91Ó°ÊÓ

The given statement is:

In Exercise 1.49 on page 16, you used simple random sampling to obtain a sample of 10 firms from Fortune Magazine's list of "The International 500."

First, divide the population size by the sample size and then round off the result to the nearest whole number(m).

In this case, the population size is 500.

and the sample size is 10.

$$\begin{gathered} m=\frac{500}{10} \\ =50 \end{gathered}$$

Now select the numbers k, k + m,...., k + 4m to generate the sample.

$$\begin{gathered} k=37 \\ k+m=37+50 \\ =87 \\ k+2m=37+2\left(50\right) \\ =137 \\ k+3m=37+3\left(50\right) \\ =187 \\ k+4m=37+4\left(50\right) \\ =237 \\ k+5m=37+5\left(50\right) \\ =287 \\ k+6m=37+6\left(50\right) \\ =337 \\ k+7m=37+7\left(50\right) \\ =387 \\ k+8m=37+8\left(50\right) \\ =437 \\ k+9m=37+9\left(50\right) \\ =487 \end{gathered}$$

The sample is 37, 87, 137, 187, 237, 287, 337, 387, 437, and 487.

Systematic random sampling is much easier to conduct if we compare it with simple random sampling.

The reason being there are some disadvantages to simple random sampling. That is, in some cases, it does not provide enough information about the subpopulations.

Furthermore, when the population members are dispersed, making this method of sample collection is impractical.

If the sample is not linked to the size of sales that are not in the United States, systematic sampling would apply.

However, in this case, the ranking is based on sales.

When the value of $k=2$is low, the sample will comprise enterprises with higher sales outside of the United States than the population as a whole.

When the value of $k=49$is high, the sample would, on average, contain firms with lower sales than the population as a whole.

In both circumstances, the sample would not be typical of the population in terms of sales outside the United States.