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Critical Thinking: Interpreting results from a test for smoking It is estimated that roughly half of smokers lie when asked about their smoking involvement. Pulse CO-oximeters may be a way to get information about smoking without relying on patients鈥� statements. Pulse CO-oximeters use light that shines through a fingernail, and it measures carbon monoxide in blood. These devices are used by firemen and emergency departments to detect carbon monoxide poisoning, but they can also be used to identify smokers. The accompanying table lists results from people aged 18鈥�44 when the pulse CO-oximeter is set to detect a 6% or higher level of carboxyhemoglobin (based on data from 鈥淐arbon Monoxide Test Can Be Used to Identify Smoker,鈥� by Patrice Wendling, Internal Medicine News, Vol. 40., No. 1, and Centers for Disease Control and Prevention).

CO-Oximetry Test for Smoking

	PositiveTest Result	Negative Test Result
Smoker	49	57
Non-smoker	24	370

Analyzing the Results

False Negative Based on the results in the table, find the probability that a subject smokes, given that the test result is negative.

Step by step solution

01

Given information

The given table summarizes the test results for smoking.

CO-Oximetry test for smoking

	Positive test result	Negative test result
Smoker	49	57
Non-smoker	24	370

02

State the formula of conditional probability

Conditional probability of event B occurring, given that event A has already occurred.

$P\left(B\left|A\right.\right)=\frac{P\left(A\text{and B}\right)}{P\left(A\right)}鈥�...\left(1\right)$

03

Find the values of P(A and B) and P(A).

Let event A denotes negative test results and event B denotes that a subject is a smoker.

Total number of subjects are 500.

Using given information,

$$\begin{gathered} P\left(A\right)=\frac{\text{Number of subjects whose test result is negative}}{\text{Total number of subjects}} \\ =\frac{427}{500} \\ P\left(\text{A and B}\right)=\frac{\text{Number of subjects who are smoker and test result is negative}}{\text{Total number of subjects}} \\ =\frac{57}{500} \end{gathered}$$

04

Calculate conditional probability 

The false negative is described as the probability that the subject is a smoker, given that the test result is negative.

It is computed as,

$$\begin{gathered} P\left(B\left|A\right.\right)=\frac{P\left(\text{Subject is smoker and test result is negative}\right)}{\text{P}\left(\text{Test result is negative}\right)} \\ P\left(B\left|A\right.\right)=\frac{P\left(A\text{and B}\right)}{P\left(A\right)}...\left(1\right) \end{gathered}$$

Substituting the values in equation (1),

$$\begin{gathered} P\left(B\left|A\right.\right)=\frac{\frac{57}{500}}{\frac{427}{500}} \\ =0.133 \end{gathered}$$

Therefore, theprobability that a subject is a smoker, given that the test result is negative, is 0.133.

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