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Chapter 13: Q.13.40 (page 542)

Fill in the missing entries in the partially completed one-way ANOVA tables.

Short Answer

Expert verified

The completed ANOVA table is

sourcedfSSMS=SS/dfF=statisticTreatment437.849.461.464error20135.206.76total24173.04

Step by step solution

01

Given Information

Given data:

02

Explanation

Determine the total number of degrees of freedom. totaldf=errordf+treatmentdf

=20+4

=24

MSE (mean square error):

MSE=SSEn-k

SSE=MSE(n-k)

=6.76(20)

=135.2

03

Explanation

Calculate the treatment's mean squares:

MSTR=SSTRk-1

=37.844

鈬�MSTR=9.46

k-1=3

Look for theF-static.

F-statistic=MSTRMSE

=9.466.76

=1.464

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Most popular questions from this chapter

Suppose that you want to compare the means of three populations by using one-way ANOVA. If the sample sizes are 5, 6, and 6, determine the degrees of freedom for the appropriate F-curve.

We have provided data from independent simple random samples from several populations. In each case, determine the following items.

a. SSTR

b. MSTR

c. SSE

d. MSE

e. F

Consider a F-curve with df=(2,14)

DetermineF0.05.

A study by E. Anionwu et al. published as the paper "Sickle Cell Disease in a British Urban Community", measured the steady-state hemoglobin levels of patients with three different types of sickle cell disease: HB SS, HB ST and HB SC. The data are presented on the WeissStats site.

a. Obtain individual normal probability plots and the standard deviations of the sample.

b. Perform a residual analysis

c. use your results from part (a) and (b) to decide whether conducting a one-way ANOVA test on the data is reasonable. If so, also do parts (d) and (e).

d. use a one-way ANOVA test to decide, at the\(5%\) significance level whether, the data provide sufficient evidence to conclude that a difference exists among the means of the populations from which the samples were taken.

e. Interpret your results from part (d).

An F-curve has df=(12,5). In each case, find the F-value having the specified area to its right.

a.0.01

b.0.05

c.0.005
See all solutions

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