Chapter 15: Problem 5
Evaluate: (a) \(\tanh ^{-1} 0-75\) and (b) \(\cosh ^{-1} 2\).
Short Answer
Expert verified
(a) \(\tanh^{-1}(0.75) \approx 0.972 \) (b) \(\text{cosh}^{-1}(2) \approx 1.317 \)
Step by step solution
01
Understanding \(\tanh^{-1}(0.75)\)
The function \(\tanh^{-1}(x)\), also known as the inverse hyperbolic tangent, is defined such that if \(y = \tanh^{-1}(x)\), then \(x = \tanh(y)\). We need to find the value of \(y\) when \(x = 0.75\).
02
Applying the formula for \(\tanh^{-1}(x)\)
The formula for the inverse hyperbolic tangent is \[ \tanh^{-1}(x) = \frac{1}{2} \times \text{ln}\frac{1+x}{1-x} \] Plugging \(x = 0.75\) into this formula, we get \[ \tanh^{-1}(0.75) = \frac{1}{2} \times \text{ln}\frac{1+0.75}{1-0.75} \]
03
Calculating the result for \(\tanh^{-1}(0.75)\)
Simplify the expression inside the logarithm: \[ \tanh^{-1}(0.75) = \frac{1}{2} \times \text{ln}\frac{1.75}{0.25} = \frac{1}{2} \times \text{ln}(7) \] Using a calculator, \[ \tanh^{-1}(0.75) \approx 0.972 \]
04
Understanding \(\text{cosh}^{-1}(2)\)
The function \(\text{cosh}^{-1}(x)\), also known as the inverse hyperbolic cosine, is defined such that if \(y = \text{cosh}^{-1}(x)\), then \(x = \text{cosh}(y)\). We need to find the value of \(y\) when \(x = 2\).
05
Applying the formula for \(\text{cosh}^{-1}(x)\)
The formula for the inverse hyperbolic cosine is \[ \text{cosh}^{-1}(x) = \text{ln}(x + \text{sqrt}(x^2 - 1)) \] Plugging \(x = 2\) into this formula, we get \[ \text{cosh}^{-1}(2) = \text{ln}(2 + \text{sqrt}(2^2 - 1)) \]
06
Calculating the result for \(\text{cosh}^{-1}(2)\)
Simplify the expression inside the logarithm: \[ \text{\(cosh\)}^{-1}(2) = \text{ln}(2 + \text{sqrt}(4 - 1)) = \text{ln}(2 + \text{sqrt}(3)) \] Using a calculator, \[ \text{cosh}^{-1}(2) \approx 1.317 \]
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Inverse Hyperbolic Tangent
The inverse hyperbolic tangent, denoted as \(\tanh^{-1}(x)\), is the function that 'reverses' the hyperbolic tangent function. It answers the question: for a given value \(x\), what hyperbolic angle \(y\) satisfies \(x = \tanh(y)\)?
To find \(\tanh^{-1}(0.75)\), we use the formula: \(\tanh^{-1}(x) = \frac{1}{2} \times \text{ln}\frac{1+x}{1-x}\).
Let's substitute \(x = 0.75\):
\(\tanh^{-1}(0.75) = \frac{1}{2} \times \text{ln}\frac{1+0.75}{1-0.75}\).
Simplifying the fraction inside the logarithm gives us: \(\tanh^{-1}(0.75) = \frac{1}{2} \times \text{ln}\frac{1.75}{0.25} = \frac{1}{2} \times \text{ln}(7)\). By using a calculator, you get \(\tanh^{-1}(0.75) \approx 0.972\). This tells us the value of \(y\) such that \(\tanh(y) = 0.75\).
In summary:
To find \(\tanh^{-1}(0.75)\), we use the formula: \(\tanh^{-1}(x) = \frac{1}{2} \times \text{ln}\frac{1+x}{1-x}\).
Let's substitute \(x = 0.75\):
\(\tanh^{-1}(0.75) = \frac{1}{2} \times \text{ln}\frac{1+0.75}{1-0.75}\).
Simplifying the fraction inside the logarithm gives us: \(\tanh^{-1}(0.75) = \frac{1}{2} \times \text{ln}\frac{1.75}{0.25} = \frac{1}{2} \times \text{ln}(7)\). By using a calculator, you get \(\tanh^{-1}(0.75) \approx 0.972\). This tells us the value of \(y\) such that \(\tanh(y) = 0.75\).
In summary:
- Inverse hyperbolic tangent solves for the hyperbolic angle \(y\) given \(x\) in \(\tanh(y)\).
- The formula \(\frac{1}{2} \times \text{ln}\frac{1+x}{1-x}\) helps calculate it.
Inverse Hyperbolic Cosine
The inverse hyperbolic cosine, denoted as \(\text{cosh}^{-1}(x)\), is a function that 'reverses' the hyperbolic cosine. Similar to before, it answers: for a given value \(x\), what hyperbolic angle \(y\) satisfies \(x = \text{cosh}(y)\)?
To find \(\text{cosh}^{-1}(2)\), we use the formula: \(\text{cosh}^{-1}(x) = \text{ln}(x + \text{sqrt}(x^2 - 1))\).
Let's substitute \(x = 2\):
\(\text{cosh}^{-1}(2) = \text{ln}(2 + \text{sqrt}(2^2 - 1))\).
Simplifying inside the logarithm gives us: \(\text{cosh}^{-1}(2) = \text{ln}(2 + \text{sqrt}(4 - 1)) = \text{ln}(2 + \text{sqrt}(3))\).
Using a calculator, you get \(\text{cosh}^{-1}(2) \approx 1.317\). This value of \(y\) such that \(\text{cosh}(y) = 2\) is obtained.
In summary:
To find \(\text{cosh}^{-1}(2)\), we use the formula: \(\text{cosh}^{-1}(x) = \text{ln}(x + \text{sqrt}(x^2 - 1))\).
Let's substitute \(x = 2\):
\(\text{cosh}^{-1}(2) = \text{ln}(2 + \text{sqrt}(2^2 - 1))\).
Simplifying inside the logarithm gives us: \(\text{cosh}^{-1}(2) = \text{ln}(2 + \text{sqrt}(4 - 1)) = \text{ln}(2 + \text{sqrt}(3))\).
Using a calculator, you get \(\text{cosh}^{-1}(2) \approx 1.317\). This value of \(y\) such that \(\text{cosh}(y) = 2\) is obtained.
In summary:
- Inverse hyperbolic cosine solves for the hyperbolic angle \(y\) given \(x\) in \(\text{cosh}(y)\).
- The formula \(\text{ln}(x + \text{sqrt}(x^2 - 1))\) helps calculate it.
Logarithms
Logarithms, often abbreviated as 'ln' for natural logarithm, is a fundamental mathematical concept.
Definition: A logarithm answers the question: 'To what power must we raise a specific base to get a given number?' For natural logarithms, the base is 'e' (approximately 2.718).
For example, if \(e^y = x\), then \(y = \text{ln}(x)\).
Hyperbolic functions often utilize logarithms for their inverse forms. For instance:
Definition: A logarithm answers the question: 'To what power must we raise a specific base to get a given number?' For natural logarithms, the base is 'e' (approximately 2.718).
For example, if \(e^y = x\), then \(y = \text{ln}(x)\).
Hyperbolic functions often utilize logarithms for their inverse forms. For instance:
- The formula for \( \tanh^{-1}(0.75) = \frac{1}{2} \text{ln} \frac{1+0.75}{1-0.75} \).
- The formula for \( \text{cosh}^{-1}(2) = \text{ln}(2 + \text{sqrt}(4-1)) \).