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Chapter 10: Q.10.71 (page 427)

The sample standard deviations are 23.6 and 59.2.

Short Answer

Expert verified

A non-pooled t test should be utilised.

Step by step solution

01

Given Information

The population standard deviations are 23.6 and 59.2.

02

Explanation

The selected sample should be a simple random sample from two populations, according to the assumptions of the pooling ttest.

  • Each sample is separate from the others.
  • The population is in the middle of the range.
  • The standard deviations of the population are all the same.

The non-pooled tassumption is that the sample chosen should be a simple random sampling from two populations.

  • Each sample is distinct from the others.
  • The population is average.
  • There is a significant sample size.

The two standard deviation values are not identical in the current circumstance.

For a non-pooled ttest, this is the assumption.

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Most popular questions from this chapter

In each of Exercises 10.35-10.38, we have provided summary statistics for independent simple random samples from two populations. Preliminary data analyses indicate that the variable under consideration is normally distributed on each population. Decide, in each case, whether use of the pooled t-lest and pooled t-interval procedure is reasonable. Explain your answer.
10.37 x炉1=118,s1=12.04,n1=99
x2=110,s2=11.25,n2=80

A variable of two population has a mean of 40and standard deviation of 12for one of the population and a mean of 40and a standard deviation of 6 for the other population.

a. For independent samples of sizes 9and4respectively find the mean and standard deviation of x1-x2

b. Must the variable under consideration be normally distributed on each of the two population for you to answer part (a) ? Explain your answer.

b. Can you conclude that the variable x1-x2is normally distributed? Explain your answer.

H2*渭1鈮�渭2

The primary concern is deciding whether the mean of Population 1 differs from the mean of Population 2 .

The primary concern is deciding whether the mean of Population 1 is greater than the mean of Population 2
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