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Best Multiple Regression Equation For the regression equation given in Exercise 1, the P-value is 0.000 and the adjusted \({R^2}\)value is 0.925. If we were to include an additional predictor variable of neck size (in.), the P-value becomes 0.000 and the adjusted\({R^2}\)becomes 0.933. Given that the adjusted \({R^2}\)value of 0.933 is larger than 0.925, is it better to use the regression equation with the three predictor variables of length, chest size, and neck size? Explain.

Short Answer

Expert verified

Yes, it is better to use the regression equation with the predictor variables of length, chest size, and neck size because of the following factors:

  • It is a greater adjusted\({R^2}\)value.
  • The regression is significant.
  • The variation in the response variable of weight is explained more using the regression equation with three predictors or independent variables.

Step by step solution

01

Given information

A regression equation is computed to predict the weight of a bear (inlb) using the predictor variables 鈥渨eight鈥, 鈥渓ength,鈥 and 鈥渃hest size.鈥

The p-value and the adjusted\({R^2}\)value are 0.000 and 0.925, respectively.

Further, another predictor variable 鈥渘eck size鈥 is added to the equation, and the p-value and the adjusted \({R^2}\) are 0.000 and 0.933, respectively.

02

Best regression equation

To identify the best regression equation, consider the equation with the highest value of adjusted\({R^2}\).

Here, the regression equation with two independent variables, 鈥渓ength鈥 and 鈥渃hest size鈥, has the adjusted \({R^2}\) value of 0.925. Moreover, the p-value for this regression is equal to 0.000, indicating that the regression is significant.

Further, another predictor variable 鈥渘eck size鈥 is added to the previous equation.

Now, the regression equation with three independent variables of 鈥渓ength鈥, 鈥渃hest size鈥 and 鈥渘eck size鈥 has a new adjusted \({R^2}\) value at 0.933.The new p-value is 0.000, which implies that the new regression is still significant.

Here,

\(\begin{array}{c}{\rm{New}}\;{\rm{Adjusted}}\;{R^2} > {\rm{Adjusted}}\;{R^2}\\0.933 > 0.925\end{array}\)

Since the new regression equation with the variable 鈥渘eck size鈥 has a larger value of adjusted\({R^2}\)and the regression is significant, the new regression equation is the best. It explains more variation in the response variable as compared to the equation with only two predictors.

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Most popular questions from this chapter

In exercise 10-1 12. Clusters Refer to the following Minitab-generated scatterplot. The four points in the lower left corner are measurements from women, and the four points in the upper right corner are from men.

a. Examine the pattern of the four points in the lower left corner (from women) only, and subjectively determine whether there appears to be a correlation between x and y for women.

b. Examine the pattern of the four points in the upper right corner (from men) only, and subjectively determine whether there appears to be a correlation between x and y for men.

c. Find the linear correlation coefficient using only the four points in the lower left corner (for women). Will the four points in the upper left corner (for men) have the same linear correlation coefficient?

d. Find the value of the linear correlation coefficient using all eight points. What does that value suggest about the relationship between x and y?

e. Based on the preceding results, what do you conclude? Should the data from women and the data from men be considered together, or do they appear to represent two different and distinct populations that should be analyzed separately?

Testing for a Linear Correlation. In Exercises 13鈥28, construct a scatterplot, and find the value of the linear correlation coefficient r. Also find the P-value or the critical values of r from Table A-6. Use a significance level of A = 0.05. Determine whether there is sufficient evidence to support a claim of a linear correlation between the two variables. (Save your work because the same data sets will be used in Section 10-2 exercises.)

Sports Diameters (cm), circumferences (cm), and volumes (cm3) from balls used in different sports are listed in the table below. Is there sufficient evidence to conclude that there is a linear correlation between diameters and circumferences? Does the scatterplot confirm a linear association?


Diameter

Circumference

Volume

Baseball

7.4

23.2

212.2

Basketball

23.9

75.1

7148.1

Golf

4.3

13.5

41.6

Soccer

21.8

68.5

5424.6

Tennis

7

22

179.6

Ping-Pong

4

12.6

33.5

Volleyball

20.9

65.7

4780.1

Softball

9.7

30.5

477.9

What is the difference between the regression equation\(\hat y = {b_0} + {b_1}x\)and the regression equation\(y = {\beta _0} + {\beta _1}x\)?

Testing for a Linear Correlation. In Exercises 13鈥28, construct a scatterplot, and find the value of the linear correlation coefficient r. Also find the P-value or the critical values of r from Table A-6. Use a significance level of A = 0.05. Determine whether there is sufficient evidence to support a claim of a linear correlation between the two variables. (Save your work because the same data sets will be used in Section 10-2 exercises.)

Sports Repeat the preceding exercise using diameters and volumes.

Scatterplots Match these values of r with the five scatterplots shown below: 0.268, 0.992, -1, 0.746, and 1.

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