91影视

In a sample of 1228 medical malpractice lawsuits, 856 were dropped or dismissed.

(a)

The best point estimate of the proportion of medical malpractice lawsuits that are dropped or dismissed is computed below:

$$\begin{gathered} \hat{p}=\frac{856}{1228} \\ =0.697 \end{gathered}$$

Thus, the sample proportion of medical malpractice lawsuits that are dropped or dismissed equal to 0.697 is the best point estimate of the proportion of medical malpractice lawsuits that are dropped or dismissed.

(b)

The confidence level is equal to 95%. Thus, the corresponding level of significance is equal to 0.05.

From the standard normal distribution table, the right-tailed value of $z_{\frac{伪}{2}}$ for$伪=0.05$ is equal to 1.96.

The margin of error is calculated below:

$$\begin{gathered} E=1.96脳\sqrt{\frac{0.697脳0.303}{1228}} \\ =0.0257 \end{gathered}$$

Thus, the margin of error is equal to 0.0257.

(c)

The formula for computing the confidence interval estimate of the population proportion is written below:

$CI=\left(\hat{p}-E,\hat{p}+E\right)$

The 95% confidence interval becomes equal to:

$$\begin{gathered} CI=\left(0.697-0.0257,0.697+0.0257\right) \\ =\left(0.671,0.723\right) \end{gathered}$$

Therefore, the 95% confidence interval estimate of the population proportion of medical malpractice lawsuits that are dropped or dismissed is equal to (0.671, 0.723).

(d)

There is 95% confidence that the true proportion of medical malpractice lawsuits that are dropped or dismissed will lie between the values, 0.671 and 0.723.