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Chapter 10: Q. 11 (page 446)

Ecosystem Response. Refer to Problem 10, and find a 90% confidence interval for the difference in the mean lengths of time that ice stays on the two lakes. Interpret your result.

Short Answer

Expert verified

(-3.3752,6.1252)

Step by step solution

01

Given Information

n=Sample Size =8

c=Confidence level =90%=0.90

02

Explanation

Here, the difference among each pair of values is needed to be calculated as follows:

d炉=Sample Mean=12+7+1+0-11+0-11+0+6-48鈮�1.375

Sd=Sample standard deviation

=(12-1375)2+鈥�+(-4-1.375)28-1鈮�7.09

Calculate the critical value with df=n-1=8-1=7

t*=1.895

Then, the margin of error is

E=t*脳sdn=1.895脳7.098鈮�4.7502

The confidence interval's endpoints are:

d炉-E=1.375-4.7502=-3.3752

d炉+E=1.375+4.7502=6.1252

It can be said with 90%confidence that the difference in mean length of time that ice stays on the Mendota lake is between 3.3752days lesser and 6.1252days greater than the mean length of time that ice stays on the Monona lake.

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Most popular questions from this chapter

The sample standard deviations are 23.6 and 59.2.

The primary concern is deciding whether the mean of Population 1 is less than the mean of Population 2.

A variable of two populations has a mean of 7.9and a standard deviation of 5.4for one of the populations and a mean of 7.1and a standard deviation of 4.6for the other population. Moreover. the variable is normally distributed in each of the two populations.

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