/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 The sample size needed to estima... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The sample size needed to estimate the difference between two population proportions to within a margin of error \(E\) with a confidence level of \(1-\alpha\) can be found by using the following expression: $$ E=z_{\alpha / 2} \sqrt{\frac{p_{1} q_{1}}{n_{1}}+\frac{p_{2} q_{2}}{n_{2}}} $$ Replace \(n_{1}\) and \(n_{2}\) by \(n\) in the preceding formula (assuming that both samples have the same size) and replace each of \(p_{1}, q_{1}, p_{2},\) and \(q_{2}\) by 0.5 (because their values are not known). Solving for \(n\) results in this expression: $$n=\frac{z_{\alpha / 2}^{2}}{2 E^{2}}$$ Use this expression to find the size of each sample if you want to estimate the difference between the proportions of men and women who own smartphones. Assume that you want \(95 \%\) confidence that your error is no more than 0.03

Short Answer

Expert verified
The sample size needed for each group is approximately 1068.

Step by step solution

01

- Understand the Given Data

Identify the given information: confidence level (95%) and margin of error (0.03).
02

- Find the Z-value for the Confidence Level

Determine the z-value corresponding to a 95% confidence level, which is found in statistical tables or standard values. For a confidence level of 95%, the z-value is 1.96.
03

- Use the Provided Formula

Substitute the z-value and margin of error into the formula to solve for the sample size: Where: .
04

- Calculate Sample Size

Substitute the values into the formula n ≈ and solve for n.
05

- Simplify the Equation

Simplify the expression to find the value of n.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Level
In statistics, the confidence level represents the percentage of times that the confidence interval would contain the true population parameter if you repeated the study multiple times. For example, a 95% confidence level means that if you were to take 100 different samples and compute a confidence interval for each sample, we would expect that approximately 95 out of the 100 confidence intervals will contain the true population parameter.

When calculating the sample size, the confidence level determines the z-value, which is a critical component in the formula. Typically, common confidence levels include 90%, 95%, and 99%. The higher the confidence level, the larger the sample size required for a given margin of error, because we want to be more certain that our interval contains the true parameter.
Margin of Error
The margin of error (MOE) indicates the range within which we expect the true population parameter to lie. It gives you a sense of how much you can expect your sample estimate to deviate from the actual population parameter. A smaller margin of error requires a larger sample size to achieve, because you are demanding greater precision.

In the given exercise, the margin of error is specified as 0.03. This means we want our estimate of the difference in proportions to be within ±3% of the true difference. The formula for estimating sample size, as shown in the problem, includes the margin of error in the denominator, highlighting its inverse relationship to the required sample size.
Z-Value
The z-value, or z-score, corresponds to the number of standard deviations a data point is from the mean in a standard normal distribution. In the context of confidence intervals, the z-value defines the number of standard deviations we need to extend from the sample mean to find our interval estimate.

For a 95% confidence level, the z-value is 1.96. This is derived from standard normal distribution tables, indicating that 95% of the data lies within ±1.96 standard deviations of the mean. Thus, in the sample size formula, the z-value multiplies with the standard error to ensure that the confidence interval covers the desired proportion of the population.
Proportion Difference
Proportion difference measures the difference between two population proportions. In this context, it refers to the difference in proportions of men and women who own smartphones. When calculating sample size, we often start with an assumption of equal proportions, especially when no preliminary data is available. Hence, using 0.5 for both proportions makes the formula more conservative, ensuring that the sample size is adequate.

The formula assumes equal sample sizes for both groups being compared, simplifying calculations and application. This approach helps balance the margin of error evenly across both populations, providing a robust estimate of the proportion difference given the specified statistical confidence.

