/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q11-2BSC Cybersecurity When using the dat... [FREE SOLUTION] | 91影视

91影视

Cybersecurity When using the data from Exercise 1 to test for goodness-of-fit with the distribution described by Benford鈥檚 law, identify the null and alternative hypotheses.

Short Answer

Expert verified

The null hypothesis and the alternative hypothesis is

\(\begin{aligned}{l}{H_0}:{p_1} = 0.301,{p_2} = 0.176,{p_3} = 0.125,{p_4} = 0.097,{p_5} = 0.079,{p_6} = 0.067,{p_7} = 0.058,\\\;\;\;\;\;{p_8} = 0.051,{p_9} = 0.046\end{aligned}\)

\({H_1}:\)At least one of the proportions will differ from the others.

Step by step solution

01

Given information

The observed frequencies and the expected frequencies of the leading digits of inter-arrival traffic times are tabulated.

02

Identify the hypotheses

The following hypotheses are set up to test for the goodness of fit test of the given distribution:

Null Hypothesis:

The null hypothesis is that in which the proportions of all the leading digits should be equal to the claimed value.

\(\begin{aligned}{l}{H_0}:{p_1} = 0.301,{p_2} = 0.176,{p_3} = 0.125,{p_4} = 0.097,{p_5} = 0.079,{p_6} = 0.067,{p_7} = 0.058,\\\;\;\;\;\;{p_8} = 0.051,{p_9} = 0.046\end{aligned}\)

Alternative Hypothesis:

The alternative hypothesis is that in which at least one of the proportions should not be equal to the claimed value.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Questions 6鈥10 refer to the sample data in the following table, which describes the fate of the passengers and crew aboard the Titanic when it sank on April 15, 1912. Assume that the data are a sample from a large population and we want to use a 0.05 significance level to test the claim that surviving is independent of whether the person is a man, woman, boy, or girl.


Men

Women

Boys

Girls

Survived

332

318

29

27

Died

1360

104

35

18

Given that the P-value for the hypothesis test is 0.000 when rounded to three decimal places, what do you conclude? What do the results indicate about the rule that women and children should be the first to be saved?

One Big Bill or Many Smaller Bills In a study of the 鈥渄enomination effect,鈥 150 women in China were given either a single 100 yuan bill or a total of 100 yuan in smaller bills. The value of 100 yuan is about $15. The women were given the choice of spending the money on specific items or keeping the money. The results are summarized in the table below (based on 鈥淭he Denomination Effect,鈥 by Priya Raghubir and Joydeep Srivastava, Journal of Consumer Research, Vol. 36). Use a 0.05 significance level to test the claim that the form of the 100 yuan is independent of whether the money was spent. What does the result suggest about a denomination effect?

Spent the Money

Kept the Money

Women Given a Single 100-Yuan Bill

60

15

Women Given 100 Yuan in Smaller Bills

68

7

Flat Tire and Missed Class A classic story involves four carpooling students who missed a test and gave as an excuse a flat tire. On the makeup test, the instructor asked the students to identify the particular tire that went flat. If they really didn鈥檛 have a flat tire, would they be able to identify the same tire? The author asked 41 other students to identify the tire they would select. The results are listed in the following table (except for one student who selected the spare). Use a 0.05 significance level to test the author鈥檚 claim that the results fit a uniform distribution. What does the result suggest about the likelihood of four students identifying the same tire when they really didn鈥檛 have a flat tire?

Tire

Left Front

Right Front

Left Rear

Right Rear

Number Selected

11

15

8

16

Exercises 1鈥5 refer to the sample data in the following table, which summarizes the last digits of the heights (cm) of 300 randomly selected subjects (from Data Set 1 鈥淏ody Data鈥 in Appendix B). Assume that we want to use a 0.05 significance level to test the claim that the data are from a population having the property that the last digits are all equally likely.

Last Digit

0

1

2

3

4

5

6

7

8

9

Frequency

30

35

24

25

35

36

37

27

27

24

Given that the P-value for the hypothesis test is 0.501, what do you conclude? Does it appear that the heights were obtained through measurement or that the subjects reported their heights?

Forward Grip Reach and Ergonomics When designing cars and aircraft, we must consider the forward grip reach of women. Women have normally distributed forward grip reaches with a mean of 686 mm and a standard deviation of 34 mm (based on anthropometric survey data from Gordon, Churchill, et al.).

a. If a car dashboard is positioned so that it can be reached by 95% of women, what is the shortest forward grip reach that can access the dashboard?

b. If a car dashboard is positioned so that it can be reached by women with a grip reach greater than 650 mm, what percentage of women cannot reach the dashboard? Is that percentage too high?

c. Find the probability that 16 randomly selected women have forward grip reaches with a mean greater than 680 mm. Does this result have any effect on the design?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.