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Chapter 13: Q.13.38 (page 542)

Fill in the missing entries in the partially completed one-way ANOVA tables.

Short Answer

Expert verified

The completed ANOVA table is

sourcedfSSMS=SS/dfF=statisticTreatment243.30421.6523.709error1284.4007.033total14127.704

Step by step solution

01

Given Information

Given data:

02

Explanation

The degrees of freedom of the error is

errordf=totaldf-treatmentdf

=14-2

=12

SSTR (sum of squares treatment):

MSTR=SSTRk-1

SSTR=MSTR(k-1)

=21.562(2)

=43.304

03

Explanation

Calculate the error mean squares MSE:

MSE=SSEn-k

=84.40012

=7.033

Calculate the F-statistic:

F-statistics=MSTRMSE

=21.6527.033

=3.079

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Most popular questions from this chapter

An F-curve has df =(12,7). What is the number of degrees of freedom for the

a. numerator?

b. denominator?

Fill in the missing entries in the partially completed one-way ANOVA tables.

13.19 What does the term one-way signify in the phrase one-wayANOVA?

We stated earlier that a one-way ANOVA test is always right-tailed because the null hypothesis is rejected only when the test statistic, F, is too large. Why is the null hypothesis rejected only when F is too large?

State the four assumptions for one-way ANOVA, and explain how those assumptions can be checked.
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