/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 80 Find the power of a test when th... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the power of a test when the probability of the type II error is: a. 0.01 b. 0.05 c. 0.10

Short Answer

Expert verified
The power of a test when probability of Type II error is 0.01 is 0.99, when it is 0.05, the power is 0.95, and when it is 0.10, the power is 0.90.

Step by step solution

01

Identify the Probability of Type II Error

This step involves identifying the provided probability of Type II error. For part a, Type II error probability, denoted as \(\beta\), is 0.01. For part b, it's 0.05. And for part c, it's 0.10.
02

Find the Power of the Test

The power of a test is given by \(1 - \beta\), that is, one minus the Type II error probability. So for each part, subtract the given probability of Type II error from 1.
03

Step 3a: Calculate the Power for probability 0.01

For part a, the power of a test, denoted as \(1 - \beta\), becomes, \(1 - 0.01 = 0.99\)
04

Step 3b: Calculate the Power for probability 0.05

For part b, the power of a test, \(1 - \beta\), becomes, \(1 - 0.05 = 0.95\)
05

Step 3c: Calculate the Power for probability 0.10

For part c, the power of a test, \(1 - \beta\), becomes, \(1 - 0.10 = 0.90\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Type II Error
In the field of statistics, a Type II error, represented by the symbol \(\beta\), occurs when a statistical test fails to reject a false null hypothesis. In simpler terms, it means that the test incorrectly concludes there is not enough evidence to support a certain belief (alternative hypothesis) when, in fact, it is true. The concept of Type II errors is crucial in hypothesis testing because it relates to the test's ability to identify a genuine effect or difference when one truly exists.

The probability of committing a Type II error is affected by several factors, including the sample size, the significance level (Type I error probability), and the true effect size. Researchers aim to minimize the risk of Type II errors because overlooking a meaningful finding can have significant implications in scientific research, quality control, and many other domains.
Probability
Probability is a fundamental concept in statistics that measures the likelihood of an event occurring. It is quantified as a number between 0 and 1, inclusive, where 0 indicates impossibility and 1 indicates certainty. The probabilities of all possible outcomes of a random event add up to 1.

In the context of statistical hypothesis testing, probability plays a key role in determining both Type I and Type II errors. For instance, the probability of a Type II error is denoted by \(\beta\), and the probability of rejecting a false null hypothesis is calculated as \(1 - \beta\), known as the power of the test. Understanding how to calculate and interpret probability is essential for conducting accurate and reliable statistical tests.
Statistical Hypothesis Testing
Statistical hypothesis testing is a method used to make decisions about population parameters based on sample data. Hypothesis tests are formulated around a null hypothesis (\(H_0\)), which generally represents a statement of no effect or no difference, and an alternative hypothesis (\(H_1\)) that suggests there is an effect or a difference. The outcome of a hypothesis test is a decision to either reject the null hypothesis in favor of the alternative or to fail to reject the null, implying the data is not sufficiently persuasive to support the alternative.

The power of a test is the probability that the test correctly rejects a false null hypothesis, that is, it successfully detects an effect when one is present. A high-powered test reduces the chances of committing a Type II error. The significance level (denoted as alpha, \(\alpha\)), sample size, effect size, and variability all influence the power of a statistical test, guiding researchers to design robust experiments and make informed decisions based on their results.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A manufacturer of automobile tires believes it has developed a new rubber compound that has superior antiwearing qualities. It produced a test run of tires made with this new compound and had them road tested. The data values recorded were the amount of tread wear per 10,000 miles. In the past, the mean amount of tread wear per 10,000 miles, for tires of this quality, has been 0.0625 inch. The null hypothesis to be tested here is "The mean amount of wear on the tires made with the new com- pound is the same mean amount of wear with the old compound, 0.0625 inch per 10,000 miles," \(H_{o}: \mu=0.0625\) Three possible alternative hypotheses could be used: \(H_{a}: \mu<0.0625,(2) H_{a}: \mu \neq 0.0625,(3) H_{a}: \mu > 0.0625\) a. Explain the meaning of each of these three alternatives. b. Which one of the possible alternative hypotheses should the manufacturer use if it hopes to conclude that "use of the new compound does yield superior wear"?

Describe in your own words what the \(p\) -value measures.

a. A one-tailed hypothesis test is to be completed at the 0.05 level of significance. What calculated values of \(p\) will cause a rejection of \(H_{o} ?\) b. A two-tailed hypothesis test is to be completed at the 0.02 level of significance. What calculated values of \(p\) will cause a "fail to reject \(H_{o}\) " decision?

Determine the critical region and critical values for \(z\) that would be used to test the null hypothesis at the given level of significance, as described in each of the following: a. \(\quad H_{o}: \mu=20, H_{a}: \mu \neq 20, \alpha=0.10\) b. \(\quad H_{o}: \mu=24(\leq), H_{a}: \mu>24, \alpha=0.01\) c. \(\quad H_{o}: \mu=10.5(\geq), H_{a}: \mu<10.5, \alpha=0.05\) d. \(\quad H_{o}: \mu=35, H_{a}: \mu \neq 35, \alpha=0.01\)

State the null hypothesis \(H_{o}\) and the alternative hypothesis \(H_{a}\) that would be used for a hypothesis test related to each of the following statements: a. The mean age of the students enrolled in evening classes at a certain college is greater than 26 years. b. The mean weight of packages shipped on Air Express during the past month was less than 36.7 lb. c. The mean life of fluorescent light bulbs is at least 1600 hours. d. The mean strength of welds by a new process is different from 570 lb per unit area, the mean strength of welds by the old process.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.