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Three age brackets; 18-25, 26-40, and 41-80, are compared for mean pulse rates for females, using the output from statdisk.

In the study, the researcher wants to test the claim that the mean pulse rates of the females in three age brackets are the same.

The significance level is 0.05.

If the study requires comparing more than two groups for mean values, the ANOVA test is recommended for use.

The hypotheses for ANOVA would be,

\(\begin{aligned}{l}{H_o}:{\mu _1} = {\mu _2} = {\mu _3} = ... = {\mu _n}\\{H_a}:\;{\rm{atleast}}\;{\rm{one}}\;{\mu _i}\;{\rm{is}}\;{\rm{different}}\end{aligned}\)

The decision rule is stated as follows:

• If the p-value for the test is less than the significance level, the null hypothesis is rejected.
• If the p-value for the test is greater than the significance level, the null hypothesis is failed to be rejected.

Assume\({\mu _1},{\mu _2},{\mu _3}\)be the mean pulse rate for the males in three age brackets 18-25,26-40, and 41-80, respectively.

The null and the alternative hypothesis is,

\(\begin{aligned}{l}{H_o}:{\mu _1} = {\mu _2} = {\mu _3}\\{H_a}:\;{\rm{atleast}}\;{\rm{one}}\;{\mu _i}\;{\rm{is}}\;{\rm{different}}\end{aligned}\)

From the output, the p-value is obtained from the last column, which is 0.000539.

As the p-value is less than 0.05, the null hypothesis is rejected at the 0.05 significance level.

Therefore, there is enough statistical evidence to warrant the rejection of the claim that the mean pulse rates of females in three age brackets are the same. So, it can be concluded at a 0.05 level of significance that the mean pulse rate level of at least one of the three age brackets of females is different from others. Thus, it can be said that the female's pulse rates are affected by the age brackets.