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91Ó°ÊÓ

Find the probability.At Least One. In Exercises \(5-12,\) find the probability. Find the probability that when a couple has three children, at least one of them is a girl. (Assume that boys and girls are equally likely.)

Short Answer

Expert verified
The probability that the couple has at least one girl when they have three children is \(\frac{7}{8}\).

Step by step solution

01

Determine Total Outcomes

Since each child can be either a boy or a girl, the total number of possible outcomes for three children can be calculated using combinations. Each child has 2 possibilities (boy or girl), so for 3 children, the total number of outcomes is: \(2^3 = 8\)
02

List All Possible Outcomes

List all possible combinations of the three children:1. BBB (Boy, Boy, Boy)2. BBG (Boy, Boy, Girl)3. BGB (Boy, Girl, Boy)4. GBB (Girl, Boy, Boy)5. BGG (Boy, Girl, Girl)6. GBG (Girl, Boy, Girl)7. GGB (Girl, Girl, Boy)8. GGG (Girl, Girl, Girl)
03

Identify Favorable Outcomes

Favorable outcomes are those that include at least one girl. The only outcome that does not include a girl is: 1. BBBSo, the favorable outcomes are:1. BBG2. BGB3. GBB4. BGG5. GBG6. GGB7. GGG
04

Calculate Probability of At Least One Girl

Count the number of favorable outcomes (outcomes that include at least one girl). There are 7 favorable outcomes.Next, use the probability formula: \[P(\text{at least one girl}) = \frac{\text{Number of Favorable Outcomes}}{\text{Total Number of Possible Outcomes}} = \frac{7}{8}\]
05

Simplify and Write the Final Answer

So, the probability that the couple has at least one girl when they have three children is \(\frac{7}{8}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Outcome Determination
Determining outcomes is the first step in solving any probability problem. In this exercise, we need to figure out all the possible outcomes when a couple has three children. Each child can be either a boy or a girl. Since each child's gender is independent of the others, we can calculate the total number of outcomes by multiplying the possibilities for each child together. This gives us:\[ 2^3 = 8 \] This means there are 8 different possible combinations of genders for three children.
Next, we list all these possible outcomes, which are: BBB (Boy, Boy, Boy), BBG (Boy, Boy, Girl), BGB (Boy, Girl, Boy), GBB (Girl, Boy, Boy), BGG (Boy, Girl, Girl), GBG (Girl, Boy, Girl), GGB (Girl, Girl, Boy), and GGG (Girl, Girl, Girl). Understanding these steps helps in precisely determining the sample space of an experiment.
Sample Space
The sample space in probability is the set of all possible outcomes. For the current problem, the sample space includes all gender combinations possible when having three children.
As we listed previously, the sample space consists of: BBB, BBG, BGB, GBB, BGG, GBG, GGB, and GGG. Each of these combinations represents a unique outcome.
Visualizing the sample space is crucial as it lays the foundation for identifying favorable outcomes. It's like having a complete map before you start your journey. Having a complete list of outcomes helps clarify what results are possible before moving on to measure probabilities.
Favorable Outcomes
Favorable outcomes are those that meet the criteria we are interested in. In this problem, we are looking for the scenarios where at least one child is a girl.
From our sample space, the only outcome where there are no girls is BBB. Therefore, all other outcomes (BBG, BGB, GBB, BGG, GBG, GGB, GGG) are favorable because they contain at least one girl.
Recognizing favorable outcomes makes it easier to calculate the desired probability. This step narrows down the focus from all possible outcomes to only those which we are interested in for the specific question.
Probability Calculation
The fundamental formula for calculating probability is: \[ P(\text{event}) = \frac{\text{Number of Favorable Outcomes}}{\text{Total Number of Possible Outcomes}} \]
Having identified that there are 7 favorable outcomes (those with at least one girl) and knowing there are 8 possible total outcomes, we can now calculate the probability: \[ P(\text{at least one girl}) = \frac{7}{8} = 0.875 \]
This means there's an 87.5% chance that a couple with three children will have at least one girl. Through understanding the total and favorable outcomes along with the sample space, we arrive at the probability, making the process clear and logical.

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Most popular questions from this chapter

Express all probabilities as fractions. Current rules for telephone area codes allow the use of digits \(2-9\) for the first digit, and \(0-9\) for the second and third digits. How many different area codes are possible with these rules? That same rule applies to the exchange numbers, which are the three digits immediately preceding the last four digits of a phone number. Given both of those rules, how many 10-digit phone numbers are possible? Given that these rules apply to the United States and Canada and a few islands, are there enough possible phone numbers? (Assume that the combined population is about \(400,000,000 .\) )

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Express all probabilities as fractions. A survey with 12 questions is designed so that 3 of the questions are identical and 4 other questions are identical (except for minor changes in wording). How many different ways can the 12 questions be arranged?

Express all probabilities as fractions. Your professor has just collected eight different statistics exams. If these exams are graded in random order, what is the probability that they are graded in alphabetical order of the students who took the exam?

Assume that 50 births are randomly selected. Use subjective judgment to describe the given number of girls as (a) significantly low, (b) significantly high, or (c) neither significantly low nor significantly high.23 girls.

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