/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q5 Identifying Probability Values W... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 4: Q5 (page 143)

Identifying Probability Values Which of the following are probabilities?

0 3/5 5/3 -0.25 250% 7:3 1 50-50 5:1 0.135 2.017

Short Answer

Expert verified

The probability values are 0, 35, 1, and 0.135.

Step by step solution

01

Given information

Numerical values are provided. The possible probability values need to be identified.

02

Probability

Probabilityis the chance that a particular event will happen or not.

The value for measures ranges from 0 to 1. The value of the probability can never be negative.It is because a favourable number of outcomes can never exceed total and the counts of outcomes cannot be negative.

03

Identifying probability values

The following numbers are classified whether they can be a probability value or not:

  • 0: Probability ranges from 0 to 1 (inclusive). Thus, 0 can be a probability value.
  • 35is a proper fraction. Its value lies between 0 and 1. Thus, 35can be a probability value.
  • 53is an improper fraction. Its value is greater than 1. Thus, 53cannot be a probability value.
  • -0.25 is a negative value. Probability can never be negative. Thus, -0.25 cannot be a probability value.
  • 250%=250100=2.5

250% is greater than 1. Thus, it cannot be a probability value.

  • 7:3can be written as 73. As73 is an improper fraction, its value is greater than 1. Thus, it cannot be a probability value.
  • 1: Probability lies between 0 to 1 (inclusive). Thus, 1 can be a probability value.
  • 50-50is not a numeric value that lies between 0 and 1. Thus, cannot be a probability value.
  • 5:1can be written as 51. As51 is an improper fraction, its value is greater than 1. Thus, it cannot be a probability value.
  • 0.135 lies between 0 and 1. Thus, it can be a probability value.
  • 2.017 is greater than 1. Thus, it cannot be a probability value.

Therefore, the values 0,35 , 1, and 0.135 are probabilities.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Exercises 13鈥�20, express the indicated degree of likelihood as a probability value between 0 and 1.

Randomness When using a computer to randomly generate the last digit of a phone number to be called for a survey, there is 1 chance in 10 that the last digit is zero

In Exercises 5鈥�36, express all probabilities as fractions.

Scheduling Routes A presidential candidate plans to begin her campaign by visiting the capitals of 5 of the 50 states. If the five capitals are randomly selected without replacement, what is the probability that the route is Sacramento, Albany, Juneau, Hartford, and Bismarck, in that order?

At Least One. In Exercises 5鈥�12, find the probability.

Probability of a Girl Assuming that boys and girls are equally likely, find the probability of a couple having a boy when their third child is born, given that the first two children were both girls.

If a month is randomly selected after mixing the pages from a calendar, what is the probability that it is a month containing the letter y?

ATM You want to obtain cash by using an ATM, but it鈥檚 dark and you can鈥檛 see your card when you insert it. The card must be inserted with the front side up and the printing configured so that the beginning of your name enters first.

a. What is the probability of selecting a random position and inserting the card with the result that the card is inserted correctly?

b. What is the probability of randomly selecting the card鈥檚 position and finding that it is incorrectly inserted on the first attempt, but it is correctly inserted on the second attempt? (Assume that the same position used for the first attempt could also be used for the second attempt.)

c. How many random selections are required to be absolutely sure that the card works because it is inserted correctly?
See all solutions

Recommended explanations on Math Textbooks

Mechanics Maths

Read Explanation

Geometry

Read Explanation

Decision Maths

Read Explanation

Discrete Mathematics

Read Explanation

Theoretical and Mathematical Physics

Read Explanation

Pure Maths

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.