3t\), and \(z = 1 + t^3\).

Each equation defines one coordinate as a function of \(t\). This approach is useful because it lets us easily capture complex shapes, like spirals or loops, which might be trickier to handle with standard Cartesian equations.
  • **Advantages:** Allows us to model dynamic paths and movement along a curve.
  • **Applications:** Widely used in computer graphics, physics simulations, and robotics.


Sometimes, to analyze a parametric curve, we examine each component (\(x, y, z\)) to understand the overall movement or path this curve takes in space. In this analysis, we're also able to determine if specific points lie on the curve by plugging their coordinates into these parametric equations, and checking if we can find a consistent \(t\) value.
Parametric Points Verification
To verify whether points are on a parametric curve, substituting their coordinates into the equations can reveal if a consistent parameter value exists.

### Process Overview: 1. **Substitute for \(x\):** Solve the equation to find differences in \(t\). For point \((1, 4, 0)\), substituting \(x = 1\) gives \( t = \pm 1 \). We choose \(t = -1\) by testing if it fits with \(y\) and \(z\).

2. **Verify with \(y\) and \(z\):** Ensure that \( t \) found fits remaining coordinates.
  • If it does (like \((1, 4, 0)\)), the point lies on the curve.
  • If no \( t \) satisfies, it doesn’t (like \((4, 7, -6)\)).


This procedure ensures thorough verification and highlights the utility of parametric equations in analyzing spatial positions. It’s often valuable to double-check computations for each coordinate.
3D Coordinate Geometry
Moving beyond 2D, three-dimensional coordinate geometry allows us to explore and decipher the spatial arrangements of objects. Parametric equations often describe curves in \(\mathbb{R}^3\), offering a robust framework for understanding complex 3D paths.

With our set of parametric equations, each pair \((t, x, y, z)\) constructs a point in 3D space, forming a continuous curve as \(t\) changes. This is especially powerful in scenarios such as:
  • **Modeling trajectories** of spaceships or particles.
  • **Analyzing surfaces** by elevating complex curves into 3D space.

By understanding how these equations operate together, we can accurately verify if specific 3D points—expressed as \((x, y, z)\)—are indeed traversed by our parametric curve.

In summary, by discovering the correct \(t\) value that fits all three dimensions, and disconfirming it when values don’t align, our analysis remains valid and comprehensive.

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Most popular questions from this chapter

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