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Chapter 5: Q 12. (page 246)

A and B are events such that P(A)=0.2,P(B)=0.6,andP(A&B)=0.1. FindP(AorB).

Short Answer

Expert verified

PAorB=0.7

Step by step solution

01

Step 1. Given information.

The given statement is:

A and B are events such that P(A)=0.2,P(B)=0.6,andP(A&B)=0.1.

02

Step 2. Find P(A or B).

If there are two events Aand Bthen the probability of either A, B, or both occurring is P(A or B), and the likelihood of both A and Boccurring is P(A & B).

Therefore, the probability of events A and B are mutually exclusive will become:

PAorB=PA+PB-PA&B=0.2+0.6-0.1=0.7

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Most popular questions from this chapter

In Exercises 5.16-5.26, express your probability answers as a decimal rounded to three places.

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n=6,p=0.5,P(X=4)
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