91影视

The numbers of subjects treated with OxyCotin were recorded. The number sample size, $n=227$. The confidence interval is 95%

a.

1. The samples are selected randomly.

2. There are two categories of outcomes, either developed nausea or not.

3. The count of success is 52 and failures is 175 which areboth are greater than 5.

Therefore, the conditions are satisfied.

Here we need to estimate the confidence interval of the OxyCotin users who developed nausea.

Thesample proportion of theOxyContin userswho developed nausea is:

$$\begin{gathered} \hat{p}=\frac{x}{n} \\ =\frac{52}{227} \\ =0.2291 \end{gathered}$$

Therefore, the sample proportion is 0.2291.

Then,

$$\begin{gathered} \hat{q}=1-\hat{p} \\ =1-0.2291 \\ =0.7709 \end{gathered}$$

At $95\%$confidence interval $伪=0.05$,

Using the standard normal table, the critical value is computed as,

$$\begin{gathered} z_{crit}=z_{\frac{伪}{2}} \\ =z_{0.025} \\ =1.96 \end{gathered}$$

The margin of error is given by,

$$\begin{gathered} E=z_{crit}脳\sqrt{\frac{\hat{p}\hat{q}}{n}} \\ =1.96脳\sqrt{\frac{0.23脳0.77}{227}} \\ =0.0547 \end{gathered}$$

The formula for the confidence interval is given by,

$$\begin{gathered} CI=\hat{p}-E<p<\hat{p}+E \\ =\left(0.23-0.0547<p<0.23+0.0547\right) \\ =(0.1744<p<0.2837) \end{gathered}$$

In percentage, the 95% confidence interval is $17.44\%<p<28.37\%$

b.

The confidence interval in the case of the treatment group is between 17.44% to 28.37%. The 95% confidence interval in the case of the control group is between 1.93% and 20.3%.

Each of the intervals are different from each other and they do not overlap. Hence it is concluded that OxyContin and Placebo have different rates of effect on developing nausea.