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Control Charts for p. In Exercises 5鈥12, use the given process data to construct a control chart for p. In each case, use the three out-of-control criteria listed near the beginning of this section and determine whether the process is within statistical control. If it is not, identify which of the three out-of-control criteria apply

Cola Cans In each of several consecutive days of production of cola cans, 50 cans are tested and the numbers of defects each day are listed below. Do the proportions of defects appear to be acceptable? What action should be taken?

8 7 9 8 10 6 5 7 9 12 9 6 8 7 9 8 11 10 9 7

Short Answer

Expert verified

The following p chart is constructed for the given number of defects:

None of the features in the chart indicates that the process is unstable.

But the values of the proportions of defectives seem to be very high.

As a result, the producer must respond quickly to improve the quality of goods produced.

Step by step solution

01

Given information

Data are given on the number of defects in 20 randomly selected samples.

The size of each sample is 50.

02

Important values of p chart

Let\(\bar p\)be the estimated proportion of defective cans in all samples.

It is computed as follows:

\(\begin{array}{c}\bar p = \frac{{{\rm{Total}}\;{\rm{number}}\;{\rm{of}}\;{\rm{defectives}}\;{\rm{from}}\;{\rm{all}}\;{\rm{samples}}\;{\rm{combined}}}}{{{\rm{Total}}\;{\rm{number}}\;{\rm{of}}\;{\rm{observations}}}}\\ = \frac{{8 + 7 + 9 + ..... + 7}}{{20\left( {50} \right)}}\\ = \frac{{165}}{{1000}}\\ = 0.165\end{array}\)

The value of\(\bar q\)is computed as shown:

\(\begin{array}{c}\bar q = 1 - 0.165\\ = 0.835\end{array}\)

The value of the lower control limit (LCL) is computed below:

\(\begin{array}{c}LCL = \bar p - 3\sqrt {\frac{{\bar p\bar q}}{n}} \\ = 0.165 - 3\sqrt {\frac{{\left( {0.165} \right)\left( {0.835} \right)}}{{50}}} \\ = 0.0075\end{array}\)

The value of the upper control limit (UCL) is computed below:

\(\begin{array}{c}UCL = \bar p + 3\sqrt {\frac{{\bar p\bar q}}{n}} \\ = 0.165 + 3\sqrt {\frac{{\left( {0.165} \right)\left( {0.835} \right)}}{{50}}} \\ = 0.3225\end{array}\)

03

Computation of the fraction defective

The sample fraction defective for the ith batch can be computed as:

\({p_i} = \frac{{{d_i}}}{{50}}\)

Here,

\({p_i}\)is the sample fraction defective for the ith batch, and

\({d_i}\)is the number of defective orders in the ith batch.

The computation of fraction defective for the ith batch is given as follows:

S.No.

Defectives (d)

Sample fraction defective (p)

1

8

0.16

2

7

0.14

3

9

0.18

4

8

0.16

5

10

0.20

6

6

0.12

7

5

0.10

8

7

0.14

9

9

0.18

10

12

0.24

11

9

0.18

12

6

0.12

13

8

0.16

14

7

0.14

15

9

0.18

16

8

0.16

17

11

0.22

18

10

0.20

19

9

0.18

20

7

0.14

04

Construction of the p chart

Follow the given steps to construct the p chart:

  • Mark the values 2, 4, ...,20on the horizontal axis and label it 鈥淪ample.鈥
  • Mark the values 0.00, 0.05, 0.10, 鈥︹, 0.35 on the vertical axis and label it 鈥淧roportion.鈥
  • Plot a straight line corresponding to the value 0.165 on the vertical axis and label it (on the left side) 鈥淺(\bar P\;or\;\bar p = 0.165\).鈥
  • Plot a horizontal line corresponding to the value 0.0075 on the vertical axis and label it 鈥淟CL=0.0075.鈥
  • Similarly, plot a horizontal line corresponding to the value 0.3225 on the vertical axis and label it 鈥淯CL=0.3225.鈥
  • Mark all 20 sample points (fraction defective of the ith lot) on the graph and join the dots using straight lines.

The following p chart is obtained:

05

Analysis of the p chart

The chart has no feature that indicates the violation of the stability of the process. Thus, the process is within statistical control.

