Chapter 15: Problem 8
Prove that: (a) \(\sinh (x+y)=\sinh x \cosh y+\cosh x \sinh y\) (b) \(\cosh (x+y)=\cosh x \cosh y+\sinh x \sinh y\) Hence prove that: $$ \tanh (x+y)=\frac{\tanh x+\tanh y}{1+\tanh x \tanh y} $$
Short Answer
Expert verified
\( \sinh (x+y)=\sinh x \cosh y+\cosh x \sinh y \) \( \cosh (x+y)=\cosh x \cosh y+\sinh x \sinh y \) \( \tanh (x+y)=\frac{\tanh x+\tanh y}{1+\tanh x \tanh y} \)
Step by step solution
01
Recall definitions of Hyperbolic Functions
Recall that the hyperbolic sine and cosine functions are defined as: \[ \ \ \ \sinh x = \frac{e^x - e^{-x}}{2} \ \ \ \ \ \ \cosh x = \frac{e^x + e^{-x}}{2} \ \ \]
02
Expand using Exponential definitions
Using the definitions, expand \( \sinh(x+y) \) and \( \cosh(x+y) \) as follows: \[ \ \sinh(x+y) = \frac{e^{x+y} - e^{-(x+y)}}{2} \ \cosh(x+y) = \frac{e^{x+y} + e^{-(x+y)}}{2} \ \ \]
03
Use Algebraic Manipulation
Separately expand the terms \( e^{x+y} \) and \( e^{-(x+y)} \) to show that: \[ \ \sinh(x+y) = \frac{e^x e^y - e^{-x} e^{-y}}{2} \ \ \cosh(x+y) = \frac{e^x e^y + e^{-x} e^{-y}}{2} \ \ \]
04
Use Symmetry of Exponential terms
Reorganize by substituting back the definitions of \( \sinh x \) and \( \cosh x \): \[ \ \sinh(x+y) = \sinh x \cosh y + \cosh x \sinh y \ \cosh(x+y) = \cosh x \cosh y + \sinh x \sinh y \ \ \]
05
Proving the Hyperbolic Tangent Addition Formula
Recall the definition of the hyperbolic tangent: \[ \tanh x = \frac{\sinh x}{\cosh x} \] Using the previously proven formulas for \( \sinh(x+y) \) and \( \cosh(x+y) \): \[ \tanh(x+y) = \frac{\sinh(x+y)}{\cosh(x+y)} = \frac{\sinh x \cosh y + \cosh x \sinh y}{\cosh x \cosh y + \sinh x \sinh y} \ \ = \frac{\frac{\sinh x}{\cosh x} + \frac{\sinh y}{\cosh y}}{1 + \frac{\sinh x \sinh y}{\cosh x \cosh y}} = \frac{\tanh x + \tanh y}{1 + \tanh x \tanh y} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
hyperbolic sine
The hyperbolic sine function, denoted as \(\text{sinh}\), is analogous to the sine function in trigonometry, but it applies to hyperbolas instead of circles. The definition of hyperbolic sine is given by:
\( \text{sinh} \, x = \frac{e^x - e^{-x}}{2} \). Here, \(e\) represents the base of the natural logarithm.
The hyperbolic sine function exhibits a number of crucial properties:
\[ \text{sinh}(x+y) = \frac{e^{x+y} - e^{-(x+y)}}{2} = \frac{e^x e^y - e^{-x} e^{-y}}{2} \]. Now, reorganizing these terms using \( \text{sinh} \, x \) and \( \text{cosh} \, x \), we finally derive the sum formula:
\[ \text{sinh}(x+y) = \text{sinh} \, x \, \text{cosh} \, y + \text{cosh} \, x \, \text{sinh} \, y \]This establishes a parallel with the sine sum formula in trigonometry.
\( \text{sinh} \, x = \frac{e^x - e^{-x}}{2} \). Here, \(e\) represents the base of the natural logarithm.
The hyperbolic sine function exhibits a number of crucial properties:
- \(\text{sinh}(0) = 0\)
- It is an odd function, meaning \(\text{sinh}(-x) = -\text{sinh}(x)\)
- Its derivative is \(\text{cosh}(x)\), the hyperbolic cosine function
\[ \text{sinh}(x+y) = \frac{e^{x+y} - e^{-(x+y)}}{2} = \frac{e^x e^y - e^{-x} e^{-y}}{2} \]. Now, reorganizing these terms using \( \text{sinh} \, x \) and \( \text{cosh} \, x \), we finally derive the sum formula:
\[ \text{sinh}(x+y) = \text{sinh} \, x \, \text{cosh} \, y + \text{cosh} \, x \, \text{sinh} \, y \]This establishes a parallel with the sine sum formula in trigonometry.
hyperbolic cosine
The hyperbolic cosine function, denoted as \(\text{cosh}\), is used in describing the shape of a hanging cable or chain. Defined similarly to hyperbolic sine, its formula is:
\[ \text{cosh} \, x = \frac{e^x + e^{-x}}{2} \] Like hyperbolic sine, \( e \) here stands for the base of the natural logarithm.
