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91Ó°ÊÓ

Find \(n\) for a \(90 \%\) confidence interval for \(p\) with \(E=0.02\) using an estimate of \(p=0.25\).

Short Answer

Expert verified
The value for 'n' is calculated from the formula for margin of error. After substituting values and calculating, you should round up to get the final sample size if not a whole number.

Step by step solution

01

Calculate z score

For a 90% confidence level, we know that the z-score is 1.645 (this value comes from a standard normal distribution table).
02

Substitute the Values

Plug the known values into the margin of error formula. We set the equation to \(E = z* \sqrt{(p*(1-p)}/n}\), substitute \(E=0.02\), \(z=1.645\), \(p=0.25\) to get \(0.02 = 1.645 * \sqrt{(0.25*(1-0.25))/n}\).
03

Rearrange the Equation to Solve for n

Square both sides to get rid of the square root and then solve for 'n'. This gets us the equation \((0.02)^2 = (1.645)^2 * ((0.25*(1-0.25))/n)\). Rearranging for 'n' we get \(n = (1.645)^2 * ((0.25*(1-0.25)))/(0.02)^2\).
04

Compute for n

Calculate the value to get the desired sample size. Remember that if the result is not a whole number, always round up to the nearest whole number since you can't have a fraction of a sample.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Margin of Error
Understanding the margin of error (MOE) is critical when interpreting the reliability of statistics. The MOE represents the extent to which you can expect the results of a survey to reflect the true population value. In other words, it's a measure of precision for an estimate from a sample.
A smaller MOE means a more accurate estimate from the sample. It is directly affected by the sample size (n) and the level of confidence one wishes to have in the estimate. The formula for the MOE typically includes the standard deviation of the population and the z-score, which corresponds to the desired confidence level. In the given exercise, an MOE of 0.02 indicates that the estimate of the true population proportion (p) is within ±2% of the reported sample proportion.
Z-Score
A z-score is a statistical measurement that describes a value's relationship to the mean of a group of values, measured in terms of standard deviations from the mean. Specifically, in the context of confidence intervals, the z-score corresponds to the number of standard deviations a data point is from the mean of the standard normal distribution.

Standard Normal Distribution and Z-scores

The standard normal distribution is a special case of the normal distribution with a mean of 0 and a standard deviation of 1. Z-scores are essentially the transformed data points that fit into this standard normal curve. For instance, a 90% confidence interval corresponds to a z-score of 1.645, which means that the sample proportion is 1.645 standard deviations away from the mean of the distribution, capturing the central 90% of the distribution.
Standard Normal Distribution
Diving deeper into the concept of standard normal distribution, it is the bell-shaped curve that is symmetrical about the mean (µ = 0) and has a standard deviation (σ) of 1. It's a key concept in statistics, representing a standardized way of examining data.
All normal distributions can be converted into the standard normal distribution using the z-score formula. When dealing with confidence intervals, this universal standardization through the z-score allows us to use the standard normal distribution to find the probability associated with certain outcomes. The table of z-scores and corresponding probabilities is called the standard normal distribution table, commonly used for finding the required z-score for calculating confidence intervals, as in the exercise example.
Sample Size Determination
Determining the appropriate sample size is crucial for achieving accurate and reliable statistical results. The sample size (n) impacts the margin of error and the precision of the confidence interval. To calculate the required sample size for a confidence interval, one must consider the population proportion (p), the desired margin of error (E), and the z-score corresponding to the chosen confidence level.
In our example, the formula \[\begin{equation}n = \left(\dfrac{z}{E}\right)^2 \times p(1-p)\end{equation}\]is used, where n is solved by assuming a proportion estimate, desired margin of error, and the corresponding z-score. After calculating, the sample size can be rounded up to the nearest whole number as one cannot survey a fraction of a respondent. Sample size determination ensures that the results are representative and statistically significant within the specified margin of error.

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Most popular questions from this chapter

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