But the values of the proportions of defectives seem to be very high.

Thus, the manufacturer should take quick action to correct the quality of the goods produced.

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Most popular questions from this chapter

Defective Child Restraint Systems The Tracolyte Manufacturing Company produces plastic frames used for child booster seats in cars. During each week of production, 120 frames are selected and tested for conformance to all regulations by the Department of Transportation. Frames are considered defective if they do not meet all requirements. Listed below are the numbers of defective frames among the 120 that are tested each week. Use a control chart for p to verify that the process is within statistical control. If it is not in control, explain why it is not.

3 2 4 6 5 9 7 10 12 15

Quarters. In Exercises 9鈥12, refer to the accompanying table of weights (grams) of quarters minted by the U.S. government. This table is available for download at www.TriolaStats.com.

Day

Hour 1

Hour 2

Hour 3

Hour 4

Hour 5

\(\bar x\)

s

Range

1

5.543

5.698

5.605

5.653

5.668

5.6334

0.0607

0.155

2

5.585

5.692

5.771

5.718

5.72

5.6972

0.0689

0.186

3

5.752

5.636

5.66

5.68

5.565

5.6586

0.0679

0.187

4

5.697

5.613

5.575

5.615

5.646

5.6292

0.0455

0.122

5

5.63

5.77

5.713

5.649

5.65

5.6824

0.0581

0.14

6

5.807

5.647

5.756

5.677

5.761

5.7296

0.0657

0.16

7

5.686

5.691

5.715

5.748

5.688

5.7056

0.0264

0.062

8

5.681

5.699

5.767

5.736

5.752

5.727

0.0361

0.086

9

5.552

5.659

5.77

5.594

5.607

5.6364

0.0839

0.218

10

5.818

5.655

5.66

5.662

5.7

5.699

0.0689

0.163

11

5.693

5.692

5.625

5.75

5.757

5.7034

0.0535

0.132

12

5.637

5.628

5.646

5.667

5.603

5.6362

0.0235

0.064

13

5.634

5.778

5.638

5.689

5.702

5.6882

0.0586

0.144

14

5.664

5.655

5.727

5.637

5.667

5.67

0.0339

0.09

15

5.664

5.695

5.677

5.689

5.757

5.6964

0.0359

0.093

16

5.707

5.89

5.598

5.724

5.635

5.7108

0.1127

0.292

17

5.697

5.593

5.78

5.745

5.47

5.657

0.126

0.31

18

6.002

5.898

5.669

5.957

5.583

5.8218

0.185

0.419

19

6.017

5.613

5.596

5.534

5.795

5.711

0.1968

0.483

20

5.671

6.223

5.621

5.783

5.787

5.817

0.238

0.602

Quarters: Run Chart Treat the 100 consecutive measurements from the 20 days as individual values and construct a run chart. What does the result suggest?

Listed below are annual sunspot numbers paired with annual high values of the Dow Jones Industrial Average (DJIA). Sunspot numbers are measures of dark spots on the sun, and the DJIA is an index that measures the value of select stocks. The data are from recent and consecutive years. Use a 0.05 significance level to test for a linear correlation between values of the DJIA and sunspot numbers. Is the result surprising?

Sunspot

DJIA

45

10941

31

12464

46

14198

31

13279

50

10580

48

11625

56

12929

38

13589

65

16577

51

18054

In Exercises 5鈥8, use the following two control charts that result from testing batches of newly manufactured aircraft altimeters, with 100 in each batch. The original sample values are errors (in feet) obtained when the altimeters are tested in a pressure chamber that simulates an altitude of 6000 ft. The Federal Aviation Administration requires an error of no more than 40 ft at that altitude.

What is the value of\(\bar \bar x\)? In general, how is a value of\(\bar \bar x\)found?

Control Charts for p. In Exercises 5鈥12, use the given process data to construct a control chart for p. In each case, use the three out-of-control criteria listed near the beginning of this section and determine whether the process is within statistical control. If it is not, identify which of the three out-of-control criteria apply

Euro Coins Repeat Exercise 5, assuming that the size of each batch is 100 instead of 10,000. Compare the control chart to the one found for Exercise 5. Comment on the general quality of the manufacturing process described in Exercise 5 compared to the manufacturing process described in this exercise.

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