Some key properties of \( \text{cosh} \, x \) are:
\[ \text{cosh}(x+y) = \frac{e^{x+y} + e^{-(x+y)}}{2} = \frac{e^x e^y + e^{-x} e^{-y}}{2} \]
Substituting back the expressions for \( \text{sinh} \, x \) and \( \text{cosh} \, x \), we get:
\[ \text{cosh}(x+y) = \text{cosh} \, x \, \text{cosh} \, y + \text{sinh} \, x \, \text{sinh} \, y \] This similarly mirrors the cosine sum formula in trigonometry.
\[ \text{cosh} \, x = \frac{e^x + e^{-x}}{2} \] Like hyperbolic sine, \( e \) here stands for the base of the natural logarithm.
Some key properties of \( \text{cosh} \, x \) are:
- \(\text{cosh}(0) = 1\)
- It is an even function, meaning \(\text{cosh}(-x) = \text{cosh}(x)\)
- Its derivative is \(\text{sinh}(x)\)
\[ \text{cosh}(x+y) = \frac{e^{x+y} + e^{-(x+y)}}{2} = \frac{e^x e^y + e^{-x} e^{-y}}{2} \]
Substituting back the expressions for \( \text{sinh} \, x \) and \( \text{cosh} \, x \), we get:
\[ \text{cosh}(x+y) = \text{cosh} \, x \, \text{cosh} \, y + \text{sinh} \, x \, \text{sinh} \, y \] This similarly mirrors the cosine sum formula in trigonometry.
hyperbolic tangent
The hyperbolic tangent function, denoted as \(\text{tanh}\), is defined as the ratio of the hyperbolic sine to the hyperbolic cosine:
\[ \text{tanh} \, x = \frac{ \text{sinh} \, x }{ \text{cosh} \, x } \] This function is useful for describing smooth transitions and is found in many areas including engineering and financial models.
Key properties include:
\[ \text{tanh}(x+y) = \frac{\text{sinh}(x+y)}{\text{cosh}(x+y)} = \frac{\text{sinh} \, x \, \text{cosh} \, y + \text{cosh} \, x \, \text{sinh} \, y}{\text{cosh} \, x \, \text{cosh} \, y + \text{sinh} \, x \, \text{sinh} \, y} = \frac{\frac{\text{sinh} \, x}{\text{cosh} \, x} + \frac{\text{sinh} \, y}{\text{cosh} \, y}}{1 + \frac{\text{sinh} \, x \, \text{sinh} \, y}{\text{cosh} \, x \, \text{cosh} \, y} } = \frac{\text{tanh} \, x + \text{tanh} \, y}{1 + \text{tanh} \, x \, \text{tanh} \, y} \] This formula for \(\text{tanh}(x+y)\) is similar to the addition formula for the tangent function in trigonometry.
\[ \text{tanh} \, x = \frac{ \text{sinh} \, x }{ \text{cosh} \, x } \] This function is useful for describing smooth transitions and is found in many areas including engineering and financial models.
Key properties include:
- \(\text{tanh}(0) = 0\)
- \(-1 < \text{tanh}(x) < 1\) holds for all real numbers x
- Its derivative is \(1 - \text{tanh}^2(x)\)
\[ \text{tanh}(x+y) = \frac{\text{sinh}(x+y)}{\text{cosh}(x+y)} = \frac{\text{sinh} \, x \, \text{cosh} \, y + \text{cosh} \, x \, \text{sinh} \, y}{\text{cosh} \, x \, \text{cosh} \, y + \text{sinh} \, x \, \text{sinh} \, y} = \frac{\frac{\text{sinh} \, x}{\text{cosh} \, x} + \frac{\text{sinh} \, y}{\text{cosh} \, y}}{1 + \frac{\text{sinh} \, x \, \text{sinh} \, y}{\text{cosh} \, x \, \text{cosh} \, y} } = \frac{\text{tanh} \, x + \text{tanh} \, y}{1 + \text{tanh} \, x \, \text{tanh} \, y} \] This formula for \(\text{tanh}(x+y)\) is similar to the addition formula for the tangent function in trigonometry.