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a. A one-tailed hypothesis test is to be completed at the 0.05 level of significance. What calculated values of \(p\) will cause a rejection of \(H_{o} ?\) b. A two-tailed hypothesis test is to be completed at the 0.02 level of significance. What calculated values of \(p\) will cause a "fail to reject \(H_{o}\) " decision?

Short Answer

Expert verified
a. For the one-tailed hypothesis test at 0.05 level of significance, if the calculated p-value is less than 0.05, then null hypothesis (\(H_{o}\)) is rejected. b. For the two-tailed hypothesis test at 0.02 level of significance, if the calculated p-value is more than 0.01, then we fail to reject the null hypothesis.

Step by step solution

01

Understand p-value in a Hypothesis Test

In hypothesis testing, the p-value, or calculated probability, is the probability of finding the observed, or more extreme, results when the null hypothesis (\(H_{o}\)) of a study question is true.
02

Determine the Decision Criterion for One-Tailed Test

In a one-tailed hypothesis test at a given level of significance, the rejection region is entirely within one tail of the distribution. When the calculated p-value is less than the level of significance (0.05 in this case), we reject the null hypothesis.
03

Decision Criterion for Two-Tailed Test

In a two-tailed hypothesis test, the rejection regions are in both tails of the distribution. When the calculated p-value is less than half the level of significance (0.01 in this case) in either tail, we reject the null hypothesis. However, if the calculated p-value is more than 0.01, we 'fail to reject' the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

P-value
The p-value is a core concept in hypothesis testing. It represents the probability of obtaining test results at least as extreme as the ones observed during the study, assuming that the null hypothesis (\( H_{0} \)) is correct. A small p-value, typically less than a pre-determined threshold known as the level of significance, indicates that the observed data is unusual under the assumption of the null hypothesis. This can lead to the rejection of the null hypothesis in favor of the alternative hypothesis.

For instance, if a p-value is calculated to be 0.03, this means there's a 3% chance of seeing the observed result (or one more extreme) if the null hypothesis were true. If our level of significance is set at 0.05, then a p-value of 0.03 would lead us to reject the null hypothesis because 0.03 is less than 0.05, indicating the result is statistically significant.
One-tailed Test
In a one-tailed hypothesis test, we're interested in determining whether there is an increase or a decrease but not both — hence the name 'one-tailed'. The direction we're testing is determined before data collection, based on the research question.

Example Context:

A typical scenario might be testing whether a new drug is more effective than the current treatment. We're interested only if the new drug demonstrates an increase in effectiveness, and thus a one-tailed test would be appropriate. If the calculated p-value is less than the level of significance, for example 0.05, the null hypothesis is rejected in the direction of the alternative hypothesis, suggesting the new drug is indeed more effective.
Two-tailed Test
Opposite to the one-tailed test, a two-tailed test does not restrict the direction of an effect. The purpose here is to determine if there is any significant difference, meaning that an effect could be either positive or negative. The level of significance is usually divided by two, allocating half to each tail of the probability distribution.

Understanding Through Example:

Consider an example where researchers are testing if a new drug has a different effect — either higher or lower — than the current standard. They're not only interested if it is more effective but also if it is less effective. In a case where the level of significance is set at 0.02, a p-value less than 0.01 (0.02/2) in either tail would lead to rejection of the null hypothesis, while a p-value greater than 0.01 would lead to 'fail to reject' decision.
Level of Significance
The level of significance is a critical decision point in hypothesis testing. It's a threshold set by the researcher that determines the point at which an observed effect is considered statistically significant. Traditionally, levels of significance are set at 0.05, 0.01, or 0.001, reflecting a 5%, 1%, or 0.1% risk of concluding that a difference exists when there is no actual difference.

Choosing an appropriate level of significance is a balance between being too lenient and too strict. A too high level could result in accepting a false effect (Type I error), and a too low level could neglect a real effect (Type II error). The chosen level should withstand the scrutiny of the scientific community and account for the potential implications of errors.
Null Hypothesis
The null hypothesis (\(H_{0} \)) represents a statement of no effect or no difference and serves as the starting point for statistical testing. It is the hypothesis that researchers aim to test against the alternative hypothesis (\(H_{a} \)) that states there is an effect or a difference.

