/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 108 The popularity of personal water... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The popularity of personal watercraft (PWCs, also known as jet skis) continues to increase, despite the apparent danger associated with their use. In fact, a sample of 54 watercraft accidents reported to the Game and Parks Commission in the state of Nebraska revealed that \(85 \%\) of them involved PWCs even though only \(8 \%\) of the motorized boats registered in the state are PWCs. Suppose the national average proportion of watercraft accidents involving PWCs was \(78 \% .\) Does the watercraft accident rate for PWCs in the state of Nebraska exceed that of the nation as a whole? Use a 0.01 level of significance. a. Solve using the \(p\) -value approach. b. Solve using the classical approach.

Short Answer

Expert verified
Without performing calculations, a complete answer cannot be given. However, the answer will involve rejecting or not rejecting the null hypothesis based on the comparison of the p-value (or test statistic in the classical approach) to the significance level.

Step by step solution

01

Set up hypotheses

The null hypothesis, H0, states that the proportion of watercraft accidents involving PWCs in Nebraska is equal to the national average proportion, 0.78. The alternative hypothesis, Ha, states that the proportion of watercraft accidents involving PWCs in Nebraska is greater than the national average; hence, H0: p = 0.78, Ha: p > 0.78.
02

Calculate Test Statistic

The z-test statistic for proportions is calculated as \(z = (p - pâ‚€) / \sqrt{(pâ‚€(1 - pâ‚€)/n)}\), where \(p\) is the sample proportion, \(pâ‚€\) is the population proportion under the null hypothesis, and \(n\) is the sample size. Substituting the given values, we get \(z = (0.85 - 0.78) / \sqrt{(0.78(1 - 0.78)/54)}\).
03

Calculate p-value

The p-value is the probability that, given the null hypothesis is true, we would observe a test statistic as extreme as the one calculated. This is calculated using the standard normal distribution (because the test statistic is a z-score). In this case, because the alternative hypothesis is that the proportion is greater than the national average, the p-value is the area to the right of the calculated z-score.
04

Compare p-value to Significance Level

If the p-value is less than 0.01 (the level of significance), we reject the null hypothesis. If it is greater, we do not reject the null hypothesis.
05

Conclude

Based on the p-value and the level of significance, make a decision about whether or not the watercraft accident rate for PWCs in Nebraska exceeds that of the nation.
06

Perform Classical Approach

For the classical approach, compare the calculated test statistic to a critical value determined from the standard normal distribution given the level of significance. If the test statistic is in the 'rejection region' beyond the critical value, reject the null hypothesis. The critical value for a one-tailed test at a 0.01 significance level from the standard normal distribution is around 2.33.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
The null hypothesis is a foundational element in hypothesis testing, representing a statement of no effect or no difference. In the context of the watercraft accident example, it posits that the proportion of watercraft accidents involving PWCs in Nebraska is the same as the national average. Essentially, it serves as the neutral ground we aim to challenge.

To mathematically represent this, you write it as:
  • Null Hypothesis ( \( H_0 \)) : \( p = 0.78 \)
Where \( p \) is the proportion of accidents involving PWCs in Nebraska. The null hypothesis suggests that any departure from the national average in your sample is due to random variation. Verifying whether this is true or false is the core of hypothesis testing. If evidence is strong enough, we may reject the null hypothesis, leading us to believe something unusual is happening.
Alternative Hypothesis
The alternative hypothesis is what you might say to challenge the null hypothesis. This statement is what you hope or suspect might be true instead. In our PWC accident case, the alternative hypothesis suggests that the proportion of accidents with PWCs in Nebraska is higher than the national average. Formally, the expression is:
  • Alternative Hypothesis ( \( H_a \)): \( p > 0.78 \)
Here, \( p \) again represents the proportion of accidents in Nebraska involving PWCs. The goal of hypothesis testing is to evaluate if the sample data provides enough evidence to support this alternative hypothesis over the null hypothesis. If the data suggests that the null hypothesis is false, the alternative hypothesis could indeed be true.
P-value
The p-value is a measure that helps us make informed decisions in hypothesis testing. It is the probability that the observed data, or something even more extreme, would occur if the null hypothesis were true. In hypothesis testing, the p-value helps us gauge the strength of our results.

In our example, if you compute a small p-value (less than 0.01 in this particular case), it suggests that such an extreme difference in accident proportions with PWCs is unlikely under the assumption of the null hypothesis. Therefore, you would reject the null hypothesis and lend support to the alternative hypothesis. A large p-value implies that the sample does not provide enough evidence against the null hypothesis, meaning no rejection takes place.
Z-test
The Z-test is a statistical method used to determine if there is a significant difference between sample and population proportions. It calculates how many standard deviations our sample proportion is from the population proportion.

