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In exercise 10.117-10.122, the null hypothesis is H0:μ1=μ2and the alternative hypothesis is as specified. we have provided data from a simple random paired sample from the two population under consideration. in each case, use the paired ttest to perform the required hypothesis test at the 10%significance level.

Hα:μ1>μ2

Short Answer

Expert verified

The null hypothesis is rejected.

Step by step solution

01

Given Information

Given in the question that,

H0:μ1=μ2Hα:μ1>μ2

Level of significance is 0.1we have to determine the paired tt-test for the given values.

02

Explanation

Let's compute the sample mean as follow:

d¯=∑dn=1810=1.8

Calculate the standard deviation :

sd=∑di2-∑di2nn-1=138-(18)21010-1=3.4254

The formula of test statistics is

t=d¯sdn

Substitute the given values

t=1.83.425410=1.66

The value of degree of freedom is:

dof=n-1=10-9=1

The critical value for the level of significance 0.1is1.383

The value of test statistic is fall in the rejection region.

Therefore, the null hypothesis is rejected.

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Most popular questions from this chapter

Two-Tailed Hypothesis Tests and CIs. As we mentioned on page 413, the following relationship holds between hypothesis tests and confidence intervals: For a two-tailed hypothesis test at the significance level α, the null hypothesis H0:μ1=μ2will be rejected in favor of the alternative hypothesis Ha:μ1≠μ2if and only if the ( 1-α)-level confidence interval for μ1-μ2does not contain 0. In each case, illustrate the preceding relationship by comparing the reults of the hypothesis test and confidence interval in the specified xercises.

a. Exercises 10.48 and 10.54.

b. Exercises 10.49 and 10.55.

Stressed-Out Bus Drivers. An intervention program designed by the Stockholm Transit District was implemented to improve the work conditions of the city's bus drivers. Improvements were evaluated by G. Evans et al., who collected physiological and psychological data for bus drivers who drove on the improved routes (intervention) and for drivers who were assigned the normal routes (control). Their findings were published in the article "Hassles on the Job: A Study of a Job Intervention with Urban Bus Drivers" (Journal of Organizational Behavior, Vol. 20, pp. 199-208). Following are data, based on the results of the study, for the heart rates, in beats per minute, of the intervention and control drivers.

a. At the 5%significance level, do the data provide sufficient evidence to conclude that the intervention program reduces mean heart rate of urban bus drivers in Stockholm? (Note; x1=67.90, s1=5.49,x¯2=66.81and s2=9.04.

b. Can you provide an explanation for the somewhat surprising results of the study?

c. Is the study a designed experiment or an observational study? plain your answer.

The sample standard deviations are 23.6 and 59.2.

In this Exercise, we have provided summary statistics for independent simple random samples from two populations. In each case, use the pooled t-lest and the pooled t-interval procedure to conduct the required hypothesis test and obtain the specified confidence interval.

x¯1=20,s1=4,n1=10,x¯2=18,s2=5,n2=15

a. Right-tailed test,α=0.05

b. 90%confidence interval

In each of Exercises 10.35-10.38, we have provided summary statistics for independent simple random samples from two populations. Preliminary data analyses indicate that the variable under consideration is normally distributed on each population. Decide, in each case, whether use of the pooled t-lest and pooled t-interval procedure is reasonable. Explain your answer.
10.35 x¯1=468.3,s1=38.2,n1=6

x2=394.6,s2=84.7,n2=14

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