91影视

A sample of McDonald鈥檚 orders was collected to check the accuracy of the orders. The sample size is 362. In the sample, 33 orders were inaccurate.

(a)

The best point estimate of the proportion of inaccurate orders is computed below:

$$\begin{gathered} \hat{p}=\frac{33}{362} \\ =0.091 \end{gathered}$$

Thus, the sample proportion of inaccurate orders equal to 0.091 is the best point estimate of the proportion of inaccurate orders.

(b)

The confidence level is equal to 95%. Thus, the corresponding level of significance is equal to 0.05.

From the standard normal distribution table, the right-tailed value of $z_{\frac{伪}{2}}$ for is equal to 1.96.

The margin of error is calculated below:

$$\begin{gathered} E=1.96脳\sqrt{\frac{0.091脳0.909}{362}} \\ =0.0297 \end{gathered}$$

Thus, the margin of error is equal to 0.0297.

(c)

The formula for computing the confidence interval estimate of the population proportion is written below:

$CI=\left(\hat{p}-E,\hat{p}+E\right)$

The 95% confidence interval becomes equal to:

$$\begin{gathered} CI=\left(0.091-0.0297,0.09+0.0297\right) \\ =\left(0.0613,0.1207\right) \end{gathered}$$

Therefore, the 95% confidence interval estimate of the population鈥檚 proportion of inaccurate orders is equal to (0.0613,0.1207).

(d)

There is 95% confidence that the true proportion of inaccurate orders will lie between the values 0.0613 and 0.1207.