91Ó°ÊÓ

Consider the given question,

Population consists of earthquakes with magnitude of 7.5 hours a greater on Richter scale.

Population mean time between two earthquakes $\mathrm{μ}=437$days.

Population of standard deviation,$\mathrm{σ}=399$days.

The sample size is$n=4$.

Assume the sample mean time between two earthquakes is denoted by $\overline{x}$.

Then, mean of role="math" localid="1652625040620" $$\begin{gathered} \overline{x}=\mathrm{μ} \\ =437days \end{gathered}$$

This mean, on an average we can expect that mean of the four times in the sample will be equal to 437 days since the mean of all possible sample mean is equal to population mean$\mathrm{μ}$.

Standard deviation of all possible mean ${\mathrm{σ}}_{\overline{x}}$,

$$\begin{gathered} =\frac{\mathrm{σ}}{\sqrt{n}} \\ =\frac{399}{\sqrt{4}} \\ =199.5days \end{gathered}$$

We can expect $Â\pm 3{\mathrm{σ}}_{\overline{x}}$variation from the mean of $\overline{x}$, i.e., from population mean $\mathrm{μ}$.

That is expected amount of variation from,

$$\begin{gathered} \overline{x}=Â\pm 3{\mathrm{σ}}_{\overline{x}} \\ =Â\pm 3\frac{\mathrm{σ}}{\sqrt{n}} \\ =Â\pm 3×199.5 \\ =Â\pm 598.5 \end{gathered}$$