/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 123 a. What value of chi-square for ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

a. What value of chi-square for 5 degrees of freedom subdivides the area under the distribution curve such that \(5 \%\) is to the right and \(95 \%\) is to the left? b. What is the value of the 95 th percentile for the chi-square distribution with 5 degrees of freedom? c. What is the value of the 90th percentile for the chi-square distribution with 5 degrees of freedom?

Short Answer

Expert verified
a) The value that subdivides the distribution curve such that it has 5% on the right and 95% on the left is 11.070. b) The value of the 95th percentile for the chi-square distribution with 5 degrees of freedom is 11.070. c) The value of the 90th percentile for the chi-square distribution with 5 degrees of freedom is 9.236.

Step by step solution

01

Understand the Chi-Square Distribution

The Chi-square (χ²) distribution is a one-sided distribution that starts from zero and extends to positive infinity. It is commonly used for hypothesis testing and constructing confidence intervals.
02

Interpreting the Statistical Table

We will use the chi-square distribution table to find the value of chi-square for different degrees of freedom. Since our degree of freedom is 5 (provided in the question), we will look for the 5th row in the table. For the first question which asks for the value that subdivides the distribution curve such that it has 5% to the right and 95% to the left, we will look under the column of 0.05.
03

Answer for a

The value which splits the chi-square distribution into 5% on the right and 95% on the left is 11.070. This value can be found on the Chi-Square Distribution Table under 5 degrees of freedom and p=0.05.
04

Answer for b

The value of the 95th percentile for the Chi-square distribution with 5 degrees of freedom is 11.070. This means there is a 95% probability that a Chi-square statistic with 5 degrees of freedom will be 11.070 or less.
05

Answer for c

The value of the 90th percentile for the Chi-square distribution with 5 degrees of freedom is 9.236. This means there's a 90% probability that a Chi-square statistic with 5 degrees of freedom will be 9.236 or less.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degrees of Freedom
The term 'degrees of freedom' is central to the proper understanding of various statistical distributions, including the chi-square distribution. It refers to the number of independent values or quantities which can vary in the analysis without breaking any constraints. In the context of the chi-square distribution, the degrees of freedom correspond to the number of independent variables in the data. For example, if a study has 6 categories of data, then the degrees of freedom would be 5 since one category will always be fixed if we know the values of the other five.

Understanding the role of degrees of freedom is crucial for interpreting statistical results accurately. It influences the shape of the chi-square distribution; as the degrees of freedom increase, the distribution becomes more symmetric. This means that for a low number of degrees of freedom, the chi-square distribution is highly skewed right, but as the degrees of freedom increase, the skew decreases, and the distribution resembles a more normal distribution.

Why Are Degrees of Freedom Important?

Calculating degrees of freedom is important because they impact the critical values of a test statistic. When conducting chi-square tests, an incorrect calculation of degrees of freedom can lead to the wrong conclusions. In research, this parameter helps to ensure the validity of hypothesis tests, enabling us to trust the statistical inferences we make.
Percentiles in Statistics
Percentiles are a way to represent the position of a particular value within a dataset. Statistically, if a value is at the 95th percentile, it means that 95% of the data points in the set are below that value, and only 5% are above. Percentiles are commonly used in applications such as standardized testing, growth charts, and the interpretation of economic data.

The calculation and interpretation of percentiles are vital in descriptive statistics as they give a clear position of where a data point stands relative to others. They also provide a way to understand and interpret distributions, such as the chi-square distribution used for various hypothesis tests.

Applying Percentiles in the Chi-Square Distribution

When we refer to percentiles within the framework of the chi-square distribution, we measure the extent of the spread of the distribution for a certain degree of freedom. Determining the 95th percentile, as in the provided exercise, is especially important in hypothesis testing. It can define cutoff values for accepting or rejecting hypotheses. In practice, this essentially tells us how extreme observed data must be for us to consider it statistically unusual.
Statistical Hypothesis Testing
Statistical hypothesis testing is a method used to make decisions about a population based on sample data. It involves making an assumption (the null hypothesis) and determining whether there is enough evidence in the sample data to reject this assumption in favor of an alternative hypothesis. The chi-square test is a common non-parametric test used in this context.

To perform a hypothesis test, one must calculate a test statistic that measures the difference between observed data and what is expected under the null hypothesis. The number of degrees of freedom in the chi-square distribution is one minus the number of categories if you're examining goodness-of-fit or the product of the categories minus one for each variable if you're looking at independence.

Chi-Square Distribution in Hypothesis Testing

The chi-square distribution is particularly useful in hypothesis testing scenarios where we wish to assess how likely the observed frequencies would occur by random chance. The percentile values act as threshold criteria to determine the significance of our results. For instance, if our test statistic falls above the 95th percentile of the chi-square distribution, we might reject the null hypothesis at a 5% level of significance, assuming our observed result is sufficiently rare under the assumption that the null hypothesis is true.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Today's newspapers and magazines often report the findings of survey polls about various aspects of life. The Pew Internet \& American Life Project (January 13-February 9,2005 ) found that "63\% of cell phone users ages \(18-27\) have used text messaging within the past month." Other information obtained from the project included "random telephone survey of 1,460 cell phone users" and "has a margin of sampling error of plus or minus 3 percentage points." Relate this information to the statistical inferences you have been studying in this chapter. a. Is a percentage of people a population parameter, and if so, how is it related to any of the parameters that we have studied? b. Based on the information given, find the \(95 \%\) confidence interval for the true proportion of cell phone users who have used text messaging. c. Explain how the terms "point estimate," "level of confidence," "maximum error of estimate," and "confidence interval" relate to the values reported in the article and to your answers in part b.

A bank randomly selected 250 checking account customers and found that 110 of them also had savings accounts at the same bank. Construct a \(95 \%\) confidence interval for the true proportion of checking account customers who also have savings accounts.

According to the August 2009 Reader's Digest article "Where Our Garbage Goes," the average American tosses 4.6 pounds of garbage every day. A small town in Vermont initiated a Going Green campaign and asked residents to work on recycling more and reducing their generation of garbage each day. To estimate the average amount of trash discarded by people in their town, 18 households were randomly selected and all were asked to carefully weigh their trash on the same day. The average amount for the sample was 3.89 pounds, with a standard deviation of 1.322 pounds. Is there sufficient evidence that the Vermont town now has significantly lower average daily garbage amounts than the average American household? Use a 0.05 level of significance and assume weights are normally distributed.

A politician claims that she will receive \(60 \%\) of the vote in an upcoming election. The results of a properly designed random sample of 100 voters showed that 50 of those sampled will vote for her. Is it likely that her assertion is correct at the 0.05 level of significance? a. Solve using the \(p\) -value approach. b. Solve using the classical approach.

A manufacturer of television sets claims that the maintenance expenditures for its product will average no more than \(110\)dollar during the first year following the expiration of the warranty. A consumer group has asked you to substantiate or discredit the claim. The results of a random sample of 50 owners of such television sets showed that the mean expenditure was \(131.60\)dollar and the standard deviation was \(42.46\)dollar At the 0.01 level of significance, should you conclude that the manufacturer's claim is true or not likely to be true?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.