For the watercraft accident scenario, the Z-test formula is:\[z = \frac{(p - p_0)}{\sqrt{\frac{p_0(1 - p_0)}{n}}}\]Where:
  • \( p \) is the sample proportion (0.85 here)
  • \( p_0 \) is the population proportion under the null hypothesis (0.78)
  • \( n \) is the sample size (54 in this case)
The calculated Z-value can then be compared to a static threshold known as the critical value to determine statistical significance.
Significance Level
The significance level (alpha, \(\alpha\)) is a threshold used to decide whether a p-value is small enough to reject the null hypothesis. It represents the risk of concluding that a difference exists when there actually is none. Common significance levels are 0.05, 0.01, or 0.10, reflecting a 5%, 1%, or 10% risk of false positives, respectively.

In the jet ski example, the significance level is set at 0.01. If the p-value calculated from the Z-test falls below 0.01, it means the results are significant enough to dismiss the null hypothesis. Conversely, a p-value higher than 0.01 suggests insufficient evidence to reject the null hypothesis, implying that the observed difference in PWC accident proportions might simply be due to chance.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Of the 150 elements in a random sample, 45 are classified as "success." a. Explain why \(x\) and \(n\) are assigned the values 45 and \(150,\) respectively. b. Determine the value of \(p^{\prime} .\) Explain how \(p^{\prime}\) is found and the meaning of \(p^{\prime}\). For each of the following situations, find \(p^{\prime}\). c. \(x=24\) and \(n=250\) d. \(x=640\) and \(n=2050\) e. \(892\) of 1280 responded "Yes"

In a poll conducted by Harris Interactive of 1179 video-gaming U.S. youngsters, \(8.5 \%\) displayed behavioral signs that may indicate addiction. Using a \(99 \%\) confidence interval for the true binomial proportion based on this random sample of 1179 binomial trials and an observed proportion of \(0.085,\) estimate the proportion of video-gaming youngsters that may go on to have an addiction.

Three nationwide poll results are described below. USA Today Snapshot/Rent.com, August 18,2009 \(N=1000\) adults 18 and over; \(\mathrm{MoE} \pm 3 .\) (MoE is margin of error. "What renters look for the most when seeking an apartment:" Washer/dryer\(-39\%,\) Air Conditioning \(-30 \%,\) Fitness Center- \(10 \%,\) Pool \(-10 \%\) USA Today/Harris Interactive Poll, February \(10-15,2009 ; N=1010\) adults; MoE ±3. "Americans who say people on Wall Street are "as honest and moral as other people." Disagree \(-70 \%\) Agree \(-26 \%,\) Not sure/refuse to answer \(-4 \%\) American Association of Retired Persons Bulletin/AARP survey, July 22-August 2, 2009; \(N=1006\) adults age 50 and older; \(\mathrm{MoE} \pm 3\). The American Association of Retired Persons Bulletin Survey reported that \(16 \%\) of adults, 50 and older, said they are likely to return to school. Each of the polls is based on approximately 1005 randomly selected adults. a. Calculate the \(95 \%\) confidence maximum error of estimate for the true binomial proportion based on binomial experiments with the same sample size and observed proportion as listed first in each article. b. Explain what caused the values of the maximum errors to vary. c. The margin of error being reported is typically the value of the maximum error rounded to the next larger whole percentage. Do your results in part a verify this? d. Explain why the round-up practice is considered "conservative." e. What value of \(p\) should be used to calculate the standard error if the most conservative margin of error is desired?

In obtaining the sample size to estimate a proportion, the formula \(n=[z(\alpha / 2)]^{2} p q / E^{2}\) is used. If a reasonable estimate of \(p\) is not available, it is suggested that \(p=0.5\) be used because this will give the maximum value for \(n\). Calculate the value of \(p q=p(1-p)\) for \(p=0.1,0.2,0.3, \ldots, 0.8,0.9\) in order to obtain some idea about the behavior of the quantity \(p q\).

State the null hypothesis, \(H_{o}\), and the alternative hypothesis, \(H_{a},\) that would be used to test these claims: a. The variance has decreased from 34.5. b. The standard deviation of shoe size is more than 0.32. c. The standard deviation is at least 5.5. d. The variance is at most 35. e. The variance has shrunk from the value of 0.34 since the assembly lines were retooled.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.