/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 48 Find the indicated area under th... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the indicated area under the curve of the standard normal distribution; then convert it to a percentage and fill in the blank. The results form the basis for the range rule of thumb and the empirical rule introduced in Section 3-2. About _____ \(\%\) of the area is between \(z=-3.5\) and \(z=3.5\) (or within 3.5 standard deviations of the mean).

Short Answer

Expert verified
About 99.954% of the area is between Z = -3.5 and Z = 3.5.

Step by step solution

01

- Identify the given parameters

Given the standard normal distribution, we need to find the area between the values of the Z-scores from -3.5 to 3.5.
02

- Use the Z-table or standard normal distribution calculator

To find the areas associated with Z-scores, either use a Z-table or an online standard normal distribution calculator. Look up the cumulative area from the mean to the Z-score of 3.5.
03

- Calculate the cumulative area

Using a Z-table or calculator, find the cumulative area for Z = 3.5, which is approximately 0.99977.
04

- Determine the total area between Z = -3.5 and Z = 3.5

Since the total area under the standard normal curve is 1, the area beyond Z = 3.5 in both tails is very small. Thus, the central area is calculated as: Total central area = 1 - 2 * (1 - cumulative area at Z = 3.5) Total central area = 1 - 2 * (1 - 0.99977) = 0.99954
05

- Convert the area to a percentage

To convert the obtained central area to a percentage, multiply by 100: Percentage area = 0.99954 * 100 = 99.954%

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-scores
In statistics, a Z-score is a numerical measurement that describes a value's relationship to the mean of a group of values. They are measured in terms of standard deviations from the mean.
For example, a Z-score of 1.0 indicates a value is one standard deviation away from the mean. Similarly, a Z-score of -1.0 indicates a value is one standard deviation below the mean.
Z-scores help in understanding how far away a particular value is from the average, which is especially useful when comparing data points from different normal distributions. They can be calculated using the formula:
$$Z = \frac{(X - \text{Mean})}{\text{Standard Deviation}}$$
In the provided exercise, we focus on Z-scores of -3.5 and 3.5, indicating values that are respectively 3.5 standard deviations below and above the mean.
Cumulative Area
The cumulative area under the normal distribution curve corresponds to the probability that a randomly selected value from the distribution will be less than or equal to a particular Z-score.
To find this area, we refer to Z-tables or use normal distribution calculators.
For example, in our exercise, we need the cumulative area from the mean to Z = 3.5. Using a Z-table, this value is approximately 0.99977.
By understanding the cumulative area, we can determine the percentage of data points falling below a certain threshold, which is critical in statistical analysis and hypothesis testing.
When finding the area between two Z-scores, like between Z = -3.5 and Z = 3.5, we can calculate:
  • Cumulative area for Z = 3.5 from the mean (0.99977)
  • Subtract the small area beyond Z=3.5 from 1
  • Then, double it due to symmetry around the mean
Thus, we find the central area of approximately 0.99954.
Empirical Rule
The empirical rule, also known as the 68-95-99.7 rule, is a quick way to understand the distribution of data points in a normal distribution.
According to this rule:
  • About 68% of data falls within one standard deviation of the mean
  • About 95% falls within two standard deviations
  • About 99.7% falls within three standard deviations
This means that for a data set following a normal distribution, nearly all values will lie within three standard deviations of the mean.
In our exercise with Z-scores of -3.5 and 3.5, the empirical rule helps confirm that more than 99.7% of the data falls within this range, thus showing 99.954% found via cumulative area closely aligns with this rule.
Employing the empirical rule helps in making quick estimations and understanding data spread without extensive calculations.
Range Rule of Thumb
The range rule of thumb provides a simple approximation for determining the range and distribution of data within a dataset. It states that:
Almost all values lie within four standard deviations (two above and two below the mean).
This is useful for estimating a range without detailed calculations.
Applied to our exercise, with Z-scores from -3.5 to 3.5, it aligns with the empirical rule, suggesting that deviations further than 3.5 are exceedingly rare, and the central area covers the vast majority.
This rule of thumb is especially helpful in quick sanity checks and basic statistical analyses where detailed breakdowns aren't required.

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Most popular questions from this chapter

The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15 days. a. In a letter to "Dear Abby," a wife claimed to have given birth 308 days after a brief visit from her husband, who was working in another country. Find the probability of a pregnancy lasting 308 days or longer. What does the result suggest? b. If we stipulate that a baby is premature if the duration of pregnancy is in the lowest \(3 \%\) find the duration that separates premature babies from those who are not premature. Premature babies often require special care, and this result could be helpful to hospital administrators in planning for that care.

Use these parameters (based on Data Set 1 "Body Data" in Appendix \(B\) ): Men's heights are normally distributed with mean 68.6 in. and standard deviation 2.8 in. Women's heights are normally distributed with mean 63.7 in. and standard deviation 2.9 in. Disney World requires that people employed as a Mickey Mouse character must have a height between 56 in. and 62 in. a. Find the percentage of men meeting the height requirement. What does the result suggest about the genders of the people who are employed as Mickey Mouse characters? b. If the height requirements are changed to exclude the tallest \(50 \%\) of men and the shortest \(5 \%\) of men, what are the new height requirements?

Hybridization A hybridization experiment begins with four peas having yellow pods and one pea having a green pod. Two of the peas are randomly selected with replacement from this population. a. After identifying the 25 different possible samples, find the proportion of peas with yellow pods in each of them, then construct a table to describe the sampling distribution of the proportions of peas with yellow pods. b. Find the mean of the sampling distribution. c. Is the mean of the sampling distribution [from part (b)] equal to the population proportion of peas with yellow pods? Does the mean of the sampling distribution of proportions always equal the population proportion?

The probability of a baby being born a boy is \(0.512 .\) Consider the problem of finding the probability of exactly 7 boys in 11 births. Solve that problem using (1) normal approximation to the binomial using Table \(A-2 ;\) (2) normal approximation to the binomial using technology instead of Table \(A-2 ;\) (3) using technology with the binomial distribution instead of using a normal approximation. Compare the results. Given that the requirements for using the normal approximation are just barely met, are the approximations off by very much?

Doorway Height The Boeing \(757-200\) ER airliner carries 200 passengers and has doors with a height of 72 in. Heights of men are normally distributed with a mean of 68.6 in. and a standard deviation of 2.8 in. (based on Data Set 1 "Body Data" in Appendix B). a. If a male passenger is randomly selected, find the probability that he can fit through the doorway without bending. b. If half of the 200 passengers are men, find the probability that the mean height of the 100 men is less than 72 in. c. When considering the comfort and safety of passengers, which result is more relevant: the probability from part (a) or the probability from part (b)? Why? d. When considering the comfort and safety of passengers, why are women ignored in this case?

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