91Ó°ÊÓ

A set of eight multiple-choice questions are answered in the SAT. The probability of a correct answer is given to be equal to 0.20.

Let X denote the number of correct answers.

Thus, the number of trials (n) is given to be equal to eight.

The probability of success (getting a correct answer) is p= 0.20.

The probability of failure (getting a wrong answer) is calculated below:

$$\begin{gathered} q=1-p \\ =1-0.20 \\ =0.80 \end{gathered}$$

The number of successes required in eight trials should be less than three.

The binomial probability formula is as follows:

$P\left(X=x\right)={}^n{C}_x{\left(p\right)}^x{\left(q\right)}^{n-x}$

By using the binomial probability formula, the probability of getting fewer than three correct answers is computed below:

$$\begin{gathered} P\left(X<3\right)=P\left(X=0\right)+P\left(X=1\right)+P\left(X=2\right) \\ {=}^8{C}_0{\left(0.20\right)}^0{\left(0.80\right)}^8+{}^8{C}_1{\left(0.20\right)}^1{\left(0.80\right)}^7+{}^8{C}_2{\left(0.20\right)}^2{\left(0.80\right)}^6 \\ =0.167772+0.335544+0.293601 \\ =0.796917 \\ =0.797 \end{gathered}$$

Therefore, the probability of getting fewer than three correct answers is equal to 0.797.