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91Ó°ÊÓ

An automobile manufacturer wants to estimate the mean gasoline mileage of its new compact model. How many sample runs must be performed to ensure that the estimate is accurate to within 0.3 mpg at \(95 \%\) confidence? (Assume \(\sigma=1.5 .\) )

Short Answer

Expert verified
The manufacturers must conduct 98 sample runs to ensure that the estimate is accurate to within 0.3 mpg at 95% confidence.

Step by step solution

01

Identify important information

In this question, there are key pieces of information provided and to be noted are:\n1. The standard deviation \(\sigma=1.5\) mpg.\n2. The acceptable margin of error is 0.3 mpg.\n3. The confidence level is 95%.
02

Understanding Concept Behind Confidence Interval

For a 95% confidence level, the Z-score (which can be found from normal probability distribution tables) is approximately 1.96. The Z-score corresponds to the number of standard deviations the confidence interval extends from the mean.
03

Determine the sample size

The formula for finding the sample size (n) when the standard deviation (\(\sigma\)) is known is as follows: \(n = \left(\frac{z \cdot \sigma}{E}\right)^2\) where: \n- n = required sample size\n- z = z-value (the number of standard deviations from the mean) at the desired confidence level\n- \(\sigma\) = population standard deviation\n- E = desired margin of error (accuracy)\nSubstitute the given values into the formula: \(n = \left(\frac{1.96 \cdot 1.5}{0.3}\right)^2\).
04

Calculate the sample size

Calculating the above expression, we get: \(n \approx 97\). As one can't have a fraction of a test, this value must be rounded up, ensuring that the sample has a large enough size to achieve the desired precision. Therefore, the number of sample runs required should be 98.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
When we estimate a population parameter such as the mean gasoline mileage of a car model, a confidence interval gives us a range within which we expect the true parameter to lie. For example, if we have a 95% confidence interval, it means there is a 95% chance that the true mean lies within this range. This helps us in making decisions based on the sample data
and gives us a quantified idea of the uncertainty in our estimation. To calculate a confidence interval, we use the formula: \[ \text{Confidence Interval} = \bar{x} \pm (Z \times \frac{\sigma}{\sqrt{n}}) \] where:
  • \(\bar{x}\) is the sample mean
  • \(Z\) is the Z-score corresponding to the desired confidence level
  • \(\sigma\) is the standard deviation
  • \(n\) is the sample size
This formula shows that the interval is built by adding and subtracting the margin of error from the sample mean, giving us an upper and lower bound of where the true mean is likely to be.
Margin of Error
The margin of error indicates the range of uncertainty about a sample statistic, such as the sample mean. In this exercise, the margin of error is set at 0.3 mpg, meaning our estimation of the mean gasoline mileage could vary by this amount. A smaller margin of error results in a more precise estimate. However, reducing the margin of error requires increasing the sample size.To determine the margin of error, we use: \[ E = Z \times \frac{\sigma}{\sqrt{n}} \] Key factors affecting the margin of error include:
  • The Z-score, which aligns with the confidence level
  • The sample size (\(n\))
  • The standard deviation (\(\sigma\)), representing data dispersion
By understanding how these variables impact the margin of error, we can quantitatively control the precision of our statistical estimates.
Z-Score
A Z-score is a statistical measurement that describes a value's relation to the mean of a group of values. In the context of confidence intervals, the Z-score is a multiplier that reflects how many standard deviations a certain value lies from the mean at a specific confidence level. For this exercise, a 95% confidence level corresponds to a Z-score of roughly 1.96. This number can be found using a normal distribution table, indicating that 95% of data under a normal curve falls within 1.96 standard deviations from the mean.
Key considerations with Z-scores include:
  • A higher confidence level will result in a higher Z-score, which in turn will increase the range of the confidence interval.
  • Each confidence level has a corresponding Z-score that is used in statistical calculations.
Understanding Z-scores helps us interpret how likely it is for a sample mean to reflect the actual population mean within our chosen margin of error.
Standard Deviation
Standard deviation is a measure of how spread out numbers are in a data set. In sample size determination, standard deviation affects both the margin of error and the overall precision of our estimates. In this problem, the standard deviation is given as 1.5 mpg, indicating the average deviation of each sample run's mileage from the mean. The greater the standard deviation, the more spread out the data points are, resulting in a wider confidence interval. A few core points include:
  • Standard deviation helps in understanding variability in the data. Larger standard deviations indicate more variability.
  • When calculating sample size, a larger standard deviation requires a larger sample to maintain the same margin of error.
By acknowledging the role of standard deviation, we can better prepare and understand the variability in our estimated confidence intervals.

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Most popular questions from this chapter

Suppose we want to test the hypothesis that the mean hourly charge for automobile repairs is at least \(\$ 60\) per hour at the repair shops in a nearby city. Explain the conditions that would exist if we make an error in decision by committing a type I error. What about a type II error?

State the null hypothesis \(H_{o}\) and the alternative hypothesis \(H_{a}\) that would be used for a hypothesis test related to each of the following statements: a. The mean age of the students enrolled in evening classes at a certain college is greater than 26 years. b. The mean weight of packages shipped on Air Express during the past month was less than 36.7 lb. c. The mean life of fluorescent light bulbs is at least 1600 hours. d. The mean strength of welds by a new process is different from 570 lb per unit area, the mean strength of welds by the old process.

The null hypothesis, \(H_{o}: \mu=48,\) was tested against the alternative hypothesis, \(H_{a}: \mu > 48 .\) A sample of 75 resulted in a calculated \(p\) -value of \(0.102 .\) If \(\sigma=3.5,\) find the value of the sample mean, \(\bar{x}\)

When a parachute is inspected, the inspector is looking for anything that might indicate the parachute might not open. a. State the null and alternative hypotheses. b. Describe the four possible outcomes that can result depending on the truth of the null hypothesis and the decision reached. c. Describe the seriousness of the two possible errors.

The null hypothesis, \(H_{o}: \mu=250,\) was tested against the alternative hypothesis, \(H_{a}: \mu<250 .\) A sample of \(n=85\) resulted in a calculated test statistic of \(z \star=-1.18 .\) If \(\sigma=22.6,\) find the value of the sample mean, \(\bar{x}\). Find the sum of the sample data, \(\Sigma x\)

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