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Two-Tailed Hypothesis Tests and CIs. As we mentioned on page 413, the following relationship holds between hypothesis tests and confidence intervals: For a two-tailed hypothesis test at the significance level α, the null hypothesis H0:μ1=μ2 will be rejected in favor of the alternative hypothesis H2:μ1≠μ2 if and only if the (1-α)-level confidence interval for μ1-μ2 does not contain 0. In each case, illustrate the preceding relationship by comparing the results of the hypothesis test and confidence interval in the specified exercises.

a. Exercises 10.81 and 10.87

b. Excrcises 10.86 and 10.92

Short Answer

Expert verified

a) 90%interval does not contain zero.

b)99%interval does not contain zero.

Step by step solution

01

Part (b) Step 1: Given Information

To discover a comparison of the results of the hypothesis test and the confidence interval.

02

Part(a) Step 2: Explanation

Consider the upper bound of a confidence interval of 90%. As a result, the 90% interval does not contain zero.

x¯1-x¯2±ta2·s12n1+s22n2=(25.8-22.1)±1.729·9.2232+5.7220

=0.1274to7.2726

As a result, it is possible to conclude that there is a difference in the mean age at arrest of East German prisoners with chronic PTSD versus those with remitted PTSD.

03

Part (a) Step 1: Given Information

To discover a comparison of the results of the hypothesis test and the confidence interval.

04

Part(b) Step 2: Explanation 

Think about the data.

Consider the 99%upper bound for a confidence interval.

x¯1-x¯2±ta2·s12n1+s22n2=(82.1-84.9)±3.012

1.501214+1.698214

=-4.6244to-0.9756

As a result, the 99%interval does not equal zero. As a result, it is possible to conclude that the mean wing length of the two species differs.

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Most popular questions from this chapter

In each of exercise 10.13-10.18, we have presented a confidence interval for the difference,μ1-μ2, between two population means. interpret each confidence interval

99%CI from-20to15

In this section, we introduced the pooled t-test, which provides a method for comparing two population means. In deriving the pooled f-test, we stated that the variable

z=f^1-x^2-μ1-μ2σ1/n1+1/n2

cannot be used as a basis for the required test statistic because σ is unknown. Why can't that variable be used as a basis for the required test statistic?

Suppose that you want to perform a hypothesis test to compare the means of two populations, using a paired sample. For each part, decide whether you would use the pairedt -test, the paired Wilcoxon signed-rank test, or neither of these tests if preliminary data analyses of the sample of paired differences suggest that the distribution of the paired-difference variable is

a. approximately normal.

b. highly skewed; the sample size is 20.

c. symmetric bimodal.

Faculty Salaries. Suppose, for Example10.2, you want to decide whether the mean salary of faculty in private institutions is less than the mean salary of faculty in public institutions. State the null and alternative hypotheses for that hypothesis test.

A variable of two populations has a mean of 7.9and a standard deviation of 5.4for one of the populations and a mean of 7.1and a standard deviation of 4.6for the other population. Moreover. the variable is normally distributed in each of the two populations.

a. For independent samples of sizes 3and 6, respectively, determine the mean and standard deviation of x1-x2.

b. Can you conclude that the variable x1-x2is normally distributed? Explain your answer.

c. Determine the percentage of all pairs of independent samples of sizes 4and 16, respectively, from the two populations with the property that the differencex1-x2 between the simple means is between -3and 4.

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