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Chapter 10: Q. 10.92 (page 429)

Wing Length. Refer to Exercise 10.86 and find a 999 con fidence interval for the difference between the mean wing lengths o the two subspecies.

Short Answer

Expert verified

The interval is -4.488 to -1.111

Step by step solution

01

Given Information.

We have to consider the given table to find the answer :

02

Step 2:Explanation 

For a confidence interval of 99%

df=s12n1+s22n22s12n12x22n22

=1.5012142+1.69821421.501214214-1+1.698214214-1

=25

The interval's end point is:

x炉1-x炉2卤ta2路s12n1+s22n2=(82.1-84.9)卤2.7871.501214+1.698214

=-4.488to-1.111

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Most popular questions from this chapter

H2:渭1<渭2

The sample standard deviations are 23.6 and 25.2, and each sample size is 25 .

The Federal Bureau of Prisons publishes data in Prison Statistics on the times served by prisoners released from federal institutions for the first time. Independent random samples of released prisoners in the fraud and firearms offense categories yielded the following information on time served, in months.

At the 5% significance level, do the data provide sufficient evidence to conclude that the meantime served for fraud is less than that for firearms offenses? (Note: x炉1=10.12,s1=4.90,x炉2=18.78, and s2=4.64.)

Discuss the relative advantages and disadvantages of using pooled and non pooled -procedures.

Two-Tailed Hypothesis Tests and CIs. As we mentioned on page 413, the following relationship holds between hypothesis tests and confidence intervals: For a two-tailed hypothesis test at the significance level 伪, the null hypothesis H0:渭1=渭2 will be rejected in favor of the alternative hypothesis H2:渭1鈮�渭2 if and only if the (1-伪)-level confidence interval for 渭1-渭2 does not contain 0. In each case, illustrate the preceding relationship by comparing the results of the hypothesis test and confidence interval in the specified exercises.

a. Exercises 10.81 and 10.87

b. Excrcises 10.86 and 10.92
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