/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 12.89 Job Satisfaction. A CNN/USA TODA... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Job Satisfaction. A CNN/USA TODAY poll conducted by Gallul asked a sample of employed Americans the following question: "Which do you enjoy more, the hours when you are on your job, or the hours when you are not on your job?" The responses to this question were cross-tabulated against several characteristics, among which were gender, age, type of community, educational attainment, income, and type of employer. The data are provided on the WeissStats site. In each of Exercises 12.87-12.92, use the technology of your choice to decide, at the 5%significance level, whether an association exists between the specified pair of variables.

type of community and response

Short Answer

Expert verified

There is no association exists between type of community and response at the 5% significance level.

Step by step solution

01

Step 1. Given  information

Given significance level=5%

The given specified pair of variables.= type of community and response

02

Step 2. Check whether there is an association exists between the specified pair of variables or not. 

The hypotheses are given below:
Null hypothesis:
H0 : There is no association exists between type of community and response.
Alternative hypothesis:
H1 : There is an association exists between type of community and response.

03

Step 3. Use MINITAB to obtain the test statistic and p-value.

MINITAB procedure:
Step 1: Choose Stat > Tables>Chi-Square test for association.
Step 2: In Columns containing the table, enter the column of Male and Female.
Step 3: In Rows, select Response.
Step 4: Under Statistics, select Chi-square test, Display counts in each cell, Display marginal counts and expected cell counts.
Step 5: Click OK.

04

Step 4. Finding MINITAB output

Chi-Square Test for Association: RESPONSE, Worksheet columns

From the MINITAB output,the value of the chi-square statistic is6.952 and the p-value is0.138

05

Step 5. Finding the conclusion for above problem

Here, theP-value is greater than the level of significance.
That is, P-value =0.138)>α(=0.05.
Therefore, the null hypothesis is not rejected at5%level.
Thus, there is no association exists between type of community and response at the 5% significance level.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The t-table has entries for areas of 0.10,0.05,0.025,0.01and0.005. In contrast, the χ2-table has entries for those areas and for 0.995,0.99,0.975,0.95and 0.90.Explain why the t-values corresponding to these additional areas can be obtained from the existing t-table but must be provided explicitly in the χ2-table.

AIDS Cases. According to the Centers for Disease Control and Prevention publication HIV Surveillance Report, the number of AIDS cases in the United States in 2011, by region and race, is as shown in the following contingency table.

RegionWhiteBlackOtherTotal
Northeast1,1002,493
5,177
Northwest1,137
5043221
South2,7617,848
12,867
West
76417664,230
Total

605225,435

a. How many cells does this contingency table have?

b. Fill in the missing entries.

c. What was the total number of AIDS cases in the United States in 2011?

d. How many AIDS cases were whites?

e. How many AIDS cases were Southerners?

f. How many AIDS cases were black Westerners?

Presidential Election. According to Dave Leip's Atlas of U.S. Presidential Elections, in the 2012 presidential election, 51.01%of those voting voted for the Democratic candidate (Barack H. Obama), whereas 57.50%of those voting who lived in Illinois did so. For that presidential election, does an association exist between the variables "party of presidential candidate voted for" and "state of residence" for those who voted? Explain your answer.

State the null and alternative hypotheses for a chi-square homogeneity test
a. without using the terms homogeneous and nonhomogeneous.
b. using the terms homogeneous and nonhomogeneous

Freshmen Politics. The Higher Education Research Institute of the University of California, Los Angeles, publishes information on the characteristics of incoming college freshmen in The American Freshman. Incoming freshmen characterized their political views as liberal, as moderate, and as conservative, For this year, a random sample of 500 incoming college freshmen yielded the following frequency distribution for political views. Freshmen Politics. The Higher Education Research Institute of the University of California, Los Angeles, publishes information on the characteristics of incoming college freshmen in The American Freshman. Incoming freshmen characterized their political views as liberal, as moderate, and as conservative, For this year, a random sample of 500 incoming college freshmen yielded the following frequency distribution for political views.

Political view

Frequency

Liberal

147

Moderate

237

Conservative

116

a. Identify the population and variable under consideration here.

b. At the 55 significance level, do the data provide sufficient evidence to conclude that this year's distribution of political views for incoming college freshmen has changed from the 2000 distribution?

c. Repeat part (b), using a significance level of.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.