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91Ó°ÊÓ

Suppose we want to test the hypothesis that the mean hourly charge for automobile repairs is at least \(\$ 60\) per hour at the repair shops in a nearby city. Explain the conditions that would exist if we make an error in decision by committing a type I error. What about a type II error?

Short Answer

Expert verified
A Type I error in this exercise would occur when we reject the null hypothesis and insist that the mean hourly charge for automobile repairs is less than $60 when, in reality, it's $60 or more. A Type II error would occur if we insist that the mean hourly charge is $60 or more when it is actually less.

Step by step solution

01

Interpret Type I Error

Type I error happens when we wrongly reject a true null hypothesis. In this scenario, the null hypothesis is that the mean hourly charge for automobile repairs is at least $60. So, a Type I error would occur if we concluded that the mean hourly charge was less than $60 when, in reality, it was $60 or more.
02

Interpret Type II Error

A Type II error occurs when we fail to reject a false null hypothesis. In this case, the null hypothesis is the mean hourly charge is at least $60. Therefore, a Type II error would be made if we concluded that the mean hourly charge was $60 or more when it was actually less.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Type I Error
A Type I error occurs when we mistakenly reject a true null hypothesis. This is akin to a false alarm in hypothesis testing. Imagine you are a detective with a solid lead (our null hypothesis) that suggests a suspect is not guilty. A Type I error would be like declaring that the suspect is indeed guilty and therefore arresting him, when in fact, he is innocent.

In the context of our automobile repair scenario, the null hypothesis states that the mean hourly charge is at least $60. A Type I error here would mean we concluded the charge is less than $60 per hour when it isn’t. This kind of error might cause unnecessary changes in business strategies or pricing, thinking that the market pricing is lower than it truly is.

To minimize Type I errors, it's crucial to choose a proper significance level or alpha (usually 0.05 or 5%). The lower the alpha, the lower the probability of committing a Type I error. However, lowering alpha too much can increase the risk of making Type II errors, highlighting a balance that must be achieved in hypothesis testing.
Type II Error
Unlike Type I errors, a Type II error involves failing to reject a false null hypothesis. This is similar to missing a presence where there is actually something to be detected. In simpler terms, think of it as overlooking a guilty suspect and proclaiming them innocent.

In our case with the auto repair shops, a Type II error would occur if we determine that the average hourly charge is at least $60 when it is actually less. Such an error might lead to overconfidence in existing pricing strategies and missed opportunities for competitive pricing adjustments.

Type II errors are related to the power of a test, which is the probability of correctly rejecting a false null hypothesis. Increasing the sample size can improve test power, thereby reducing the chance of a Type II error. Balancing power and risk with resource constraints is a critical aspect of experimental design.
Null Hypothesis
The null hypothesis ( H_0 ) is a fundamental concept in hypothesis testing. It's the statement being tested, often representing the status quo or no effect. We assume the null is true until evidence suggests otherwise.

In the given scenario, the null hypothesis claims that the mean hourly charge for automobile repairs is at least $60. It's the line we're starting from and what we're seeking evidence to possibly change. If sufficient evidence exists suggesting this mean hourly rate is indeed below $60, the null would be rejected.

Testing the null involves using statistical tests to determine the probability of observing data as extreme as ours, assuming the null is true. This probability, quantified by the p-value, helps decide if the null hypothesis should be rejected. The smaller the p-value, the stronger the evidence against H_0 , and thus the more justified we are in concluding an effect, like a mean charge less than $60 in this case.
  • Null hypothesis (H_0) indicates what is assumed true.
  • It's the backbone of hypothesis testing.
  • Determines if there's enough reason to support a shift in the current understanding.

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Most popular questions from this chapter

The director of an advertising agency is concerned with the effectiveness of a television commercial. a. What null hypothesis is she testing if she commits a type I error when she erroneously says that the commercial is effective? b. What null hypothesis is she testing if she commits a type II error when she erroneously says that the commercial is effective?

After conducting a large number of tests over a long period, a rope manufacturer has found that its rope has a mean breaking strength of 300 Ib and a standard deviation of 24 lb. Assume that these values are \(\mu\) and \(\sigma .\) It is believed that by using a recently developed highspeed process, the mean breaking strength has been decreased. a. Design null and alternative hypotheses such that rejection of the null hypothesis will imply that the mean breaking strength has decreased. b. Using the decision rule established in part a, what is the \(p\) -value associated with rejecting the null hypothesis when 45 tests result in a sample mean of \(295 ?\) c. If the decision rule in part a is used with \(\alpha=0.01\) what is the critical value for the test statistic and what value of \(\bar{x}\) corresponds to it if a sample of size 45 is used?

Use a computer and generate 50 random samples, each of size \(n=28,\) from a normal probability distribution with \(\mu=19\) and \(\sigma=4\) a. Calculate the \(z\) * corresponding to each sample mean that would result when testing the null hypothesis \(\mu=18\) b. In regard to the \(p\) -value approach, find the proportion of \(50 z \star\) values that are "more extreme" than the \(z=-1.04\) that occurred in Exercise \(8.201\left(H_{a}: \mu \neq 18\right)\) Explain what this proportion represents. c. In regard to the classical approach, find the critical values for a two- tailed test using \(\alpha=0.01 ;\) find the proportion of \(50 z \star\) values that fall in the noncritical region. Explain what this proportion represents.

a. If \(\beta\) is assigned the value \(0.001,\) what are we saying about the type II error? b. If \(\beta\) is assigned the value \(0.05,\) what are we saying about the type II error? c. If \(\beta\) is assigned the value \(0.10,\) what are we saying about the type II error?

Assume that \(z\) is the test statistic and calculate the value of \(z \star\) for each of the following: a. \(\quad H_{o}: \mu=51, \sigma=4.5, n=40, \bar{x}=49.6\) b. \(\quad H_{o}: \mu=20, \sigma=4.3, n=75, \bar{x}=21.2\) c. \(\quad H_{o}: \mu=138.5, \sigma=3.7, n=14, \bar{x}=142.93\) d. \(\quad H_{o}: \mu=815, \sigma=43.3, n=60, \bar{x}=799.6\)

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