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The given statement is:

Preeclampsia is a medical condition characterized by high blood pressure and protein in the urine of a pregnant woman. It is a serious condition that can be life-threatening to the mother and child. In the article "Women's Experiences Preeclampsia: Australian Action on Preeclampsia Survey of Wom and Their Confidants", C. East et al. examined the experiences of 68 women with preeclampsia.

The following table provides a frequency distribution of instances of prenatal or infant death for infants of women with preeclampsia.

We know that an event's probability ranges from 0 to 1, and both 0 and 1 are included in it.

The formula for the probability of an event is:

$P\left(E\right)=\frac{No.offavorableoutcomes}{Totalno.ofoutcomes}$

A total of 68 women were examined with preeclampsia. Therefore, the total number of instances will become 68.

The total instances where a child dies is:

$9+4+3+1+1=18$

Let's call the occurrence 'E' the death of the woman's child.

The probability that the child of the woman selected died is:

$$\begin{gathered} p\left(E\right)=\frac{18}{68} \\ =0.265 \end{gathered}$$

The total instances where a child dies one week to six months after birth are:

$4+3+1=8$

Now Let's call the occurrence 'E' the death of the woman's child from week one to six months after birth.

The probability that the child of the woman selected died one week to six months after birth is:

$$\begin{gathered} P\left(E\right)=\frac{8}{68} \\ =0.118 \end{gathered}$$

The total instances where a child lived at least six weeks are:

$1+1+50=52$

Now Let's call the occurrence 'E' the child that lived at least six weeks.

The probability that the child of the woman selected lived at least six weeks is:

$$\begin{gathered} P\left(E\right)=\frac{52}{68} \\ =0.765 \end{gathered}$$