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Home Ownership Rates The percentage rates of home ownership for 8 randomly selected states are listed below. Estimate the population variance and standard deviation for the percentage rate of home ownership with \(99 \%\) confidence. Assume the variable is normally distributed. $$ 66.075 .8 \quad 70.9 \quad 73.9 \quad 63.4 \quad 68.5 \quad 73.3 \quad 65.9 $$

Short Answer

Expert verified
The \(99\%\) confidence interval for the population standard deviation is calculated after finding the variance interval.

Step by step solution

01

Calculate the Sample Mean

First, calculate the sample mean \(\bar{x}\) of the given percentage rates. Add all the values together and divide by the number of values:\[\bar{x} = \frac{66.0 + 75.8 + 70.9 + 73.9 + 63.4 + 68.5 + 73.3 + 65.9}{8}\]Calculate this sum to find \(\bar{x}\).
02

Compute Sample Variance

Use the sample mean \(\bar{x}\) to calculate the sample variance \(s^2\). The formula is:\[s^2 = \frac{\sum (x_i - \bar{x})^2}{n-1}\]Subtract \(\bar{x}\) from each data point, square the result, sum these squares, and then divide by \(n-1\) where \(n\) is the number of data points (which is 8 in this case).
03

Determine the Confidence Interval for Variance

The \(99\%\) confidence interval for the population variance \(\sigma^2\) can be calculated using the Chi-Square distribution since it's normally distributed. Identify the critical values for a \(99\%\) confidence interval from a Chi-Square table. Use the formulas:\[\frac{(n-1)s^2}{\chi^2_{0.005}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{0.995}}\]Calculate these values using the sample variance from Step 2.
04

Compute Population Variance and Standard Deviation

Substitute the sample variance in the formulas from Step 3 to calculate the interval limits for the variance. Finally, take the square root of these variance limits to find the confidence interval for the population standard deviation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Variance
Understanding population variance is crucial for estimating how data points in a set are spread out. In simpler terms, it tells us how much the percentage rates of home ownership are expected to vary from one state to another. This is particularly useful when trying to make predictions or decisions based on statistical data.

Population variance, denoted as \(\sigma^2\), is a measure of how data points differ from the population mean. The primary drawback in calculating population variance directly is that we usually deal with samples, not entire populations. We estimate this variance through sample data using a specific formula:

- Calculate the mean (average) of the sample data
- Subtract this mean from each data point to get deviations
- Square each deviation
- Sum all squared deviations
- Divide the total by the number of data points minus one (i.e., degrees of freedom in the sample)

This method gives us the sample variance \(s^2\), an approximation of the population variance. This foundational understanding allows us to apply this information to more complex statistical concepts, like determining confidence intervals.
Standard Deviation
The standard deviation is a measure that complements variance by showing how much, on average, each observation deviates from the mean. It gives us a more tangible metric, especially since it is expressed in the same unit as the data itself.

After we calculate variance, finding the standard deviation is straightforward. We simply take the square root of the variance. So, for our home ownership example:

- Calculate sample variance first
- Take the square root of this variance to find the standard deviation

Standard deviation helps to understand the average distance from the mean. If the standard deviation is small, this means the data points are closely clustered around the mean. Conversely, a large standard deviation suggests a wide range of data points.

By analyzing the standard deviation, we gain insights into the consistency of homeownership percentages across states, which can guide policy-making and economic strategies.
Chi-Square Distribution
When it comes to estimating population variance and forming confidence intervals, the chi-square distribution comes into play. It's a statistical method used when working with normally distributed variables, especially for variance-related inquiries.

In the context of our exercise, since we assume a normal distribution for home ownership percentages, the chi-square distribution helps us to define the bounds within which the true population variance falls. Here's how it works:

- Identify the degrees of freedom, which is the sample size minus one
- Use a chi-square table to find critical values corresponding to our confidence level (in this case, 99%)
- Apply the formula: \[ \frac{(n-1)s^2}{\chi^2_{upper}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{lower}} \] - Solve the equations to get the lower and upper boundaries for variance

Understanding this distribution is pivotal when producing confidence intervals, allowing us to express the precision and reliability of our estimated population variance. It ensures that we are scientifically grounded in our predictions and conclusions regarding population characteristics.

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Most popular questions from this chapter

Overweight Men For a random sample of 60 over- weight men, the mean of the number of pounds that they were overweight was \(30 .\) The standard deviation of the population is 4.2 pounds. $$ \begin{array}{l}{\text { a. Find the best point estimate of the average number of }} \\ {\text { excess pounds that they weighed. }} \\ {\text { b. Find the } 95 \% \text { confidence interval of the mean of }} \\ {\text { these pounds. }}\end{array} $$ $$ \begin{array}{l}{\text {c. Find the } 99 \% \text { confidence interval of these pounds. }} \\ {\text { d. Which interval is larger? Why? }}\end{array} $$

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Home Internet Access According to a study, \(96 \%\) of adults ages \(18-29\) had internet access at home in 2015 . A researcher wanted to estimate the proportion of undergraduate college students \((18\) to 29 years) with access, so she randomly sampled 180 undergraduates and found that 157 had access. Estimate the true proportion with \(90 \%\) confidence.

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