/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q29 Low Birth Weight The University ... [FREE SOLUTION] | 91影视

91影视

Low Birth Weight The University of Maryland Medical Center considers 鈥渓ow birth weights鈥 to be those that are less than 5.5 lb or 2495 g. Birth weights are normally distributed with a mean of 3152.0 g and a standard deviation of 693.4 g (based on Data Set 4 鈥淏irths鈥 in Appendix B).

a. If a birth weight is randomly selected, what is the probability that it is a 鈥渓ow birth weight鈥?

b. Find the weights considered to be significantly low, using the criterion of a birth weight having a probability of 0.05 or less.

c. Compare the results from parts (a) and (b).

Short Answer

Expert verified

a.The probability of Low birth weight is 0.1711.

b. The birth weight having a probability of 0.05 or less is 2011.4 g weight is considered significantly low.

c.The birth weights between 2011.4g and 2496g are considered 鈥渓ow birth weights鈥 but are not significantly low.

Step by step solution

01

Given information

Low birth weights are recognized as weights lesser than 5.5lb or 2495g.

The birth weights follow Normal distribution with a mean of 3152.0g and a standard deviation of 693.4g.

02

Describe the distribution of birth weights

a.

Let X be the random variable for birth weight which follows a normal distribution

X~N,2~N3152,693.42

03

Calculation for z score

The probability of birth weight lesser than 2495g can be expressed as follows:

PX<2495

The z score associated with the birth weights 2495 computed as:

z=x-=2495-3152.0693.4=-0.95

04

Calculate the probability of getting a low birth weight

The probability that weight is less than 2496gis expressed as:

PX<2495=PZ<-0.95...1)

From the standard normal table, the cumulative probability of z = -0.95 is obtained from the cell intersection of row value -0.9 and column value 0.05, which is 0.1711.

Thus,

PX<2496=0.1711

Thus, the probability of weight lesser than 2495 g is 0.1711.

05

Finding the weights considered to be significantly low

b.

Significantly low weights are all those birth weights that have the probability of lesser than 0.05 to appear.

That is,

PX<x0.05, where x is the maximum weight below which the weights are significantly low.

The probability of birth weight having a probability of 0.05 or less can be expressed as:

PX<x=PZ<z=0.05

From the standard normal table, the area of 0.05 is observed corresponding to the row value -1.6 and column value between 0.04 and 0.05, which implies the z score is -1.645.

Substitute the value of z as follows:

z=x-x=+z=3152-1.645693.4=2011.357

Therefore, all birth weights lesser than 2011.4 g are considered to be significantly low.

06

Comparing the results 

c.

The birth weights are significantly low if they are 2011.35 g or less, which have only a 5% chance to appear in the selection.

Also, birth weights lower than 2496 g are considered low birth rates with 17.11% chances to appear.

Thus, any weight that lies between 2011.5 g and 2496 g is recognized as low birth weight but actually is not significantly low (rare).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In Exercises 9鈥12, find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1.

In Exercises 9鈥12, find the area of the shaded region. The graph depicts the standard normal distribution of bone density scores with mean 0 and standard deviation 1.

SAT and ACT Tests Because they enable efficient procedures for evaluating answers, multiple choice questions are commonly used on standardized tests, such as the SAT or ACT.

Such questions typically have five choices, one of which is correct. Assume that you must make random guesses for two such questions. Assume that both questions have correct answers of 鈥渁.鈥

a. After listing the 25 different possible samples, find the proportion of correct answers in each sample, then construct a table that describes the sampling distribution of the sample proportions of correct responses.

b. Find the mean of the sampling distribution of the sample proportion.

c. Is the mean of the sampling distribution [from part (b)] equal to the population proportion of correct responses? Does the mean of the sampling distribution of proportions always equal the population proportion?

Unbiased Estimators Data Set 4 鈥淏irths鈥 in Appendix B includes birth weights of 400 babies. If we compute the values of sample statistics from that sample, which of the following statistics are unbiased estimators of the corresponding population parameters: sample mean; sample median; sample range; sample variance; sample standard deviation; sample proportion?

Sampling with Replacement The Orangetown Medical Research Center randomly selects 100 births in the United States each day, and the proportion of boys is recorded for each sample.

a. Do you think the births are randomly selected with replacement or without replacement?

b. Give two reasons why statistical methods tend to be based on the assumption that sampling is conducted with replacement, instead of without replacement.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.