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For Exercises 7 through \(27,\) perform these steps. a. State the hypotheses and identify the claim. b. Find the critical value(s). c. Compute the test value. d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. Victims of Violence A random survey of 80 women who were victims of violence found that 24 were attacked by relatives. A random survey of 50 men found that 6 were attacked by relatives. At \(\alpha=0.10,\) can it be shown that the percentage of women who were attacked by relatives is greater than the percentage of men who were attacked by relatives?

Short Answer

Expert verified
We reject the null hypothesis, concluding that more women than men are attacked by relatives.

Step by step solution

01

State the Hypotheses

We need to set up the null and alternative hypotheses. The null hypothesis (\( H_0 \)) states that the proportion of women attacked by relatives is less than or equal to the proportion of men attacked by relatives. The alternative hypothesis (\( H_1 \)) states that the proportion of women attacked by relatives is greater than the proportion of men attacked by relatives. Mathematically, it is expressed as: \[ H_0: p_1 \leq p_2 \]\[ H_1: p_1 > p_2 \] Where \( p_1 \) is the proportion of women who were attacked by relatives, and \( p_2 \) is the proportion of men who were attacked by relatives.
02

Identify the Claim

The claim is that the percentage of women attacked by relatives (\( p_1 \)) is greater than the percentage of men who were attacked by relatives (\( p_2 \)). This corresponds with the alternative hypothesis (\( H_1 \)).
03

Find the Critical Value

Since this is a one-tailed test at an alpha level of \( \alpha = 0.10 \), we need the critical value from the standard normal distribution (Z-table). For a right-tailed test at \( 0.10 \) significance level, the critical value \( z_c \) is approximately 1.28.
04

Compute the Test Value

We first calculate the sample proportions: - \( \hat{p}_1 = \frac{24}{80} = 0.3 \) (women)- \( \hat{p}_2 = \frac{6}{50} = 0.12 \) (men)Next, calculate the pooled sample proportion \( \hat{p} = \frac{24 + 6}{80 + 50} = \frac{30}{130} = 0.2308 \).Now we compute the standard error (SE):\[ SE = \sqrt{\hat{p}(1-\hat{p})\left(\frac{1}{n_1} + \frac{1}{n_2}\right)} \]\[ SE = \sqrt{0.2308(1-0.2308)\left(\frac{1}{80} + \frac{1}{50}\right)} = 0.0774 \]Finally, compute the test statistic (z):\[ z = \frac{\hat{p}_1 - \hat{p}_2}{SE} = \frac{0.3 - 0.12}{0.0774} = 2.32 \]
05

Make the Decision

Since the test statistic \( z = 2.32 \) is greater than the critical value \( z_c = 1.28 \), we reject the null hypothesis \( H_0 \).
06

Summarize the Results

Based on the sample data and at the significance level of 0.10, there is sufficient evidence to support the claim that the percentage of women who were attacked by relatives is greater than the percentage of men who were attacked by relatives.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In hypothesis testing, the null hypothesis is an essential component. It's a statement made for the purpose of the test, which is assumed to be true until evidence suggests otherwise. In the given exercise, the null hypothesis (\( H_0 \)) asserts that the proportion of women who were attacked by relatives is less than or equal to the proportion of men attacked by relatives.This hypothesis provides a baseline or a neutral position against which the alternative hypothesis is tested. In mathematical terms, we formulate it as:\[H_0: p_1 \leq p_2\]Where \( p_1 \) represents the proportion of women attacked by relatives and \( p_2 \) represents the proportion of men attacked by relatives. By stating this hypothesis, we are essentially assuming for the time being that there is no greater prevalence of attacks among women.The null hypothesis is central because statistical tests are designed to evaluate whether there's enough evidence to reject it. The notion is not to prove it true but to determine the probability of observing the test results, assuming the null hypothesis holds true.
Alternative Hypothesis
The alternative hypothesis presents a contrasting claim to the null hypothesis and is what researchers typically aim to support. For the exercise, the alternative hypothesis (\( H_1 \)) asserts that the percentage of women attacked by relatives is greater than that of men.It stands as the statement researchers hope to find evidence for in the analysis. The hypothesis is articulated as:\[H_1: p_1 > p_2\]Here, \( p_1 \) again represents the proportion of women who are victims of attacks by relatives, while \( p_2 \) reflects the proportion for men. The alternative hypothesis is essential for directing the focus of the investigation.Should the data indicate enough evidence against the null hypothesis at the selected significance level, the alternative hypothesis gains support. In this scenario, finding a significant result in favor of \( H_1 \) would imply sufficient statistical evidence that more women, as a proportion, experience such attacks compared to men.
Critical Value
A critical value serves as a threshold to determine whether to reject the null hypothesis. It depends on the chosen significance level (\( \alpha \)) and the type of test being performed. For this exercise, the level of significance is \( 0.10 \), and we're dealing with a right-tailed test.To find the critical value, we refer to the standard normal distribution, often using a Z-table. Given that the significance level is \( 0.10 \), the critical value is approximately:\[z_c \approx 1.28\]This critical value acts as a cutoff point. If our computed test statistic exceeds this value, we have grounds to reject the null hypothesis. The critical value, therefore, delineates the boundary between the region where we would retain the null hypothesis and the area where we have enough evidence to support the alternative.It's crucial to understand that setting the critical value is context-dependent, influenced by the significance level, and the design of the hypothesis test.
Test Statistic
The test statistic provides a standardized measure to compare against the critical value. For this exercise, it quantifies the difference between sample proportions, taking into account variation within the samples.In computing the test statistic, sample data is compared under the assumption that the null hypothesis holds true. Here is the formula used:\[z = \frac{\hat{p}_1 - \hat{p}_2}{SE}\]Where:
  • \( \hat{p}_1 = 0.3 \) - Represents the sample proportion of women attacked by relatives.
  • \( \hat{p}_2 = 0.12 \) - Stands for the sample proportion of men attacked by relatives.
  • \( SE = 0.0774 \) - This is the standard error, calculated as part of assessing variability within the sample.
Upon calculation, the test statistic is found to be \( z = 2.32 \). Since \( z = 2.32 \) is greater than the critical value of \( 1.28 \), we reject the null hypothesis. The test statistic thus plays an instrumental role, guiding the decision-making about the hypotheses.Ultimately, the test statistic translates the observed data's deviation from the null hypothesis into a number that allows us to establish the statistical significance of the results.

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For Exercises 7 through \(27,\) perform these steps. a. State the hypotheses and identify the claim. b. Find the critical value(s). c. Compute the test value. d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. Leisure Time In a sample of \(150 \mathrm{men}, 132\) said that they had less leisure time today than they had 10 years ago. In a random sample of 250 women, 240 women said that they had less leisure time than they had 10 years ago. At \(\alpha=0.10,\) is there a difference in the proportions? Find the \(90 \%\) confidence interval for the difference of the two proportions. Does the confidence interval contain \(0 ?\) Give a reason why this information would be of interest to a researcher.

For Exercises 7 through \(27,\) perform these steps. a. State the hypotheses and identify the claim. b. Find the critical value(s). c. Compute the test value. d. Make the decision. e. Summarize the results. Use the traditional method of hypothesis testing unless otherwise specified. Animal Bites of Postal Workers In Cleveland, a random sample of 73 mail carriers showed that 10 had been bitten by an animal during one week. In Philadelphia, in a random sample of 80 mail carriers, 16 had received animal bites. Is there a significant difference in the proportions? Use \(\alpha=0.05 .\) Find the \(95 \%\) confidence interval for the difference of the two proportions.

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