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Chapter 13: Q.13.40 (page 542)

Fill in the missing entries in the partially completed one-way ANOVA tables.

Short Answer

Expert verified

The completed ANOVA table is

sourcedfSSMS=SS/dfF=statisticTreatment437.849.461.464error20135.206.76total24173.04

Step by step solution

01

Given Information

Given data:

02

Explanation

Determine the total number of degrees of freedom. totaldf=errordf+treatmentdf

=20+4

=24

MSE (mean square error):

MSE=SSEn-k

SSE=MSE(n-k)

=6.76(20)

=135.2

03

Explanation

Calculate the treatment's mean squares:

MSTR=SSTRk-1

=37.844

鈬�MSTR=9.46

k-1=3

Look for theF-static.

F-statistic=MSTRMSE

=9.466.76

=1.464

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Most popular questions from this chapter

13.19 What does the term one-way signify in the phrase one-wayANOVA?

An F-curve has df =(12,7). What is the number of degrees of freedom for the

a. numerator?

b. denominator?

Fill in the missing entries in the partially completed one-way ANOVA tables.

State the four assumptions for one-way ANOVA, and explain how those assumptions can be checked.

We stated earlier that a one-way ANOVA test is always right-tailed because the null hypothesis is rejected only when the test statistic, F, is too large. Why is the null hypothesis rejected only when F is too large?
See all solutions

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