/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q36 Sample Size. In Exercises 29鈥3... [FREE SOLUTION] | 91影视

91影视

Sample Size. In Exercises 29鈥36, find the sample size required to estimate the population mean.

Mean Body Temperature Data Set 3 鈥淏ody Temperatures鈥 in Appendix B includes 106 body temperatures of adults for Day 2 at 12 am, and they vary from a low of 96.5掳F to a high of 99.6掳F. Find the minimum sample size required to estimate the mean body temperature of all adults. Assume that we want 98% confidence that the sample mean is within 0.1掳F of the population mean.

a. Find the sample size using the range rule of thumb to estimate s.

b. Assume that =0.62F, based on the value of s=0.6Ffor the sample of 106 body temperatures.

c. Compare the results from parts (a) and (b). Which result is likely to be better?

Short Answer

Expert verified

a. The sample size required to estimate the mean body temperature of all adults using the estimate of is 327.

b. The sample size required to estimate the mean temperature of all adults instead of for a sample of 106 body temperatures is 209.

c. On comparing the results (a) and (b), the result obtained in part (b) is likely to be better than that in part (a).

Step by step solution

01

Given information

The temperature varies from a low 96.5掳F to a high 99.6掳F.

The required confidence level is 98%, and the sample mean is within 0.1掳F of the population mean.

02

Describe the formula for sample size

The sample size n can be determined by using the following formula:

n=z2E2...1

Here, E is the margin of error.

03

Describe the range rule of thumb 

The range rule of thumb is a simple tool for understanding and interpreting the standard deviation.It is used to estimate the standard deviation roughly from the collection of sample data.

The formula for the range rule of thumb is as follows.

range4...2

04

Find the critical value  zα2

z2 is a z score that separates an area of 2 in the right tail of the standard normal distribution.

The confidence level 98% corresponds to =0.02and2=0.01.

The value z2, has the cumulative area 1-2to its left .

Mathematically,

Pz<z2=1-2=0.99

From the standard normal table, the area of 0.99 is observed as the corresponding to the row value 2.3, column value 0.02, which implies that role="math" localid="1648032893802" z2 is 2.33.

05

Find the estimate of  using the range rule of thumb 

a.

Themean body temperature varies from a low 96.5掳F to a high 99.6掳F.

Therefore, the range of body temperature is as follows.

Range=99.6-96.5=3.1

The estimate of is obtained by substituting the value of range in equation (2). So,

range4=3.14=0.775

06

Find the required sample size using the estimate of   σ

The sample size is calculated by substituting the values of z2, , and E in equation (1), as follows.

n=z2E2=2.330.7750.12=326.07=327roundedoff

Thus, with 326 samples values, we can be98% confident that the sample mean is within 0.1掳F of the population mean.

07

Find the required sample size using  s instead of   σ

b.

Assume that=0.62F is based on the value of s=0.62F for the sample of 106 body temperatures.

The sample size is calculated by substituting the values ofz2,s , and E in equation (1), as follows.

n=z2sE2=2.330.620.12=208.68=209roundedoff

Thus, with 209 sample values, we can be98% confident that the sample mean is within 0.1掳F of the population mean.

08

Compare the results (a) and (b)

c.

The sample size required to estimate the mean body temperature of all adults using the range rule thumb estimate of is 327.

The sample size required to estimate the mean temperature of all adults s instead of for the sample of 106 body temperature is 209.

The result obtained in part (a) is larger than the result obtained in part (b).

The result from part (b) is better than the results from part (a) because it uses instead of the estimated obtained from the range rule of thumb.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Using Correct Distribution. In Exercises 5鈥8, assume that we want to construct a confidence interval. Do one of the following, as appropriate: (a) Find the critical value t2,(b) find the critical value ,or z2(c) state that neither the normal distribution nor the t distribution applies.

Denver Bronco Salaries confidence level is 99%,=3342thousand dollars, and the histogram of 61 player salaries (thousands of dollars) is shown in Exercise 6.

Confidence Intervals. In Exercises 9鈥24, construct the confidence interval estimate of the mean.

Birth Weights of Girls Use these summary statistics given in Exercise 8:n=205,x=30.4hg,s=7.1hg. Use a 95% confidence level. Are the results very different from those found in Example 2 with only 15 sample values?

Confidence Intervals. In Exercises 9鈥24, construct the confidence interval estimate of the mean.

Student Evaluations Listed below are student evaluation ratings of courses, where a rating of 5 is for 鈥渆xcellent.鈥 The ratings were obtained at the University of Texas at Austin. (See Data Set 17 鈥淐ourse Evaluations鈥 in Appendix B.) Use a 90% confidence level. What does the confidence interval tell us about the population of college students in Texas?

3.8 3.0 4.0 4.8 3.0 4.2 3.5 4.7 4.4 4.2 4.3 3.8 3.3 4.0 3.8

Critical Thinking. In Exercises 17鈥28, use the data and confidence level to construct a

confidence interval estimate of p, then address the given question. Mendelian GeneticsOne of Mendel鈥檚 famous genetics experiments yielded 580 peas, with 428 of them green and 152 yellow.

a.Find a 99% confidence interval estimate of the percentageof green peas.

b.Based on his theory of genetics, Mendel expected that 75% of the offspring peas would be green. Given that the percentage of offspring green peas is not 75%, do the results contradict Mendel鈥檚 theory? Why or why not?

Finding Critical Values In constructing confidence intervals for or 2, Table A-4 can be used to find the critical values L2and R2only for select values of n up to 101, so the number of degrees of freedom is 100 or smaller. For larger numbers of degrees of freedom, we can approximate L2andR2 by using,

2=12z2+2k-12

where k is the number of degrees of freedom and z2is the critical z score described in Section 7-1. Use this approximation to find the critical values L2and R2for Exercise 8 鈥淗eights of Men,鈥 where the sample size is 153 and the confidence level is 99%. How do the results compare to the actual critical values of L2= 110.846 and R2= 200.657?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.