Examining the null hypothesis is like putting a claim on trial. The data collected is the evidence, and the statistical tests help decide whether this evidence is strong enough to reject the null hypothesis. Failing to reject the null doesn't prove it true; rather, it indicates that there isn't sufficient evidence to support an alternative claim. It’s crucial for researchers to clearly define the null hypothesis and the conditions under which it can be rejected or fail to be rejected.

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Most popular questions from this chapter

Describe the actions that would result in a type I error and a type II error if each of the following null hypotheses were tested. (Remember, the alternative hypothesis is the negation of the null hypothesis.) a. \(\quad H_{o}:\) The majority of Americans favor laws against assault weapons. b. \(\quad H_{o}:\) The choices on the fast food menu are not low in salt. c. \(\quad H_{o}:\) This building must not be demolished. d. \(\quad H_{o}:\) There is no waste in government spending.

Use a computer or calculator to select 40 random single-digit numbers. Find the sample mean, \(z \star,\) and \(p\) -value for testing \(H_{o}: \mu=4.5\) against a two-tailed alternative. Repeat several times as in Table \(8.8 .\) Describe your findings.

Jack Williams is vice president of marketing for one of the largest natural gas companies in the nation. During the past 4 years, he has watched two major factors erode the profits and sales of the company. First, the average price of crude oil has been virtually flat, and many of his industrial customers are burning heavy oil rather than natural gas to fire their furnaces, regardless of added smokestack emissions. Second, both residential and commercial customers are still pursuing energy-conservation techniques (e.g., adding extra insulation, installing clockdrive thermostats, and sealing cracks around doors and windows to eliminate cold air infiltration). In previous years, residential customers bought an average of 129.2 mcf of natural gas from Jack's company \((\sigma=18 \mathrm{mcf})\) based on internal company billing records, but environmentalists have claimed that conservation is cutting fuel consumption up to \(3 \%\) per year. Jack has commissioned you to conduct a spot check to see if any change in annual usage has transpired before his next meeting with the officers of the corporation. A sample of 300 customers selected randomly from the billing records reveals an average of \(127.1 \mathrm{mcf}\) during the past 12 months. Is there a significant decline in consumption? a. Complete the appropriate hypothesis test at the 0.01 level of significance using the \(p\) -value approach so that you can properly advise Jack before his meeting. b. Because you are Jack's assistant, why is it best for you to use the \(p\) -value approach?

The owner of a local chain of grocery stores is always trying to minimize the time it takes her customers to check out. In the past, she has conducted many studies of the checkout times, and they have displayed a normal distribution with a mean time of 12 minutes and a standard deviation of 2.3 minutes. She has implemented a new schedule for cashiers in hopes of reducing the mean checkout time. A random sample of 28 customers visiting her store this week resulted in a mean of 10.9 minutes. Does she have sufficient evidence to claim the mean checkout time this week was less than 12 minutes? Use \(\alpha=0.02\)

A large order of the no. 9 corks described in Applied Example \(6.13(p .285)\) is about to be shipped. The final quality-control inspection includes an estimation of the mean ovality (ovalization; out-of roundness) of the corks. The diameter of each cork is measured in several places, and the difference between the maximum and minimum diameters is the measure of ovality for each cork. After years of measuring corks, the manufacturer is sure that ovality has a mounded distribution with a standard deviation of \(0.10 \mathrm{mm} .\) A random sample of 36 corks is taken from the batch and the ovality is determined for each. $$\begin{array}{lllllllll} \hline 0.32 & 0.27 & 0.24 & 0.31 & 0.20 & 0.38 & 0.32 & 0.11 & 0.25 \\ 0.22 & 0.35 & 0.20 & 0.28 & 0.17 & 0.36 & 0.28 & 0.38 & 0.17 \\ 0.34 & 0.06 & 0.43 & 0.13 & 0.39 & 0.15 & 0.18 & 0.13 & 0.25 \\ 0.20 & 0.16 & 0.26 & 0.47 & 0.21 & 0.19 & 0.34 & 0.24 & 0.20 \\ \hline \end{array}$$ a. The out-of-round spec is "less than \(1.0 \mathrm{mm}\) " Does it appear this order meets the spec on an individual cork basis? Explain. b. The certification sheet that accompanies the shipment includes a \(95 \%\) confidence interval for the mean ovality. Construct the confidence interval. c. Explain what the confidence interval found in part b tells about this shipment of corks.

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