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Most popular questions from this chapter

Use the listed paired sample data, and assume that the samples are simple random samples and that the differences have a distribution that is approximately normal. As part of the National Health and Nutrition Examination Survey, the Department of Health and Human Services obtained self-reported heights (in.) and measured heights (in.) for males aged \(12-16 .\) Listed below are sample results. Construct a \(99 \%\) confidence interval estimate of the mean difference between reported heights and measured heights. Interpret the resulting confidence interval, and comment on the implications of whether the confidence interval limits contain \(0 .\) $$\begin{array}{|l|c|c|c|c|c|c|c|c|c|c|c|c|} \hline \text { Reported } & 68 & 71 & 63 & 70 & 71 & 60 & 65 & 64 & 54 & 63 & 66 & 72 \\ \hline \text { Measured } & 67.9 & 69.9 & 64.9 & 68.3 & 70.3 & 60.6 & 64.5 & 67.0 & 55.6 & 74.2 & 65.0 & 70.8 \\ \hline \end{array}$$

Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. (Note: Answers in Appendix D include technology answers based on Formula 9 - 1 along with "Table" answers based on Table \(A\) - 3 with df equal to the smaller of \(\boldsymbol{n}_{I}-\boldsymbol{I}\) and \(\boldsymbol{n}_{2}-\boldsymbol{I} .\) ) Is Old Faithful Not Quite So Faithful? Listed below are time intervals (min) between eruptions of the Old Faithful geyser. The "recent" times are within the past few years, and the "past" times are from 1995. Does it appear that the mean time interval has changed? Is the conclusion affected by whether the significance level is 0.05 or \(0.01 ?\) $$\begin{array}{l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l|l} \hline \text { Recent } & 78 & 91 & 89 & 79 & 57 & 100 & 62 & 87 & 70 & 88 & 82 & 83 & 56 & 81 & 74 & 102 & 61 \\ \hline \text { Past } & 89 & 88 & 97 & 98 & 64 & 85 & 85 & 96 & 87 & 95 & 90 & 95 & & & & & \\ \hline\end{array}$$

Use the listed paired sample data, and assume that the samples are simple random samples and that the differences have a distribution that is approximately normal. A popular theory is that presidential candidates have an advantage if they are taller than their main opponents. Listed are heights (cm) of presidents along with the heights of their main opponents (from Data Set 15 "Presidents"). a. Use the sample data with a 0.05 significance level to test the claim that for the population of heights of presidents and their main opponents, the differences have a mean greater than \(0 \mathrm{cm} .\) b. Construct the confidence interval that could be used for the hypothesis test described in part (a). What feature of the confidence interval leads to the same conclusion reached in part (a)? $$\begin{array}{|l|l|l|l|l|l|l|} \hline \text { Height (cm) of President } & 185 & 178 & 175 & 183 & 193 & 173 \\\ \hline \text { Height (cm) of Main Opponent } & 171 & 180 & 173 & 175 & 188 & 178 \\ \hline \end{array}$$

Use the listed paired sample data, and assume that the samples are simple random samples and that the differences have a distribution that is approximately normal. Listed below are body temperatures from seven different subjects measured at two different times in a day (from Data Set 3 "Body Temperatures" in Appendix B). a. Use a 0.05 significance level to test the claim that there is no difference between body temperatures measured at \(8 \mathrm{AM}\) and at \(12 \mathrm{AM}\). b. Construct the confidence interval that could be used for the hypothesis test described in part (a). What feature of the confidence interval leads to the same conclusion reached in part (a)? $$\begin{array}{l|l|l|l|l|l|l|l} \hline \text { Body Temperature ("F) at 8 AM } & 96.6 & 97.0 & 97.0 & 97.8 & 97.0 & 97.4 & 96.6 \\ \hline \text { Body Temperature ('F) at 12 AM } & 99.0 & 98.4 & 98.0 & 98.6 & 98.5 & 98.9 & 98.4 \\ \hline \end{array}$$

Test the given claim. Identify the null hypothesis, alternative hypothesis, test statistic, P-value or critical value(s), then state the conclusion about the null hypothesis, as well as the final conclusion that addresses the original claim. The Chapter Problem involved passenger cars in Connecticut and passenger cars in New York, but here we consider passenger cars and commercial trucks. Among 2049 Connecticut passenger cars, 239 had only rear license plates. Among 334 Connecticut trucks, 45 had only rear license plates (based on samples collected by the author). A reasonable hypothesis is that passenger car owners violate license plate laws at a higher rate than owners of commercial trucks. Use a 0.05 significance level to test that hypothesis. a. Test the claim using a hypothesis test. b. Test the claim by constructing an appropriate confidence interval.

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