91Ó°ÊÓ

It is given that 42% of consumers are comfortable having drones deliver their purchases and the rest are not.

The probability that out of five consumers, exactly two of them are comfortable with drones delivering their goods is to be considered.

Let X be a random variable that follows a binomial distribution. As a result, the following variables are defined:

• n denotes the total number of trials.
• x denotes the number of successes.
• pdenotes the probability of success.
• q denotes the probability of failure.

Here, assume that X denotes the number of consumers who are comfortable with drones, and it follows the binomial probability distribution.

Thus, success is defined as selecting a consumer who is comfortable with drones.

The total number of trials conducted is equal to 5.

The desired number of successes is equal to 2.

The probability of selecting a consumer who is comfortable with drones (p) is equal to 42% or 0.42.

Thus, the probability of selecting a consumer who is not comfortable with drones delivering their goods is equal to $1-0.42=0.58$.

Therefore, the following values are obtained:

• n = 5
• x = 2
• p = 0.42
• q = 0.58